- Asked 2/22
- 2067 Asar (old course) · 14 marks
Earthwork, concrete, brick, RCC from drawing
Short answer
Using centre-line method for an assumed one-room building with RCC roof: excavation 15.23 m3, cement concrete 4.62 m3, first class brickwork 16.99 m3, RCC 2.61 m3. Deduct openings and lintels from brickwork; roof slab and lintels are measured under RCC.
Estimate the quantities of the following items of work from the accompanying drawing. a) Earthwork in excavation b) Cement concrete c) 1st class brick work d) RCC work [Drawing not included in the scanned paper]
No drawing is given. The method is therefore shown on an assumed one-room building with an RCC flat roof, using the centre-line method.
Assumed data
- Room 4.5 m × 3.5 m clear; walls 0.23 m (first class brick in 1:6 cement mortar); centre-line length = 2(4.5 + 3.5 + 2 × 0.23) = 16.92 m.
- Trench 0.90 m wide, 1.00 m deep; PCC 1:3:6, 0.20 m thick; two brick footing steps (0.69 m and 0.46 m wide, 0.15 m each); plinth 0.45 m above GL; ceiling height 3.0 m.
- One door 1.0 × 2.1 m and two windows 1.2 × 1.2 m; RCC lintels 0.23 × 0.15 m with 0.2 m bearing on each side; roof slab 125 mm; floor PCC 100 mm.
- Wall height from the last footing to the plinth top = 1.00 − 0.20 − 0.30 + 0.45 = 0.95 m.
a) Earthwork in excavation
| Item | No. | L (m) | B (m) | H/D (m) | Qty (m³) |
|---|---|---|---|---|---|
| Trench, all walls (centre-line) | 1 | 16.920 | 0.900 | 1.000 | 15.228 |
| Total | 15.228 |
b) Cement concrete
| Item | No. | L (m) | B (m) | H/D (m) | Qty (m³) |
|---|---|---|---|---|---|
| PCC bed under walls | 1 | 16.920 | 0.900 | 0.200 | 3.046 |
| Floor PCC 1:4:8, 100 mm (room) | 1 | 4.500 | 3.500 | 0.100 | 1.575 |
| Total | 4.621 |
c) First class brick work (foundation, plinth and superstructure)
| Item | No. | L (m) | B (m) | H/D (m) | Qty (m³) |
|---|---|---|---|---|---|
| Brick footing step 1 (0.69 m wide) | 1 | 16.920 | 0.690 | 0.150 | 1.751 |
| Brick footing step 2 (0.46 m wide) | 1 | 16.920 | 0.460 | 0.150 | 1.167 |
| Wall up to plinth | 1 | 16.920 | 0.230 | 0.950 | 3.697 |
| Wall above plinth, full length | 1 | 16.920 | 0.230 | 3.000 | 11.675 |
| Deduct door 1.00×2.10 | -1 | 1.000 | 0.230 | 2.100 | -0.483 |
| Deduct window 1.20×1.20 | -2 | 1.200 | 0.230 | 1.200 | -0.662 |
| Deduct lintel over door (1.00 m opening + 2 × 0.20 m bearing) | -1 | 1.400 | 0.230 | 0.150 | -0.048 |
| Deduct lintels over windows (1.20 m opening + 2 × 0.20 m bearing) | -2 | 1.600 | 0.230 | 0.150 | -0.110 |
| Total | 16.986 |
(The full lintels are deducted from the brickwork because they are measured under RCC work.)
d) RCC work
| Item | No. | L (m) | B (m) | H/D (m) | Qty (m³) |
|---|---|---|---|---|---|
| Roof slab, 125 mm (outer size of walls) | 1 | 4.960 | 3.960 | 0.125 | 2.455 |
| Lintel over door | 1 | 1.400 | 0.230 | 0.150 | 0.048 |
| Lintels over windows | 2 | 1.600 | 0.230 | 0.150 | 0.110 |
| Total | 2.614 |
Answer: Excavation = 15.23 m³; cement concrete = 4.62 m³; brickwork = 16.99 m³; RCC = 2.61 m³ (assumed dimensions; follow the same sequence for the actual drawing).
Quantities are taken in the usual order: length × breadth × height/depth, in cubic metres (m³) or square metres (m²), with deductions entered as negatives. Rates are not asked; when costing, apply the current District Rate and DUDBC rate-analysis norms of the district.
✓ Answer checked by Claude Opus 5.5 (high effort)
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