Materials: 10 m³ brick 1:4, 100 m³ PCC 1:3:6

Assumptions: dry volume = 1.54 × wet volume for concrete and 1.27 × wet volume for mortar; 1 m³ of cement = 28.8 bags. The brick size is not given, so 230 × 110 × 55 mm bricks with 10 mm joints are assumed.

(i) 10 m³ brickwork in 1:4 cement mortar

• Volume of one brick with mortar $= 0.240 \times 0.120 \times 0.065 = 1872.0\times 10^{-6}$ m³; bricks per m³ $= 1/(1872.0\times10^{-6}) = 534.19$
• Bricks for 10.00 m³ $= 534.19 \times 10.00 = 5,342$ nos
• Volume of one brick alone $= 0.230\times0.110\times0.055 = 1391.5\times10^{-6}$ m³; wet mortar per m³ $= 1 - 534.19\times1391.5\times10^{-6} = 0.2567$ m³
• Wet mortar for 10.00 m³ $= 2.567$ m³; dry volume $= 1.27\times2.567 = 3.260$ m³
• Cement $= 1/5\times3.260 = 0.652$ m³ $= 0.652 \times 28.8 = 18.8$ bags
• Sand $= 4/5\times3.260 = 2.608$ m³

(ii) 100 m³ PCC (1:3:6) in foundation

• Wet volume $= 100.000$ m³; dry volume $= 1.54 \times 100.000 = 154.000$ m³ (sum of ratio $= 1 + 3 + 6 = 10$)
• Cement $= 1/10 \times 154.000 = 15.400$ m³ $= 15.400 \times 28.8 = 443.5$ bags (50 kg)
• Sand $= 3/10 \times 154.000 = 46.200$ m³
• Coarse aggregate $= 6/10 \times 154.000 = 92.400$ m³

Answer: (i) bricks 5,342 nos, cement 18.8 bags, sand 2.61 m³. (ii) cement 443.5 bags, sand 46.20 m³, coarse aggregate 92.40 m³.