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Flexible vs rigid; radius of relative stiffness, k

Short answer

Flexible pavements use bituminous layers and granular base with grain-to-grain load transfer; rigid pavements use concrete slabs bearing loads through bending. Radius of relative stiffness l = (E h^3/(12(1-µ^2)k))^¼ defines the slab area resisting load. Modulus of subgrade reaction k = p/∆ is pressure per unit deflection, measured via plate-load test.

List out the differences between flexible and rigid pavement. Explain the terms radius of relative stiffness (l) and modulus of subgrade reaction (k) used in the design of rigid pavements.

Differences between flexible and rigid pavement

BasisFlexible pavementRigid pavement
MaterialBituminous surface over granular layersCement concrete slab (PQC) on a sub-base
Load transferLayer to layer by grain contact; load spreads in a coneSlab action; bending resists the load, which spreads over a large area
Design basisLimiting strains, CBR/resilient modulus, thickness by IRC:37Flexural stress and fatigue, Westergaard analysis, IRC:58
Stresses on subgradeHigh, so many layers are neededVery low because of the wide spread
JointsNo joints, only cracksJoints are essential (contraction, expansion, longitudinal)
Temperature effectSurface softens in heat; little stressWarping and expansion stresses, so joints and dowels are needed
Life and cost10-15 years, low initial cost, higher maintenance20-40 years, high initial cost, low maintenance
Repair and openingQuick repair; opens to traffic soonLong curing (28 days), difficult repair
SurfaceSlightly rough, absorbs sound; self-healingSmooth and rigid; good in water-logged areas, poor skid resistance when polished

Radius of relative stiffness (l)

The radius of relative stiffness ll is a measure of how stiff the slab is compared with the subgrade support. It defines the area of slab that takes part in resisting a load (Westergaard).

l=[E h312 (1−μ2) k]1/4l=\left[\frac{E\,h^{3}}{12\,(1-\mu^{2})\,k}\right]^{1/4}

where EE is the modulus of elasticity of concrete (kg/cm2), hh the slab thickness (cm), μ\mu Poisson's ratio and kk the modulus of subgrade reaction (kg/cm3). The unit of ll is cm.

  • A thicker slab or higher EE gives a larger ll (a stiffer slab spreads the load over a wider area); a higher kk gives a smaller ll.
  • Typical values for 20-30 cm slabs are about 60-100 cm.
  • It is used in all the stress equations (Westergaard, Kelly, Bradbury), in the ratios L/lL/l and B/lB/l for the warping coefficient, and to decide joint spacing and the spread of dowel load transfer (about 1.8 l1.8\,l).

Modulus of subgrade reaction (k)

The modulus of subgrade reaction kk is the pressure required to cause unit deflection of the subgrade (Winkler's foundation assumption):

k=pΔ  (kg/cm3)k=\frac{p}{\Delta}\ \ (\text{kg/cm}^3)

It is found by a plate-load test: a rigid 75 cm diameter plate is loaded in increments, and kk is taken at 0.125 cm deflection (so k=p0.125/0.125k = p_{0.125}/0.125). The test value is corrected as follows:

  • Correction for plate size: k75=k30/2k_{75}= k_{30}/2 when a 30 cm plate is used.
  • Correction for saturation (soaking) of the subgrade soil.
  • A sub-base (e.g. lean concrete or granular) raises the effective kk; IRC:58 gives tables of kk over granular or cement-treated sub-bases.
  • Roughly, IRC:58 relates kk to the soaked CBR of the subgrade: about 2 kg/cm3 for CBR 2 and 5 to 6 kg/cm3 for CBR 10.

Rigid pavement stresses depend only weakly on kk (through ll), so approximate values are acceptable.

✓ Answer checked by Claude Opus 5.5 (high effort)

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