- 2081 Bhadra · 8 marks
Design pipes AB and BC, 75 lpcd, tank 6 m high
Short answer
Pipe AB: 65 mm, residual head at B 26.9 m, velocity 1.04 m/s. Pipe BC: 40 mm, residual at C 8.4 m, velocity 0.99 m/s. Both meet minimum 5 m head, velocities acceptable.
Design pipes; AB and BC having 400 m and 500 m length respectively. Assume Hazen Williams coefficient C as 100 and maximum demand as 3 times the average demand. The average water consumption is 75 lpcd and population is distributed within the two blocks of 850 in AB section and 480 in BC section. The elevated storage tank is fixed at point A above 6 m height. The R.L. of points A, B and C are 2160, 2125 and 2115 meters respectively. The minimum pressure head of water is to be 5.0 m. Check velocity in the pipes also.
Data: C = 100, peak (maximum) demand = 3 × average, 75 lpcd, minimum residual head 5.0 m. The tank at A stands 6 m high, so the HGL at A = 2160 + 6 = 2166 m. The population of each section is taken as drawn at its end point (B for AB, C for BC), so pipe AB carries the demand of 850 + 480 = 1330 people and BC carries 480 people.
- lps
- lps
Method
Use the Hazen-Williams equation in SI units:
with in m³/s, and in m. For each pipe the available head is (HGL at upstream end − ground RL of the tap − required residual head). The gradient gives the calculated diameter, the next larger commercial size is adopted, and the real head loss and residual head are then checked. Commercial sizes (nominal bore): 15, 20, 25, 32, 40, 50, 65, 80, 100, 125, 150, 200 mm and so on. Constant C = 100.
Pipe AB
- Discharge lps, length m
- HGL at A = 2166.00 m; ground RL at B = 2125 m; residual head required = 5 m
- Available head m
- Gradient
- From : mm, adopt commercial size 65 mm
- Actual m, HGL at B = 2151.86 m, residual head = 26.86 m (≥ 5 m, OK)
- Velocity m/s
Pipe BC
- Discharge lps, length m
- HGL at B = 2151.86 m; ground RL at C = 2115 m; residual head required = 5 m
- Available head m
- Gradient
- From : mm, adopt commercial size 40 mm
- Actual m, HGL at C = 2123.37 m, residual head = 8.37 m (≥ 5 m, OK)
- Velocity m/s
Summary
| Pipe | Q (lps) | L (m) | Calc. D (mm) | Adopted D (mm) | h_f (m) | Residual (m) | v (m/s) |
|---|---|---|---|---|---|---|---|
| AB | 3.46354 | 400 | 53.7 | 65 | 14.14 | 26.86 | 1.04 |
| BC | 1.25 | 500 | 39.1 | 40 | 28.48 | 8.37 | 0.99 |
Velocities are between 0.6 m/s and 3 m/s, so the sizes are acceptable.
Answer: AB = 65 mm and BC = 40 mm; residual heads 26.9 m at B and 8.4 m at C (both more than 5 m); velocities 1.04 m/s and 0.99 m/s.
✓ Answer checked by Claude Opus 5.5 (high effort)
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