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- 2081 Baisakh (CS II) · 4 marks
Line coding 1101010111 (polar NRZ, polar RZ, Manchester, AMI)
Short answer
For 1101010111: Polar NRZ: 1→+V, 0→-V full bit. Polar RZ: 1→+V half-bit then 0, 0→-V half-bit then 0. Manchester: 1→+V then -V, 0→-V then +V. AMI: 0→0 V, 1s alternate +V,-V starting +V. Each code format described.
Given the binary sequence 1101010111 represent in polar NRZ, polar RZ, Manchester and AMI codes.
Line codes convert the bit stream into electrical pulses. Conventions used (bit period , amplitude ):
- Polar NRZ: 1 → , 0 → for the full bit.
- Polar RZ: 1 → , 0 → for the first half bit, then 0.
- Manchester: 1 → then (high-to-low at mid-bit); 0 → then .
- AMI: 0 → 0 V; successive 1s alternate , (first 1 taken as , full-width pulses).
Bit sequence: 1 1 0 1 0 1 0 1 1 1
bits 1 1 0 1 0 1 0 1 1 1
Polar NRZ:
+V |‾‾‾‾‾‾‾‾ ‾‾‾‾ ‾‾‾‾ ‾‾‾‾‾‾‾‾‾‾‾‾
0 |
-V | ____ ____ ____
Polar RZ:
+V |‾‾ ‾‾ ‾‾ ‾‾ ‾‾ ‾‾ ‾‾
0 | -- -- -- -- -- -- -- -- -- --
-V | __ __ __
Manchester:
+V |‾‾ ‾‾ ‾‾‾‾ ‾‾‾‾ ‾‾‾‾ ‾‾ ‾‾
0 |
-V | __ ____ ____ ____ __ __ __
AMI (bipolar NRZ):
+V |‾‾‾‾ ‾‾‾‾ ‾‾‾‾ ‾‾‾‾
0 | ---- ---- ----
-V | ____ ____ ____
Level in each bit (a pair means first half, second half):
| Code | 1 | 1 | 0 | 1 | 0 | 1 | 0 | 1 | 1 | 1 |
|---|---|---|---|---|---|---|---|---|---|---|
| Polar NRZ | +V | +V | −V | +V | −V | +V | −V | +V | +V | +V |
| Polar RZ | +V,0 | +V,0 | −V,0 | +V,0 | −V,0 | +V,0 | −V,0 | +V,0 | +V,0 | +V,0 |
| Manchester | +V,−V | +V,−V | −V,+V | +V,−V | −V,+V | +V,−V | −V,+V | +V,−V | +V,−V | +V,−V |
| AMI (bipolar NRZ) | +V | −V | 0 | +V | 0 | −V | 0 | +V | −V | +V |
Observations: polar NRZ has a DC component when 1s are more frequent (here seven 1s); Manchester has a transition in every bit, so it carries timing; AMI has zero average value because its marks alternate.
✓ Answer checked by Claude Opus 5.5 (high effort)
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