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Guide bank and launching apron, 5000 m3/s

Short answer

Lacey waterway W=336m. Upstream length 420m, downstream 84m, curved head radius 168m (120°). Pitching thickness 1.03m. Normal scour R=8.39m. Apron at shank: length 12.87m, launched thickness 1.54m (laid 2.29m). At nose: length 19.16m, same thickness.

A bridge is to be constructed across a river having the following hydraulic data: Maximum flood Discharge: 5000 m³/s; Highest flood level: 254.0 m; River bed level: 250 m; Average diameter of river sand: 0.25 m. Design and sketch a guide bank including launching apron to train the river.

Data and design basis

  • The average size of the river sand is taken as 0.25 mm (0.25 m would not be sand).
  • Silt factor (Lacey): f=1.76dmm=1.760.25=0.88f = 1.76\sqrt{d_{mm}} = 1.76\sqrt{0.25} = 0.88
  • Flood depth above bed: h=254−250=4.00h = 254 - 250 = 4.00 m
  • Design discharge for scour/apron: Q=5000Q = 5000 m³/s

1. Waterway and length of guide bund

Lacey's regime waterway: W=4.75Q=4.755000=335.88W = 4.75\sqrt{Q} = 4.75\sqrt{5000} = 335.88 m. Adopt W≈336W \approx 336 m. Length of guide bund (Garg): upstream shank =1.0=1.0 to 1.5 W1.5\,W, downstream tail =0.2=0.2 to 0.5 W0.5\,W. Adopt

Lus=1.25W=1.25×336=420 mLds=0.25W=84 m\begin{aligned} L_{us} &= 1.25W = 1.25\times 336 = 420\ \text{m} \\ L_{ds} &= 0.25W = 84\ \text{m} \end{aligned}

Curved heads: upstream radius Ru≈0.5W=168R_u \approx 0.5W = 168 m with sweep 120∘120^\circ to 145∘145^\circ (adopt 120∘120^\circ); downstream radius Rd≈0.25W=84R_d \approx 0.25W = 84 m with sweep about 45∘45^\circ. Arc length of upstream head =Ruθ=168×2.094=352= R_u\theta = 168\times 2.094 = 352 m, so total length on the upstream side ≈772\approx 772 m.

2. Thickness of stone pitching

t=0.06 Q1/3=0.06×50001/3=0.06×17.10=1.03 mt = 0.06\,Q^{1/3} = 0.06\times 5000^{1/3} = 0.06\times 17.10 = 1.03\ \text{m}

Adopt t≈1.1t \approx 1.1 m (pitching on the river side slope 2:1, over a 0.15 to 0.3 m graded filter).

3. Scour depth and launching apron

Lacey's normal scour depth:

R=0.47(Qf)1/3=0.47(50000.88)1/3=8.39 mR = 0.47\left(\frac{Q}{f}\right)^{1/3} = 0.47\left(\frac{5000}{0.88}\right)^{1/3} = 8.39\ \text{m}

Maximum scour below HFL: 2R2R at the upstream nose, 1.5R1.5R at the shank (straight portion). The apron must launch to the slope 2H:1V2H:1V, so its horizontal width is 1.5D′1.5D' and, when launched, it covers a slope length 5 D′\sqrt5\,D' with thickness 1.5t1.5t.

PortionScour factorScour depth below HFLDepth below bed D′D'Apron length 1.5D′1.5D'
Nose (u/s curved head)2.0R16.77 m12.77 m19.16 m
Shank (straight)1.5R12.58 m8.58 m12.87 m

Thickness: pitching t=1.03t = 1.03 m, so the launched apron thickness is 1.5t=1.5×1.03=1.541.5t = 1.5\times1.03 = 1.54 m. Equating volumes per metre, the thickness as laid over 1.5D′1.5D' width is T=1.5t×5D′1.5D′=5 t=2.29T = \dfrac{1.5t\times\sqrt5 D'}{1.5D'} = \sqrt5\,t = 2.29 m (about 2.25t2.25t).

Summary

ItemValue
Lacey waterway WW335.88 m (adopt 336 m)
Length of guide bund (u/s)420 m; d/s tail 84 m
Pitching thickness tt1.03 m
Apron at shank: width 1.5D′1.5D' / thickness12.87 m / 1.54 m launched (2.29 m laid)
Apron at nose: width / thickness19.16 m / 1.54 m launched (2.29 m laid)

Sketches

Plan of guide bunds:

 U/S                                          D/S
                       bridge / weir axis
   Shank (straight)                |
 ________________________________  |  ___
/  1.0-1.5 W upstream            \ | /   \  tail
\________________________________/=|=\___/  0.25 W
 curved head                       |
 R, sweep 120 deg    <-- waterway W -->
 ________________________________  |  ___
/                                \ | /   \
\________________________________/=|=\___/

Section at the shank (straight portion):

           top width 6 m
         ___________  <- HFL + 1.5 m
        /           \
 HFL ---/-------------\---  2:1 slopes
       / pitching t    \
 bed__/__ filter ______ \___
      \_ launching apron _/ (launches at 2:1)

✓ Answer checked by Claude Opus 5.5 (high effort)

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