- 2081 Baisakh · 4+4 marks
Parking terms; speed-density and flow relations
Short answer
Parking accumulation is number of vehicles parked at a given time; turnover is rate of use per bay; load is total vehicle-hours; index is percentage occupancy relative to capacity. Speed-density relation is linear v=vf(1−k/kj); speed-flow relation is parabolic with maximum flow qmax=vf kj/4 at speed vf/2 and density kj/2.
Define parking accumulation, parking turnover, parking load and parking index. Explain speed-density relation and speed-flow relation with required graphs.
Parking terms
- Parking accumulation: the number of vehicles parked in a study area at a given instant. Plotting it against time gives the accumulation curve; its peak gives the demand.
- Parking volume: total number of vehicles parked in an area during a given period (usually a day); it counts each vehicle once.
- Parking load: the area under the accumulation curve, in vehicle-hours (or vehicle-minutes) in a given period; it shows the total parking demand in time.
- Parking duration: the length of time a vehicle stays parked.
- Parking turnover: the rate of use of a parking space, the number of vehicles parked per bay in a given time.
- Parking index (occupancy): the ratio of the number of bays occupied to the number of bays available, as a percentage. It measures how well the supply is used.
where parking capacity = number of bays x hours of study. An index near 100 percent means the supply is exhausted; a very low value means over-supply.
Speed-density relation
Speed falls as density rises. The simplest (Greenshields) model is linear:
where is the free-flow speed (at ) and is the jam density (where ).
v ^
vf |*
| *
| *
| *
| *
+---------------*--> k
0 kj
Speed-flow relation
Since , eliminating gives , a parabola with maximum flow at .
v ^
vf |*
| *
| * uncongested
vm |- - - -*----- (v = vf/2)
| * congested
| *
+-----|----> q
0 qmax
The upper branch is stable (uncongested) flow, and the lower branch is forced (congested) flow. Flow rises with density up to (capacity) and then falls to zero at jam density.
✓ Answer checked by Claude Opus 5.5 (high effort)
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