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Long line by short model and vice versa
Short answer
Modelling a long line with the short-line model ignores shunt capacitance, giving incorrect sending-end voltage, missing the Ferranti effect, wrong current and power factor, and unsafe design. Conversely, using the exact long-line model for a short line gives correct results because hyperbolic terms simplify to short-line parameters, but requires more computation.
What will happen if a long line is modelled by the short line model and vice versa?
The long-line model (distributed parameters) is exact for any length. The short-line model keeps only the series impedance and ignores the shunt capacitance (, , ).
Long line modelled by the short-line model
A long line (above about 250 km) has a large shunt capacitance and large charging current, and the parameters are distributed. Using the short model:
- Charging current is ignored. The sending-end current is taken equal to the receiving-end current, which is wrong; at light load the real is mostly charging current.
- Sending-end voltage is wrong. With a lagging load the short model overestimates (no capacitive rise), so the voltage regulation comes out too high.
- Ferranti effect cannot be predicted. At no load the short model gives , whereas a long line actually has .
- Losses and efficiency are wrong, since the true current varies along the line.
- Power factor at the sending end is wrong; the reactive power generated by the line is missing.
- Reactive compensation, insulation and protection design based on these results would be unsafe.
Example: for a 300 km, 220 kV line delivering 50 MW at 0.8 lag (Z = 40 + j125 Ω, Y = j10⁻³ S), the short model gives kV at p.f. 0.75 lag, whereas the Π model gives about 238 kV at p.f. 0.99 lead.
Short line modelled by the long-line model
- The long-line equations are exact for all lengths, so the results are correct.
- For a short line, is very small, so , and . The answers become practically the same as the short-line model.
- The only drawback is more calculation (complex hyperbolic functions) for no real gain in accuracy.
Summary
| Case | Accuracy | Effect |
|---|---|---|
| Long line, short model | Poor | Wrong , , p.f., regulation; Ferranti effect missed |
| Short line, long model | Exact | Correct, only more work |
✓ Answer checked by Claude Opus 5.5 (high effort)
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