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Power measurement with static calorimeter

Short answer

A static calorimeter absorbs microwave power in a fixed thermally insulated mass and measures temperature rise. Power is P = m c DeltaT / t, with DC substitution used for calibration. Example: 0.1 kg water rising 2.4 C in 60 s gives 16.74 W.

Explain how microwave power is measured with static calorimeter.

A calorimeter measures high microwave power by converting it completely into heat in a load and measuring the temperature rise. In a static calorimeter, a fixed (non-flowing) mass of absorbing material is heated.

Principle

P = m·c·ΔT / t
m  = mass of absorbing load (kg)
c  = specific heat (J/kg·°C)
ΔT = temperature rise (°C) in time t (s)

Construction and working

 RF in      insulated (thermally isolated) load
 ======[ waveguide ]==[ absorbing load ]
                         |  thermometer /
                         |  thermocouple
                      [ ΔT readout ]
  1. A matched, thermally insulated load (water, lossy dielectric or absorbing block) terminates the waveguide.
  2. The microwave power is applied for a known time t; the load absorbs all of it.
  3. The temperature rise ΔT is measured with a thermometer or thermocouple.
  4. Power is calculated from P = m·c·ΔT/t. To remove the need to know m and c exactly, the same load is calibrated by applying a known DC or 50 Hz power and noting its temperature rise (substitution method):
P_RF = P_DC × (ΔT_RF / ΔT_DC)   (same time)

Example

A 0.1 kg water load (c = 4186 J/kg·°C) rises by 2.4 °C in 60 s:

P = 0.1 × 4186 × 2.4 / 60 = 16.74 W

Features

  • Suitable for medium to high power (watts to kilowatts); accurate (about ±1 %) because it is an absolute method.
  • Slow; heat losses through insulation and the mount cause error, so good thermal isolation is needed.
  • For continuous high power, the circulating (flow) calorimeter is used instead.

✓ Answer checked by Claude Opus 5.5 (high effort)

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