RCC slab culvert 1.5 m span: four items

Reading of the drawing (some dimensions are hard to read; assumed values are stated)

• Roadway $4.00$ m + two kerbs of $0.45$ m: width of culvert $4.90$ m = length of abutment.
• Clear span between abutments $1.20$ m, bearing $0.15$ m each side, so slab span $1.50$ m; slab thickness $0.20$ m (assumed).
• Abutment: brick shaft $0.40$ m thick $\times$ $1.00$ m high on a brick footing $0.70$ m wide $\times$ $0.30$ m high; PCC (1:3:6) bed $1.00$ m wide $\times$ $0.30$ m thick; bottom of PCC $0.60$ m below ground (footing + PCC).

a) Earthwork in excavation

$V = 2 \times 1.00 \times 4.90 \times 0.60 = 5.880$ m³

b) PCC (1:3:6) in foundation

$V = 2 \times 1.00 \times 4.90 \times 0.30 = 2.940$ m³

c) Brickwork in 1:4 mortar

Area of one abutment section $= 0.70 \times 0.30 + 0.40 \times 1.00 = 0.61$ m²

$V = 2 \times 4.90 \times 0.61 = 5.978$ m³

d) PCC (1:2:4) for RCC slab

$V = 4.90 \times 1.50 \times 0.20 = 1.470$ m³

Answer: excavation = 5.880 m³; PCC (1:3:6) = 2.940 m³; brickwork = 5.978 m³; slab concrete (1:2:4) = 1.470 m³.