- 2075 Baisakh · 6+2 marks
Equivalent circuits; transformer on dc supply
Short answer
Referred to primary: R₂′ = R₂/K², X₂′ = X₂/K²; R₀₁ = R₁ + R₂′, X₀₁ = X₁ + X₂′. Referred to secondary: R₁′ = K²R₁, etc. A transformer on DC has no induced back emf, current limited only by winding resistance, so I = V/R₁ causes severe overheating and burnout.
Explain how we can make equivalent circuits referred to primary side and referred to secondary side. What happens when a power transformer is connected to a d.c. supply of the same voltage ratings?
Equivalent circuit referred to primary or secondary
A real transformer has winding resistances R1, R2, leakage reactances X1, X2, and a no-load branch (Ro, Xo). To solve it as a single-voltage circuit, all quantities are expressed on one side, with K = N2/N1.
Rules for transferring impedance from one side to the other
- Voltage, current and impedance transform as: V2′ = V2/K, I2′ = K I2, Z2′ = Z2/K² (secondary to primary).
- The reverse: Z1′ = K² Z1 (primary to secondary).
- The VA, power and losses stay the same, only the base voltage changes.
| Referred to primary | Referred to secondary |
|---|---|
| R2′ = R2/K², X2′ = X2/K² | R1′ = K² R1, X1′ = K² X1 |
| R01 = R1 + R2/K² | R02 = R2 + K² R1 |
| X01 = X1 + X2/K² | X02 = X2 + K² X1 |
| Z01 = √(R01² + X01²) | Z02 = √(R02² + X02²) |
| Ro, Xo from the OC test (on the primary side) | Ro′ = K² Ro, Xo′ = K² Xo |
The magnetising branch is usually moved to the input terminals (approximate circuit), since the no-load current is small.
I1 R01 X01 I2'
o──┬───/\/\/──────(((────────────o
│
Ro∥Xo load, V2'
│
o──┴─────────────────────────────o
(referred to primary; reverse for secondary)
Referring to the secondary uses R02, X02, and the shunt branch Ro′, Xo′ at the output side in the same way.
Transformer connected to a d.c. supply of the same voltage rating
- A transformer works only on a changing flux. A d.c. supply creates a constant flux, so no back emf (E1 = −N dΦ/dt = 0) is induced in the primary.
- The only opposition to the current is the very low winding resistance R1. The current is I = V/R1, which is many times (often 20 to 100 times) the rated current.
- The large current heats the winding (I²R) and the insulation, and the primary winding burns out unless a fuse or circuit breaker acts quickly.
- The core may also saturate. A transformer must never be connected to d.c.
✓ Answer checked by Claude Opus 5.5 (high effort)
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