- 2076 Asoj · 12 marks
Building: excavation, second footing, wood frames
Short answer
For assumed room 5.0×3.5 m: earthwork excavation 16.13 m³, brickwork in second footing 1.24 m³, and woodwork for frames 0.111 m³.
Estimate the quantities of the following items of work from the accompanying building drawings: a) Earthwork in excavation in foundation b) Brick work in 2nd footing in foundation c) Wood work for doors and windows frame [Drawing not included in the scanned paper]
The drawing is not available, so a room 5.0 m × 3.5 m clear with 230 mm walls is assumed. Centre-line length = 2(5.0 + 3.5 + 0.46) = 17.92 m.
Foundation assumed: trench 0.90 m wide × 1.00 m deep, PCC 1:3:6 200 mm, first footing 0.69 m × 0.15 m, second footing 0.46 m × 0.15 m (each footing step projects 115 mm, i.e. half a brick, on each side beyond the one above), then 230 mm wall. Openings: D 1.0 × 2.1 m (1 no.), W 1.2 × 1.2 m (2 nos.); frame 100 × 75 mm.
a) Earthwork in excavation
| Item | No. | L (m) | B (m) | H/D (m) | Qty (m³) |
|---|---|---|---|---|---|
| Trench, all walls (centre-line) | 1 | 17.920 | 0.900 | 1.000 | 16.128 |
| Total | 16.128 |
b) Brickwork in second footing
The second footing is the upper step, 0.46 m wide:
| Item | No. | L (m) | B (m) | H/D (m) | Qty (m³) |
|---|---|---|---|---|---|
| Second footing, 0.46 m wide | 1 | 17.920 | 0.460 | 0.150 | 1.236 |
| Total | 1.236 |
(If your drawing counts the lower, wider step as the "second" footing, its quantity is 1.85 m³, found the same way.)
c) Wood work for door and window frames
| Item | No. | L (m) | B (m) | H/D (m) | Qty (m³) |
|---|---|---|---|---|---|
| Door frame 2×2.1 + 1.0 | 1 | 5.200 | 0.100 | 0.075 | 0.0390 |
| Window frames 2 × (2×1.2 + 2×1.2) | 2 | 4.800 | 0.100 | 0.075 | 0.0720 |
| Total | 0.1110 |
Answer: Excavation 16.13 m³; second-footing brickwork 1.24 m³; frame timber 0.111 m³ (assumed dimensions).
✓ Answer checked by Claude Opus 5.5 (high effort)
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