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Materials for 115 m³ brick masonry 1:3

Short answer

Using dry factor 1.27 for mortar and nominal brick size 252x127x72 mm, bricks per m³ is 434. For 115 m³ brickwork, bricks = 49,907 nos, cement = 295.8 bags, sand = 30.82 m³.

Calculate the quantities of materials required for 115 m³ of brick masonry in (1:3) cement mortar (the size of brick is 240 × 115 × 60 mm and thickness of mortar is 12 mm).

Assumptions: dry volume = 1.54 × wet volume for concrete and 1.27 × wet volume for mortar; 1 m³ of cement = 28.8 bags of 50 kg; no wastage is added.

Brick 240 × 115 × 60 mm, mortar joint 12 mm.

115 m³ brickwork, mortar 1:3

  • Brick with mortar =0.252×0.127×0.072=2304.3×10−6= 0.252 \times 0.127 \times 0.072 = 2304.3\times 10^{-6} m³; bricks per m³ =1/2304.3×106=433.97= 1/2304.3\times10^6 = 433.97
  • Bricks for 115.00 m³ =433.97×115.00=49,907= 433.97 \times 115.00 = 49,907 nos (say 49,907)
  • Volume of bricks only =0.240×0.115×0.060=1656.0×10−6= 0.240\times0.115\times0.060 = 1656.0\times10^{-6} m³ each; wet mortar per m³ =1−433.97×1656.0×10−6=0.2813= 1 - 433.97\times1656.0\times10^{-6} = 0.2813 m³
  • Wet mortar for 115.00 m³ =32.354= 32.354 m³; dry =1.27×32.354=41.090= 1.27\times32.354 = 41.090 m³
  • Cement =1/4×41.090=10.272= 1/4\times41.090 = 10.272 m³ =295.8= 295.8 bags
  • Sand =3/4×41.090=30.817= 3/4\times41.090 = 30.817 m³

Answer: bricks = 49,907 nos; cement = 295.8 bags; sand = 30.82 m³.

✓ Answer checked by Claude Opus 5.5 (high effort)

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