- Asked 2/18
- 2070 Magh · 8 marks
Pelton turbine design (1.8 m³/s, 605 m)
Short answer
Single-jet Pelton wheel: power 9.29 MW at 500 rpm (12 poles). Jet diameter 147 mm, pitch circle diameter 1.91 m, jet ratio 13.07. Specific speed 16.1. 22 buckets; bucket width 0.73 m, depth 0.18 m.
Design a pelton turbine with following data: Overall efficiency = 87%, Discharge (Qd) = 1.8 m³/s, Net head (H) = 605 m.
A Pelton wheel is designed by finding the jet velocity and jet diameter, choosing a synchronous speed that gives a suitable jet ratio (10 to 14 for good efficiency), and then sizing the wheel and buckets. Of the two nearest synchronous speeds (500 and 600 rpm), 500 rpm is chosen because it gives a jet ratio nearer 12.
Data: m³/s, m, , Hz. Assumed from the standard ranges: (0.97 to 0.99) and speed ratio (0.43 to 0.47).
1. Power developed
2. Jet velocity and bucket (peripheral) velocity
3. Jet diameter (single jet)
4. Speed of the wheel
Trial with jet ratio : m, so
Nearest synchronous speed for 50 Hz: rpm (12 poles).
5. Wheel (pitch circle) diameter and jet ratio
lies within 10 to 14, so a single-jet wheel is satisfactory.
6. Specific speed check
This is within the single-jet Pelton range (about 8.5 to 30), so the Pelton wheel is the correct choice.
7. Number of buckets (Tygun's formula)
8. Bucket size (usual proportions)
- Bucket width m
- Bucket depth m
- Bucket radial length m
Summary of design
| Item | Value |
|---|---|
| Power | 9.29 MW |
| Speed | 500 rpm |
| Number of jets | 1 |
| Jet diameter | 147 mm |
| Wheel diameter | 1.91 m |
| Jet ratio | 13.07 |
| Specific speed | 16.1 |
| Number of buckets | 22 |
| Bucket width × depth | 0.73 m × 0.18 m |
✓ Answer checked by Claude Opus 5.5 (high effort)
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