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Long line by short model and vice versa

Short answer

Modelling a long line with the short-line model ignores shunt capacitance, giving incorrect sending-end voltage, missing the Ferranti effect, wrong current and power factor, and unsafe design. Conversely, using the exact long-line model for a short line gives correct results because hyperbolic terms simplify to short-line parameters, but requires more computation.

What will happen if a long line is modelled by the short line model and vice versa?

The long-line model (distributed parameters) is exact for any length. The short-line model keeps only the series impedance ZZ and ignores the shunt capacitance (A=D=1A = D = 1, B=ZB = Z, C=0C = 0).

Long line modelled by the short-line model

A long line (above about 250 km) has a large shunt capacitance and large charging current, and the parameters are distributed. Using the short model:

  • Charging current is ignored. The sending-end current is taken equal to the receiving-end current, which is wrong; at light load the real ISI_S is mostly charging current.
  • Sending-end voltage is wrong. With a lagging load the short model overestimates VSV_S (no capacitive rise), so the voltage regulation comes out too high.
  • Ferranti effect cannot be predicted. At no load the short model gives VR=VSV_R = V_S, whereas a long line actually has VR>VSV_R > V_S.
  • Losses and efficiency are wrong, since the true current varies along the line.
  • Power factor at the sending end is wrong; the reactive power generated by the line is missing.
  • Reactive compensation, insulation and protection design based on these results would be unsafe.

Example: for a 300 km, 220 kV line delivering 50 MW at 0.8 lag (Z = 40 + j125 Ω, Y = j10⁻³ S), the short model gives VS≈251V_S \approx 251 kV at p.f. 0.75 lag, whereas the Π model gives about 238 kV at p.f. 0.99 lead.

Short line modelled by the long-line model

  • The long-line equations are exact for all lengths, so the results are correct.
  • For a short line, γl\gamma l is very small, so cosh⁡γl≈1\cosh\gamma l \approx 1, Zcsinh⁡γl≈ZZ_c\sinh\gamma l \approx Z and sinh⁡γl/Zc≈0\sinh\gamma l / Z_c \approx 0. The answers become practically the same as the short-line model.
  • The only drawback is more calculation (complex hyperbolic functions) for no real gain in accuracy.

Summary

CaseAccuracyEffect
Long line, short modelPoorWrong VSV_S, ISI_S, p.f., regulation; Ferranti effect missed
Short line, long modelExactCorrect, only more work

✓ Answer checked by Claude Opus 5.5 (high effort)

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