How is the earthwork of 15.228 m3 obtained?

Centre-line length 16.92 m x trench width 0.90 m x depth 1.00 m

Clear room perimeter x 0.23 m x 1.00 m

Room area 4.5 x 3.5 x depth 1.00 m

Centre-line 16.92 m x 0.23 m x 0.90 m

What is the timber volume of the door frame (1.0 x 2.1 m, 100 x 75 mm section)?

0.039 m3, from length 2 x 2.1 + 1.0 = 5.2 m

0.0465 m3, from length 2 x 2.1 + 2 x 1.0 = 6.2 m

0.039 m3, from a length of 2.1 m only

What is the purpose of the 1.30 and 0.80 multipliers in the painting calculation?

They convert the plain measured area of frame and shutter into the actual paint surface for that type of shutter

They allow for wastage of paint

They convert square metres into litres of paint

They account for the number of coats

How is the painted area of 10.07 m2 used for primer and two coats of enamel?

The same area is taken for the primer (one coat) and the enamel (two coats), rated per coat as specified

The area is doubled for the two enamel coats and tripled for the primer

Primer area is half of the enamel area

Only the enamel area is measured; primer is ignored

2076 Chaitra · 3+3+4 marks

Building: excavation, wood frames, enamel paint

Short answer

For assumed room 4.5×3.5 m: earthwork excavation 15.23 m³, woodwork for door and window frames 0.111 m³, and two-coat enamel painting over primer 10.07 m².

Estimate the quantities of the following items of work from the accompanying drawing (Figure 1): (i) Earthwork excavation in foundation (ii) Wood work for doors and windows frame (iii) Two coats enamel painting over one coat primer in doors and windows. [Figure 1 not included in the scanned paper]

No drawing is given, so a one-room building is assumed: room 4.5 m × 3.5 m clear, 230 mm walls, centre-line length 16.92 m; trench 0.90 m × 1.00 m; one door 1.0 × 2.1 m (panelled); two glazed windows 1.2 × 1.2 m; frames 100 × 75 mm.

i) Earthwork in excavation in foundation

Item	No.	L (m)	B (m)	H/D (m)	Qty (m³)
Trench, all walls (centre-line)	1	16.920	0.900	1.000	15.228
Total					15.228

ii) Wood work for door and window frames

Item	No.	L (m)	B (m)	H/D (m)	Qty (m³)
Door frame 2×2.1 + 1.0	1	5.200	0.100	0.075	0.0390
Window frames 2 × (2×1.2 + 2×1.2)	2	4.800	0.100	0.075	0.0720
Total					0.1110

iii) Two coats of enamel paint over one coat of primer

Painted area is measured over the frame and shutter on both sides and multiplied by a coefficient for the type of shutter. The multipliers below are typical textbook values (IS 1200 style; they differ slightly between books): panelled door 1.30 per side measured, glazed window 0.80.

Door: 1.0 × 2.1 × 2 sides × 1.30 = 5.46 m²
Windows: 2 × 1.2 × 1.2 × 2 sides × 0.80 = 4.61 m²
Total painted area = 10.07 m², which is taken for primer (1 coat) and enamel (2 coats).

Answer: Excavation 15.23 m³; timber frames 0.111 m³; painting 10.07 m² (assumed dimensions).

✓ Answer checked by Claude Opus 5.5 (high effort)

Building: excavation, second footing, wood frames · Estimating and Costing, chapter 6
Building: excavation, brick 1:4, wood work · Estimating and Costing, chapter 6
Building: excavation, PCC, brick, wood work · Estimating and Costing, chapter 6
Building: PCC, brick, sal wood frame, RCC slab · Estimating and Costing, chapter 6
Building: excavation, PCC foundation, brick · Estimating and Costing, chapter 6
One-roomed building: earthwork, plaster, openings · Estimating and Costing, chapter 6
Emulsion paint; painting on new woodwork · Building Technology, chapter 9
Thermal insulation of walls, doors, windows, roofs · Building Technology, chapter 1 · asked 3×
Purpose and sizing of doors and windows; panelled doors · Building Technology, chapter 6

All Estimating and Costing chapter 6 questions →

Building: excavation, wood frames, enamel paint

i) Earthwork in excavation in foundation

ii) Wood work for door and window frames

iii) Two coats of enamel paint over one coat of primer

Related questions