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Line coding 1101010011 (polar NRZ, polar RZ, Manchester, AMI)

Short answer

Polar NRZ: +V,+V,-V,+V,-V,+V,-V,-V,+V,+V. Polar RZ: +V0,+V0,-V0,+V0,-V0,+V0,-V0,-V0,+V0,+V0. Manchester: +V-V,+V-V,-V+V,+V-V,-V+V,+V-V,-V+V,-V+V,+V-V,+V-V. AMI: +V,-V,0,+V,0,-V,0,0,+V,-V.

Given the binary sequence 1101010011 represent in polar NRZ, polar RZ, Manchester and AMI codes.

Conventions (bit period TbT_b, amplitude VV):

  • Polar NRZ: 1 → +V+V, 0 → −V-V for the full bit.
  • Polar RZ: 1 → +V+V, 0 → −V-V for the first half, then 0.
  • Manchester: 1 → +V+V then −V-V; 0 → −V-V then +V+V.
  • AMI: 0 → 0; 1s alternate +V+V, −V-V (first 1 positive).

Bit sequence: 1 1 0 1 0 1 0 0 1 1

bits  1   1   0   1   0   1   0   0   1   1  

Polar NRZ:
+V  |‾‾‾‾‾‾‾‾    ‾‾‾‾    ‾‾‾‾        ‾‾‾‾‾‾‾‾
 0  |
-V  |        ____    ____    ________

Polar RZ:
+V  |‾‾  ‾‾      ‾‾      ‾‾          ‾‾  ‾‾
 0  |  --  --  --  --  --  --  --  --  --  --
-V  |        __      __      __  __

Manchester:
+V  |‾‾  ‾‾    ‾‾‾‾    ‾‾‾‾    ‾‾  ‾‾‾‾  ‾‾
 0  |
-V  |  __  ____    ____    ____  __    __  __

AMI (bipolar NRZ):
+V  |‾‾‾‾        ‾‾‾‾                ‾‾‾‾
 0  |        ----    ----    --------
-V  |    ____            ____            ____

Levels in each bit (a pair means first half, second half):

Code1101010011
Polar NRZ+V+V−V+V−V+V−V−V+V+V
Polar RZ+V,0+V,0−V,0+V,0−V,0+V,0−V,0−V,0+V,0+V,0
Manchester+V,−V+V,−V−V,+V+V,−V−V,+V+V,−V−V,+V−V,+V+V,−V+V,−V
AMI (bipolar NRZ)+V−V0+V0−V00+V−V

Manchester and polar RZ have a transition in every bit (good timing), while AMI has zero average value because its marks alternate.

✓ Answer checked by Claude Opus 5.5 (high effort)

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