How are bricks per m^3 found?

1 divided by volume of brick with mortar (0.245 x 0.120 x 0.067) = 507.67

1 divided by brick size without mortar = 678.7

1 divided by 0.235 x 0.11 x 0.057 only, then minus 1.27

How is wet mortar per m^3 of brickwork found?

1 minus the volume of bricks only, giving 0.2520 m^3

1 minus brick-with-mortar volume

Wet mortar 6.955 m^3 gives which cement?

Dry 8.832 m^3, cement 1/7 = 1.262 m^3 = 36.3 bags

2076 Asoj · 6 marks

Materials for 100 m brick wall 1:6

Short answer

Wall volume 27.60 m³ yields 14,012 bricks (nominal size 235×110×57 mm with 10 mm joint). Mortar dry volume 8.832 m³ for 1:6 mix: cement 36.3 bags, sand 7.57 m³.

Calculate the quantities of materials required for a 100 m long, 23 cm thick and 1.20 m high wall in (1:6) cement mortar. (Assume size of brick is 235 × 110 × 57 mm and thickness of mortar 10 mm.)

Assumptions: dry volume = 1.54 × wet volume for concrete and 1.27 × wet volume for mortar; 1 m³ of cement = 28.8 bags of 50 kg; no wastage is added.

Volume of wall

$V = 100 \times 0.23 \times 1.20 = 27.60$ m³ (23 cm = two bricks of 110 mm plus one 10 mm joint).

Quantities (brick 235 × 110 × 57 mm, joint 10 mm, mortar 1:6)

Brickwork 1:6

Brick with mortar $= 0.245 \times 0.120 \times 0.067 = 1969.8\times 10^{-6}$ m³; bricks per m³ $= 1/1969.8\times10^6 = 507.67$
Bricks for 27.60 m³ $= 507.67 \times 27.60 = 14,012$ nos (say 14,012)
Volume of bricks only $= 0.235\times0.110\times0.057 = 1473.4\times10^{-6}$ m³ each; wet mortar per m³ $= 1 - 507.67\times1473.4\times10^{-6} = 0.2520$ m³
Wet mortar for 27.60 m³ $= 6.955$ m³; dry $= 1.27\times6.955 = 8.832$ m³
Cement $= 1/7\times8.832 = 1.262$ m³ $= 36.3$ bags
Sand $= 6/7\times8.832 = 7.571$ m³

Answer: bricks = 14,012 nos; cement = 36.3 bags; sand = 7.57 m³.

✓ Answer checked by Claude Opus 5.5 (high effort)

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Materials for 100 m brick wall 1:6

Volume of wall

Quantities (brick 235 × 110 × 57 mm, joint 10 mm, mortar 1:6)

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