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Parking terms; speed-density and flow relations

Short answer

Parking accumulation is number of vehicles parked at a given time; turnover is rate of use per bay; load is total vehicle-hours; index is percentage occupancy relative to capacity. Speed-density relation is linear v=vf(1−k/kj); speed-flow relation is parabolic with maximum flow qmax=vf kj/4 at speed vf/2 and density kj/2.

Define parking accumulation, parking turnover, parking load and parking index. Explain speed-density relation and speed-flow relation with required graphs.

Parking terms

  • Parking accumulation: the number of vehicles parked in a study area at a given instant. Plotting it against time gives the accumulation curve; its peak gives the demand.
  • Parking volume: total number of vehicles parked in an area during a given period (usually a day); it counts each vehicle once.
  • Parking load: the area under the accumulation curve, in vehicle-hours (or vehicle-minutes) in a given period; it shows the total parking demand in time.
  • Parking duration: the length of time a vehicle stays parked.
  • Parking turnover: the rate of use of a parking space, the number of vehicles parked per bay in a given time.
Turnover=Number of vehicles parked in the periodNumber of parking bays available\text{Turnover} = \frac{\text{Number of vehicles parked in the period}}{\text{Number of parking bays available}}
  • Parking index (occupancy): the ratio of the number of bays occupied to the number of bays available, as a percentage. It measures how well the supply is used.
Parking index=Parking load (vehicle-hours)Parking capacity (bay-hours)×100\text{Parking index} = \frac{\text{Parking load (vehicle-hours)}}{\text{Parking capacity (bay-hours)}} \times 100

where parking capacity = number of bays x hours of study. An index near 100 percent means the supply is exhausted; a very low value means over-supply.

Speed-density relation

Speed falls as density rises. The simplest (Greenshields) model is linear:

v=vf(1−kkj)v = v_f\left(1 - \frac{k}{k_j}\right)

where vfv_f is the free-flow speed (at k→0k \to 0) and kjk_j is the jam density (where v=0v = 0).

 v ^
vf |*
   |   *
   |      *
   |         *
   |            *
   +---------------*--> k
   0               kj

Speed-flow relation

Since q=vkq = vk, eliminating kk gives q=kj(v−v2/vf)q = k_j\left(v - v^2/v_f\right), a parabola with maximum flow qmax=vfkj/4q_{max} = v_f k_j/4 at v=vf/2v = v_f/2.

 v ^
vf |*
   |  *
   |    *   uncongested
vm |- - - -*----- (v = vf/2)
   |       *  congested
   |     *
   +-----|----> q
   0   qmax

The upper branch is stable (uncongested) flow, and the lower branch is forced (congested) flow. Flow rises with density up to km=kj/2k_m = k_j/2 (capacity) and then falls to zero at jam density.

✓ Answer checked by Claude Opus 5.5 (high effort)

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