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Transformer equivalent circuit, referring parameters

Short answer

The equivalent circuit includes primary R1, X1, secondary R2, X2, and shunt Rc, Xm. To refer secondary to primary, multiply impedances by a^2 (a=N1/N2): R2'=a^2 R2, X2'=a^2 X2. Total referred series impedance is R01=R1+a^2 R2, X01=X1+a^2 X2.

Draw the equivalent circuit of a transformer with their parameters as it is in primary side and secondary side. How all parameters can be transferred to primary side - explain with mathematical derivation.

An equivalent circuit replaces the magnetically coupled windings with an electric network that has the same terminal behaviour. Winding resistance and leakage reactance are put in series, and the core is represented by a shunt branch.

Equivalent circuit (ideal transformer N1:N2N_1:N_2 in the centre)

   R1     X1                R2      X2
 o-/\/\--UUU--+---+----+--/\/\--UUU--o
              |   |    |  ideal      
  V1        Rc   Xm    ) N1:N2 (       V2   Load
              |   |    |             
 o------------+---+----+-------------o
  • R1,X1R_1, X_1: primary resistance and leakage reactance. R2,X2R_2, X_2: the secondary values.
  • RcR_c: core-loss resistance. XmX_m: magnetising reactance, with Ic=E1/RcI_c = E_1/R_c and Iμ=E1/XmI_\mu = E_1/X_m (where E1≈V1E_1 \approx V_1). Together they form I0I_0.
  • a=N1/N2a = N_1/N_2.

Referring all parameters to the primary side

The power in each element must remain the same after referring. Secondary quantities are referred to the primary as follows:

V2′=aV2,I2′=I2aV_2' = aV_2,\qquad I_2' = \frac{I_2}{a}

For the secondary impedance, equate the power (and reactive power) before and after referring:

I2′ 2R2′=I22R2⇒R2′=R2(I2I2′)2=a2R2I_2'^{\,2}R_2' = I_2^2R_2 \Rightarrow R_2' = R_2\left(\frac{I_2}{I_2'}\right)^2 = a^2R_2 X2′=a2X2,ZL′=a2ZLX_2' = a^2X_2,\qquad Z_L' = a^2Z_L

The referred circuit has all the elements on the primary side:

   R1    X1     R2'     X2'
 o-/\/\--UUU--+--/\/\--UUU--+---o
              |            |
  V1        Rc   Xm       ZL' (= a^2 ZL)
              |            |
 o------------+------------+---o

The total referred values are then

R01=R1+a2R2,X01=X1+a2X2,Z01=R012+X012R_{01} = R_1 + a^2R_2,\qquad X_{01} = X_1 + a^2X_2,\qquad Z_{01} = \sqrt{R_{01}^2 + X_{01}^2}

The shunt branch (Rc,XmR_c, X_m) is often moved to the input terminals (approximate circuit) because I0I_0 is small. With this approximation the circuit is V1V_1 across Rc∥XmR_c \parallel X_m, followed by R01+jX01R_{01} + jX_{01} in series with ZL′Z_L'.

Referring to the secondary side

Primary quantities are referred to the secondary by dividing by aa (voltage) and a2a^2 (impedance):

R1′=R1a2,X1′=X1a2,R02=R2+R1a2,X02=X2+X1a2R_1' = \frac{R_1}{a^2},\quad X_1' = \frac{X_1}{a^2},\quad R_{02} = R_2 + \frac{R_1}{a^2},\quad X_{02} = X_2 + \frac{X_1}{a^2}

Similarly Rc′=Rc/a2R_c' = R_c/a^2, Xm′=Xm/a2X_m' = X_m/a^2, and the primary current becomes aI1aI_1.

Rule: an impedance is multiplied by a2a^2 when moved from the secondary to the primary, and divided by a2a^2 when moved from the primary to the secondary, where a=N1/N2a = N_1/N_2.

✓ Answer checked by Claude Opus 5.5 (high effort)

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