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Suspension 100 m: max/min tension, SFD, BMD

Short answer

Per girder, H = 3000 kN. Maximum cable tension is 3231.10 kN at the supports; minimum is 3000.0 kN at mid-span. Cable length is 102.60 m. Girder maximum hogging moment is -312.5 kN m at 12.5, 37.5, 62.5 and 87.5 m; maximum shear is 50 kN.

A suspension bridge, 100 m span, has two three-hinged stiffening girders supported by two cables with a central dip of 10 m. The dead load is a uniformly distributed load of 40 kN/m for the entire span and in addition, it supports three point loads of 200 kN each placed along the center line of the roadway, dividing the span in four equal parts. Calculate the maximum tension and minimum tension with their locations in the cable and the length of the cable, also draw shear force and bending moment diagrams for the girders.

Assumptions. The loads given are for the whole bridge, so each of the two girders and cables carries half: ww = 40/2 = 20 kN/m and PP = 200/2 = 100 kN (if the data are taken for a single cable, double all forces below; the method does not change). Span LL = 100 m, dip dd = 10 m.

Cable pull HH

A three-hinged girder gives the cable a uniform load, so the cable stays parabolic.

  • Dead load part: Hd=wL28d=20(100)28(10)=2500.0H_d = \dfrac{wL^2}{8d} = \dfrac{20(100)^2}{8(10)} = 2500.0 kN
  • Point loads: RA=1.5P=150.0R_A = 1.5P = 150.0 kN; M0C=150.0(50)−100(25)=5000.0M_{0C} = 150.0(50) - 100(25) = 5000.0 kN m, so Hp=M0Cd=500.0H_p = \dfrac{M_{0C}}{d} = 500.0 kN
H=Hd+Hp=2500.0+500.0=3000.0 kNH = H_d + H_p = 2500.0 + 500.0 = 3000.0\ \text{kN}

Maximum and minimum tension

End slope: tan⁡θ=4d/L=0.40\tan\theta = 4d/L = 0.40, sec⁡θ=1.0770\sec\theta = 1.0770.

  • Maximum tension at the supports A and B: Tmax=Hsec⁡θ=3000.0(1.0770)=3231.10T_{max} = H\sec\theta = 3000.0(1.0770) = 3231.10 kN
  • Minimum tension at mid-span (crown, where the cable is horizontal): Tmin=H=3000.0T_{min} = H = 3000.0 kN

Length of the cable

Using l=L[1+83(dL)2−325(dL)4]l = L\left[1+\dfrac{8}{3}\left(\dfrac{d}{L}\right)^2-\dfrac{32}{5}\left(\dfrac{d}{L}\right)^4\right] with d/L=0.1d/L = 0.1:

l=100[1+83(0.1)2−325(0.1)4]=102.60 ml = 100\left[1 + \frac{8}{3}(0.1)^2 - \frac{32}{5}(0.1)^4\right] = 102.60\ \text{m}

Girder shear force and bending moment (per girder)

The dead load is carried wholly by the cable, so it produces no SF or BM in the girder. For the three loads, with y=0.004x(100−x)y = 0.004x(100-x) and HpH_p = 500 kN:

M=M0−Hp y,S=S0−Hp dydxM = M_0 - H_p\,y,\qquad S = S_0 - H_p\,\frac{dy}{dx}
  • 0≤x≤250 \le x \le 25: M=2x2−50xM = 2x^2 - 50x, S=4x−50S = 4x - 50
  • 25≤x≤5025 \le x \le 50: M=2x2−150x+2500M = 2x^2 - 150x + 2500, S=4x−150S = 4x - 150
  • The right half is the mirror image (SF with opposite sign).

So M=0M = 0 at the load points (0, 25, 50, 75, 100 m), and M=−312.5M = -312.5 kN m at 12.5 m, 37.5 m, 62.5 m and 87.5 m (the greatest hogging value). Shear force is −50-50 to +50+50 kN in each quarter, changing sign at the mid-point of each panel (a saw-tooth).

SFD (kN), +-50 in each quarter span
            *           *           *           *
          **          **          **          **
         *           *           *           *
       **          **          **          **
------*-----------*-----------*-----------*------
    **          **          **          **
   *           *           *           *
 **          **          **          **
*
(top = 50.0, bottom = -50.0; '-' is zero line)
BMD (kN m), all hogging, zero at the loads
*-----------*-----------*-----------*-----------*

 *         * *         * *         * *         *

  *       *   *       *   *       *   *       *

   *     *     *     *     *     *     *     *
    *   *       *   *       *   *       *   *
     ***         ***         ***         ***
(top = 0.0, bottom = -312.5; '-' is zero line)

Answer: Tmax=3231.10T_{max} = 3231.10 kN at the supports; Tmin=3000.0T_{min} = 3000.0 kN at the crown (mid-span); cable length = 102.60 m; girder Mmax=−312.5M_{max} = -312.5 kN m (hogging) at 12.5, 37.5, 62.5 and 87.5 m; Smax=50S_{max} = 50 kN.

✓ Answer checked by Claude Opus 5.5 (high effort)

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