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Classification of lines by length and model validity

Short answer

Lines are classified by length: short (<80 km, capacitance neglected), medium (80–250 km, nominal-π or T), long (>250 km, distributed parameters). The long-line model uses exact hyperbolic equations valid for any length. The short-line model omits shunt capacitance, giving incorrect results for medium and long lines where charging current is significant.

How are transmission lines classified according to their lengths? Explain why all lines can be represented by the long transmission line model whereas all the lines cannot be represented by the short transmission line model.

Transmission lines are classified by length because the effect of shunt capacitance (charging current) grows with length. The usual limits for 50 Hz lines are:

TypeLengthModel used
Shortup to 80 km (below about 20 kV)Series R+jXR + jX; capacitance neglected
Medium80–250 km (20–100 kV)Lumped: nominal-Π or nominal-T
Longabove 250 km (above 100 kV)Distributed parameters (exact)

Why every line can use the long-line model

  • The long-line model solves the line's differential equations exactly with distributed rr, LL, CC (A=cosh⁡γlA = \cosh\gamma l, B=Zcsinh⁡γlB = Z_c\sinh\gamma l, C=sinh⁡γl/ZcC = \sinh\gamma l/Z_c). It makes no approximation, so it is valid for any length.
  • For a short line, γl\gamma l is small, so cosh⁡γl≈1\cosh\gamma l \approx 1, Zcsinh⁡γl≈ZZ_c\sinh\gamma l \approx Z and sinh⁡γl/Zc≈0\sinh\gamma l/Z_c \approx 0. The model reduces to the short-line result. For a medium line, A≈1+ZY/2A \approx 1 + ZY/2 and B≈ZB \approx Z, which are the nominal-model values.
  • So the result is always correct; only the calculation is longer.

Why the short-line model cannot be used for all lines

  • It assumes C=0C = 0, so the charging current and the reactive power generated by the line are ignored, and IS=IRI_S = I_R.
  • For medium and long lines the charging current is a large part of the line current. Ignoring it gives wrong sending-end voltage, current, power factor, regulation and efficiency.
  • It cannot show the Ferranti effect (no-load VR>VSV_R > V_S) or the variation of voltage and current along the line.
  • So it is valid only where the charging current is negligible, that is, for short lines.

✓ Answer checked by Claude Opus 5.5 (high effort)

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