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Brick (1:6) materials; PCC (1:2:4) rate

Short answer

Per m³ brickwork: 535 bricks, 1.34 bags cement, 0.279 m³ sand. For 10 m³: 5,342 bricks, 13.4 bags cement, 2.79 m³ sand. PCC 1:2:4 rate: NPR 24,982.50 per m³ (cement 6.336 bags, sand 0.44 m³, aggregate 0.88 m³, overhead & profit 15%+10%).

Workout quantities of materials required in brickwork (consider brick size 230 mm × 110 mm × 55 mm and mortar joint thickness as 10 mm) in cement mortar (1:6). Prepare rate analysis of plain cement concrete (1:2:4). Assume suitable rates of labor and materials.

Assumptions: dry volume = 1.54 × wet volume for concrete and 1.27 × wet volume for mortar; 1 m³ of cement = 28.8 bags of 50 kg; no wastage is added. No volume of brickwork is given, so the quantities are worked per 1 m³ and per 10 m³ (multiply for the actual volume).

Part 1: Quantities of materials for brickwork (brick 230 × 110 × 55 mm, joint 10 mm, mortar 1:6)

Per 1 m³ of brickwork

  • Brick with mortar =0.240×0.120×0.065=1872.0×10−6= 0.240 \times 0.120 \times 0.065 = 1872.0\times 10^{-6} m³; bricks per m³ =1/1872.0×106=534.19= 1/1872.0\times10^6 = 534.19
  • Bricks for 1.00 m³ =534.19×1.00=534= 534.19 \times 1.00 = 534 nos (say 535)
  • Volume of bricks only =0.230×0.110×0.055=1391.5×10−6= 0.230\times0.110\times0.055 = 1391.5\times10^{-6} m³ each; wet mortar per m³ =1−534.19×1391.5×10−6=0.2567= 1 - 534.19\times1391.5\times10^{-6} = 0.2567 m³
  • Wet mortar for 1.00 m³ =0.257= 0.257 m³; dry =1.27×0.257=0.326= 1.27\times0.257 = 0.326 m³
  • Cement =1/7×0.326=0.047= 1/7\times0.326 = 0.047 m³ =1.3= 1.3 bags
  • Sand =6/7×0.326=0.279= 6/7\times0.326 = 0.279 m³

Per 10 m³ of brickwork

  • Brick with mortar =0.240×0.120×0.065=1872.0×10−6= 0.240 \times 0.120 \times 0.065 = 1872.0\times 10^{-6} m³; bricks per m³ =1/1872.0×106=534.19= 1/1872.0\times10^6 = 534.19
  • Bricks for 10.00 m³ =534.19×10.00=5,342= 534.19 \times 10.00 = 5,342 nos (say 5,342)
  • Volume of bricks only =0.230×0.110×0.055=1391.5×10−6= 0.230\times0.110\times0.055 = 1391.5\times10^{-6} m³ each; wet mortar per m³ =1−534.19×1391.5×10−6=0.2567= 1 - 534.19\times1391.5\times10^{-6} = 0.2567 m³
  • Wet mortar for 10.00 m³ =2.567= 2.567 m³; dry =1.27×2.567=3.260= 1.27\times2.567 = 3.260 m³
  • Cement =1/7×3.260=0.466= 1/7\times3.260 = 0.466 m³ =13.4= 13.4 bags
  • Sand =6/7×3.260=2.794= 6/7\times3.260 = 2.794 m³

Answer: per m³ of brickwork about 535 bricks, 1.34 bags cement and 0.279 m³ sand; per 10 m³: 5,342 bricks, 13.4 bags cement and 2.79 m³ sand.

Part 2: Rate analysis of PCC (1:2:4) per m³

Rates and labour norms below are illustrative (DUDBC-style norms; use the current District Rate and norms of the project area for a real estimate): cement NPR 1,000/bag, sand NPR 3,500/m³, 20 mm aggregate NPR 4,500/m³, skilled labour NPR 1,500/day, unskilled labour NPR 1,100/day, water lump sum, contractor's overhead 15% and profit 10% on direct cost (VAT excluded).

  • Dry volume =1.54= 1.54 m³; cement =1/7×1.54=0.2200= 1/7\times1.54 = 0.2200 m³ =6.336= 6.336 bags; sand =2/7×1.54=0.4400= 2/7 \times 1.54 = 0.4400 m³; aggregate =4/7×1.54=0.8800= 4/7\times1.54 = 0.8800 m³
  • Labour: 1.0 skilled and 6.0 unskilled days per m³.
ItemQtyUnitRate (NPR)Amount (NPR)
Cement6.336bag1,000.006,336.00
Sand0.4400m³3,500.001,540.00
Coarse aggregate0.8800m³4,500.003,960.00
Skilled labour1.000day1,500.001,500.00
Unskilled labour6.000day1,100.006,600.00
Water and curing (lump)1LS50.0050.00
Direct cost19,986.00
Contractor's overhead @ 15%2,997.90
Contractor's profit @ 10%1,998.60
Total (rate per m³)24,982.50

Rate of PCC (1:2:4) = NPR 24,982.50 per m³.

✓ Answer checked by Claude Opus 5.5 (high effort)

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