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Power measurement with circulating calorimeter
Short answer
A circulating calorimeter measures high continuous microwave power by flowing water through a matched load and measuring temperature rise. Power is P = rho v c DeltaT, with DC substitution to remove errors. Example: 0.5 L/min flow and 2.87 C rise gives 100.1 W.
Discuss in detail the power measurement using circulating calorimeter.
A circulating (flow) calorimeter measures high continuous microwave power by passing a fluid (usually water) through the load at a steady rate and measuring the temperature rise of the fluid. All the absorbed power is carried away by the flowing fluid.
Principle
P = ρ·v·c·ΔT (W)
ρ = density of fluid (kg/m³)
v = volume flow rate (m³/s)
c = specific heat (J/kg·°C)
ΔT = T_out − T_in (°C)
(ρ·v = mass flow rate ṁ, so P = ṁ·c·ΔT)
Construction
water in (T_in)
|
RF in ====[ water load: glass/ ]
[ dielectric tube in ]
[ tapered waveguide ]
|
water out (T_out)
|
[flow meter] [ΔT sensor: thermocouples
or thermopile]
- The load is a tube of water (or lossy liquid) placed across or along a tapered waveguide so that it is well matched and absorbs all incident power.
- Flow system: a pump circulates water at a constant, measured rate.
- Temperature sensors (thermocouples or thermopile) measure inlet and outlet temperatures.
- Heat exchanger (closed loop) cools the water before it returns.
Measurement procedure
- Start the flow and wait for steady inlet temperature.
- Apply microwave power and wait until the outlet temperature becomes steady.
- Read the flow rate and ΔT and compute P.
- Substitution check: switch off RF and pass a known DC/50 Hz power through a heater in the same load to get the same ΔT; the RF power equals this known power. This removes errors from flow measurement and heat leakage.
Example
Water flow 0.5 L/min (ρv = 0.5/60 = 8.33×10⁻³ kg/s), c = 4186 J/kg·°C, ΔT = 2.87 °C:
P = 8.333×10⁻³ × 4186 × 2.87 = 100.1 W
Features
| Advantage | Limitation |
|---|---|
| Measures high power (100 W to MW) | Slow response |
| Absolute, accurate (±1–2 %) | Needs pump, flow meter |
| Continuous measurement | Heat loss and flow errors |
| Load handles high power safely | Bulky set-up |
Compared with a static calorimeter, it can run continuously because heat is removed all the time, so it suits transmitters, radars and magnetrons.
✓ Answer checked by Claude Opus 5.5 (high effort)
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