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Droop for capacity sharing: 500 and 250 MW

Short answer

For capacity-proportional sharing, both units must have the same per-unit droop. Therefore the 250 MW unit must have a droop of 5% on its own rating, same as the 500 MW unit.

Two generating units of 500MW and 250 MW capacities respectively are operating in parallel and supplying power to a common load. When each generator is half loaded, they operate at a common frequency of 50 Hz. If the droop regulation of 500MW generating set is 5% based on its rating, what must be the droop regulation of 250 MW generating unit based on its own rating so that they share the change in load according to their capacities.

For two units to share any change in load according to their capacities, each must change by the same fraction of its rating for the same frequency change.

From the droop definition, for a common Δf\Delta f:

ΔP1Pr1=Δf/f0R1,ΔP2Pr2=Δf/f0R2\frac{\Delta P_1}{P_{r1}} = \frac{\Delta f/f_0}{R_1}, \qquad \frac{\Delta P_2}{P_{r2}} = \frac{\Delta f/f_0}{R_2}

Sharing by capacity requires

ΔP1Pr1=ΔP2Pr2  ⇒  R1=R2\frac{\Delta P_1}{P_{r1}} = \frac{\Delta P_2}{P_{r2}} \;\Rightarrow\; R_1 = R_2

So R2=R1=5 %R_2 = R_1 = 5\ \%.

Check with numbers: for, say, a 75 MW increase,

K1=5000.05×50=200 MW/Hz,K2=2500.05×50=100 MW/HzΔf=−75300=−0.25 HzΔP1=50 MW,ΔP2=25 MW\begin{aligned} K_1 &= \frac{500}{0.05 \times 50} = 200\ \text{MW/Hz}, \quad K_2 = \frac{250}{0.05 \times 50} = 100\ \text{MW/Hz} \\ \Delta f &= -\frac{75}{300} = -0.25\ \text{Hz} \\ \Delta P_1 &= 50\ \text{MW}, \quad \Delta P_2 = 25\ \text{MW} \end{aligned}

Ratio 50:25=500:25050:25 = 500:250, i.e. in proportion to capacity ✓.

Answer: The 250 MW unit must have a droop of 5 % on its own rating (the same per-unit droop as the 500 MW unit).

✓ Answer checked by Claude Opus 5.5 (high effort)

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