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Building: excavation, brick 1:4, wood work

Short answer

For assumed room 4.0×3.6 m: earthwork excavation 14.51 m³, first class brickwork in 1:4 mortar in foundation and plinth 6.30 m³, and woodwork for frames 0.141 m³.

Prepare detailed estimate of the following items of work for a building from the attached Fig. 1. i) Earthwork in excavation in foundation ii) First class brick work in (1:4) cement mortar in foundation and plinth. iii) Wood work in door and window frame. [Fig. 1 not included in the scanned paper]

Fig. 1 is not available, so the method is worked on an assumed room 4.0 m × 3.6 m clear with 230 mm walls. Centre-line length = 2(4.0 + 3.6 + 2 × 0.23) = 16.12 m.

Assumed data

  • Trench 0.90 m × 1.00 m; PCC 1:3:6 200 mm; first class brick footings 0.69 m and 0.46 m wide (150 mm each); 230 mm wall to plinth (0.45 m above GL), wall height from the last step = 0.95 m.
  • Door D 1.0 × 2.1 (1 no.); windows W1 1.2 × 1.2 (1 no.), W2 1.0 × 1.2 (2 nos.); frames 100 × 75 mm.

i) Earthwork in excavation in foundation

ItemNo.L (m)B (m)H/D (m)Qty (m³)
Trench, all walls (centre-line)116.1200.9001.00014.508
Total14.508

ii) First class brickwork (1:4) in foundation and plinth

ItemNo.L (m)B (m)H/D (m)Qty (m³)
Brick footing step 1 (0.69 m wide)116.1200.6900.1501.668
Brick footing step 2 (0.46 m wide)116.1200.4600.1501.112
Wall up to plinth116.1200.2300.9503.522
Total6.303

iii) Wood work in door and window frames

FrameNo.L (m)B (m)H/D (m)Qty (m³)
Door frame D (2×2.1 + 1.0)15.2000.1000.0750.0390
Window frame W1 (2×1.2 + 2×1.2)14.8000.1000.0750.0360
Window frame W2 (2×1.2 + 2×1.0)24.4000.1000.0750.0660
Total0.1410

Answer: Excavation 14.51 m³; brickwork 6.30 m³; timber for frames 0.141 m³ (assumed dimensions).

✓ Answer checked by Claude Opus 5.5 (high effort)

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