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Frequency counter operation with block diagram
Short answer
A frequency counter counts input cycles during a precise gate time from a crystal oscillator divider chain. The signal is shaped, gated by an AND gate, counted by BCD counters, latched, and displayed. Frequency f = N / T_gate. Example: 5000 counts in 1s gives 5 kHz.
With the help of block diagram explain the operation of frequency counter.
A frequency counter measures the frequency of a signal by counting the number of its cycles during an accurately known time interval (the gate time) and displaying the count:
Block diagram
Input +-----------+ pulses +-----+ +-----------+
signal->| Amplifier |--------->| |-->| Decade |
| & Schmitt | | AND | | counters |
| trigger | +---->|gate | | (BCD) |
+-----------+ | +-----+ +-----+-----+
| |
+---------+ +---------+ | gate +----------v----+
| Crystal |->| Divider |-+ pulse | Latch |
| osc. | | chain |---+ +-------+-------+
+---------+ +---------+ | |
+----v-----+ +-------v-------+
| Control | | BCD to 7-seg |
| (reset, | | decoders and |
| latch) | | displays |
+----------+ +---------------+
Working of each block
- Amplifier and Schmitt trigger (wave shaper): amplifies the unknown input (sine, triangle, etc.) and converts it into clean rectangular pulses of the same frequency, one pulse per cycle.
- Time base: a crystal oscillator (e.g. 1 MHz) followed by a chain of divide-by-10 counters gives a very accurate gate pulse of 1 s, 0.1 s, 10 ms, … selected by the range switch.
- AND (main) gate: one input receives the shaped pulses, the other the gate pulse. Pulses pass to the counter only while the gate pulse is HIGH, i.e. for exactly .
- Decade counters: cascaded BCD counters (e.g. 7490) count the pulses that pass the gate; each counter is one decimal digit.
- Control logic: before each gate period it resets the counters; when the gate closes it sends a latch (transfer) pulse, then resets again for the next measurement.
- Latch, decoder and display: the latch holds the final count so the display does not flicker while counting; BCD-to-7-segment decoders (e.g. 7447) drive the LED displays.
Example
With s, if 5000 pulses pass the gate, Hz = 5 kHz. With a 0.1 s gate the same signal gives 500 counts, displayed as 5.00 kHz with the decimal point shifted. A longer gate gives better resolution (1 Hz for a 1 s gate); the accuracy depends on the crystal time base, with an error of ±1 count.
✓ Answer checked by Claude Opus 5.5 (high effort)
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