- Asked 2/23
- 2072 Asoj · 2+8 marks
- 2070 Bhadra · 4+6 marks
VSWR meter and low power (bolometer) measurement
Short answer
Standing waves: a slotted-line probe with crystal detector feeds a VSWR meter. For low VSWR, it directly reads E_max/E_min; for high VSWR, the double-minimum width gives S≈λg/[π(d2−d1)]. Low power: a bolometer (barretter/thermistor) in a bridge; RF heating unbalances it, and DC is reduced to rebalance, yielding P_RF=(I1²−I2²)R.
Describe how standing waves and microwave powers are measured with VSWR meter and bolometry (low power measurement) respectively.
The VSWR meter with a slotted line measures the standing-wave ratio on a line, and the bolometer bridge measures low microwave power (below about 10 mW).
Measuring standing waves with a VSWR meter
Set-up:
Klystron -> Isolator -> Var. -> Freq. -> Slotted -> Load
(1 kHz AM) atten. meter line
|
probe + crystal
|
VSWR meter
- The source is square-wave modulated at 1 kHz.
- A probe moves along the slotted line and samples the field. A crystal detector (square law, V ∝ E²) recovers the 1 kHz envelope.
- The VSWR meter is a high-gain amplifier tuned to 1 kHz, with a meter calibrated in VSWR and dB for a square-law detector.
Steps (low VSWR, S < 10, direct method):
- Move the probe to a voltage maximum; adjust the gain so the meter reads full scale (VSWR = 1.0).
- Move the probe to the next minimum; read the VSWR directly from the scale.
- S = E_max / E_min. Also |Γ| = (S − 1)/(S + 1).
- Twice the distance between two successive minima gives λg.
For high VSWR (S > 10), the double minimum method is used: find the two positions d1, d2 on either side of the minimum where the power is twice the minimum (3 dB up). Then S ≈ λg / [π(d2 − d1)].
Low power measurement by bolometry
A bolometer is a temperature-sensitive resistor: a barretter (platinum wire, R rises with power) or a thermistor (semiconductor, R falls with power). It is placed in a mount at the end of the line and forms one arm of a Wheatstone bridge.
+----R1----+----R2----+
| | |
DC --+ G +--
bias | | |
+----R3----+--Bolom.--+
^ RF power
Working (DC substitution):
- With no RF, DC bias current I1 heats the bolometer to the balance resistance R; the galvanometer G reads zero.
- RF is applied. It also heats the bolometer, so its resistance changes and the bridge becomes unbalanced.
- The DC current is reduced to I2 until balance returns. The bolometer is again at the same R and temperature, so the RF power has replaced the DC power removed:
P_RF = (I1² − I2²) · R
Example: R = 200 Ω, I1 = 8 mA, I2 = 5 mA P_RF = (64 − 25)×10⁻⁶ × 200 = 7.8 mW.
Limitations: ambient temperature drift (solved by a compensating bridge), low power only, and mismatch errors.
✓ Answer checked by Claude Opus 5.5 (high effort)
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