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Line coding 1001101101 (unipolar NRZ, polar RZ, AMI, Manchester)

Short answer

For 1001101101: Unipolar NRZ: 1→+V full bit, 0→0 V. Polar RZ: 1→+V half-bit then 0, 0→-V half-bit then 0. AMI: 0→0 V, 1s alternate +V,-V starting +V. Manchester: 1→+V then -V, 0→-V then +V, with mid-bit transition.

Represent given binary sequence 1001101101 in unipolar NRZ, polar RZ, AMI, and Manchester codes.

Bit sequence: 1 0 0 1 1 0 1 1 0 1, bit period TbT_b, levels ±V\pm V.

Unipolar NRZ

1 → +V for the full bit, 0 → 0 V.

Unipolar NRZ

    1   0   0   1   1   0   1   1   0   1  
+V ────|       |───────|   |───────|   |───
 0     |───────|       |───|       |───|   

Polar RZ

1 → +V for half the bit, 0 → −V for half the bit, then 0.

Polar RZ

    1   0   0   1   1   0   1   1   0   1  
+V ──|         |─| |─|     |─| |─|     |─| 
 0   |─| |─| |─| |─| |─| |─| |─| |─| |─| |─
-V     |─| |─|         |─|         |─|     

AMI

0 → 0 V. The 1s are half-width pulses of alternating polarity: + − + − + −.

AMI (RZ)

    1   0   0   1   1   0   1   1   0   1  
+V ──|             |─|         |─|         
 0   |─────────| |─| |─────| |─| |─────| |─
-V             |─|         |─|         |─| 

Manchester

1 → +V then −V, 0 → −V then +V. There is a transition at every mid-bit.

Manchester

    1   0   0   1   1   0   1   1   0   1  
+V ──|   |─| |───| |─|   |───| |─|   |───| 
-V   |───| |─|   |─| |───|   |─| |───|   |─

✓ Answer checked by Claude Opus 5.5 (high effort)

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