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Design traffic from surveys, with design-method examples

Short answer

Design traffic begins with classified volume counts to get commercial vehicles per day, projected to opening year. Axle load survey yields vehicle damage factor using the fourth power law. Cumulative standard axles over design life N = (365[(1+r)^n-1]/r)*A*D*F. Examples: IRC:37 computes msa; AASHTO uses ESALs with load equivalency factors; Asphalt Institute uses design lane ESAL.

Explain how design traffic is calculated from the data obtained from traffic surveys. Give at least three different examples in various design methods.

Design traffic is the number of load repetitions the pavement must carry in its design life. It is built from survey data in these steps:

  1. Traffic volume count (classified, 3-7 days, 12-24 h) gives the ADT/AADT by vehicle type; only commercial vehicles (above 3 t laden weight) are used for structural design (passenger cars are ignored).
  2. Growth - the count is projected with the growth rate rr (from past trends, regression or economic data) to the year of opening: A=P(1+r)xA=P(1+r)^x.
  3. Axle load survey (at weigh stations, 24 h) gives the axle load spectrum; each axle is converted to standard axles by the fourth power law or load equivalency factors, giving the vehicle damage factor (VDF).
  4. Lane and direction distribution - the share of traffic in the design lane.
  5. Cumulative load over design life nn:
Ns=365 [(1+r)n−1]r A D FN_s=\frac{365\,[(1+r)^n-1]}{r}\,A\,D\,F

Example 1 - IRC:37-2012 flexible pavement (msa)

Count 2000 CVPD, r=7.5%r=7.5\%, 2 years to completion, n=15n=15 years, VDF = 3.5, two-lane road (D=0.5D=0.5): A=2000(1.075)2=2311A=2000(1.075)^2=2311 CVPD; Ns=365×26.118×2311×0.5×3.5/106=38.6N_s=365\times26.118\times2311\times0.5\times3.5/10^6=38.6 msa. This design msa and the subgrade CBR are used to read the thickness from the catalogue.

Example 2 - AASHTO-93 (design ESALs, W18W_{18})

Each vehicle class is multiplied by its load equivalency factor (LEF) for the structural number and terminal serviceability, then by directional (DDD_D = 0.5) and lane (DLD_L = 0.8-1.0) factors and growth: W18=∑ni LEFi×365×DDDL×growth factorW_{18}=\sum n_i\,\text{LEF}_i\times365\times D_DD_L\times\text{growth factor}. For example, 100 trucks per day with LEF 1.2, DDDLD_DD_L=0.45, growth factor 27.15 (8 percent, 15 years): W18=100×1.2×365×0.45×27.15=0.535×106W_{18}=100\times1.2\times365\times0.45\times27.15=0.535\times10^6.

Example 3 - Asphalt Institute method (design lane ESAL)

Now daily ESAL both directions 1850 and design lane factor 0.45 (4 lanes): ESAL=1850×0.45×365×(1.06)15−10.06=7.07×106ESAL=1850\times0.45\times365\times\dfrac{(1.06)^{15}-1}{0.06}=7.07\times10^6 (construction period neglected). This ESAL and the subgrade modulus MR=10 CBRM_R=10\,CBR are used with the AI chart.

Example 4 - IRC:58 rigid pavement (CVPD classes)

The design CVPD at the end of construction (e.g. 1050(1.075)3=13041050(1.075)^3=1304) decides the traffic class (E: 450-1500 CVPD) and the thickness adjustment; the design wheel load (5100 kg) and the axle-load spectrum are used in the fatigue check of the slab.

✓ Answer checked by Claude Opus 5.5 (high effort)

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