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Flexible vs rigid design; Westergaard temperature stresses

Short answer

Flexible pavement uses layered elastic theory, CBR/SN, and protects subgrade; rigid design treats slab as plate on elastic foundation using modulus k and flexural stress. Westergaard’s temperature concept models curling from top-bottom temperature difference, with reduced edge stress σ = CEαΔT/2 depending on slab length/radius ratio.

Differentiate between flexible pavement design and rigid pavement design. Describe Westergaard's concept for temperature stresses.

Flexible pavement design vs rigid pavement design

BasisFlexible pavement designRigid pavement design
Structural actionLayered system; load spread through layersSlab acting in flexure (plate on elastic foundation)
Theory usedBurmister layered elastic theory, empirical CBR or AASHO methodsWestergaard, Bradbury, Pickett-Ray analysis
Main design variableThickness of each layer (SN or total thickness)Slab thickness and joint details
Subgrade parameterCBR or resilient modulus MRM_RModulus of subgrade reaction kk
Traffic inputCumulative standard axles (msa, ESAL)Wheel load, load repetition (fatigue), CVPD class
Critical stress/strainTensile strain at bottom of bituminous layer; vertical strain on subgradeFlexural tensile stress at slab edge/corner (load + temperature)
TemperatureAffects stiffness of bituminous mixCauses warping and frictional stresses, so joints are needed
CodesIRC:37, AASHTO-93, Asphalt Institute, Road Note 31IRC:58, AASHTO rigid, PCA

Westergaard's concept of temperature stresses

Westergaard (1927) treated the slab as a plate on a dense-liquid foundation and analysed curling due to a temperature difference between top and bottom.

  • A temperature gradient ΔT\Delta T across the thickness hh makes the top and bottom expand or contract differently, so the slab tends to curve. In the daytime the top is warmer and the slab edges curl down; at night the edges curl up. The slab weight and the subgrade reaction resist the curvature, creating stresses.
  • If the slab were completely restrained from curving, the stress would be σ=EαΔT2(1−μ)\sigma=\dfrac{E\alpha\Delta T}{2(1-\mu)}.
  • For a finite slab free to curl, the stress is reduced by coefficients that depend on the ratio of slab length to radius of relative stiffness (L/lL/l). Bradbury's version of Westergaard's result for the edge is
σte=C E α ΔT2\sigma_{te}=\frac{C\,E\,\alpha\,\Delta T}{2}

and for the interior σti=EαΔT2(Cx+μCy1−μ2)\sigma_{ti}=\dfrac{E\alpha\Delta T}{2}\left(\dfrac{C_x+\mu C_y}{1-\mu^2}\right).

  • For short slabs (L/lL/l below about 4) CC is small, so closely spaced joints reduce warping stress; for slabs about 8-9 ll long CC reaches a maximum (about 1.08), and then decreases slightly.
  • The stress is tension at the bottom in the daytime and tension at the top at night; it is added to the load stress for the critical combination.

✓ Answer checked by Claude Opus 5.5 (high effort)

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