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Launching apron, 6000 m3/s, HFL 330 m

Short answer

Lacey silt factor f=1.76, normal scour R=7.07m. For straight portion, scour below bed D'=6.61m. Launching apron horizontal length 1.5D'=9.92m. Launched thickness 1.5t=1.64m (t=1.09m), laid thickness √5 t=2.44m.

Determine the length and thickness of launching apron for the straight portion of a guide bund in a river for the following data given below. Max. discharge = 6000 m³/s, Average dia. of bed material = 1.0 mm, Highest flood level (HFL) = 330 m and River bed level = 326 m.

Data and design basis

  • Silt factor (Lacey): f=1.76dmm=1.761.0=1.76f = 1.76\sqrt{d_{mm}} = 1.76\sqrt{1.0} = 1.76
  • Flood depth above bed: h=330−326=4.00h = 330 - 326 = 4.00 m
  • Design discharge for scour/apron: Q=6000Q = 6000 m³/s

1. Pitching thickness

t=0.06 Q1/3=0.06×60001/3=0.06×18.17=1.09 mt = 0.06\,Q^{1/3} = 0.06\times 6000^{1/3} = 0.06\times 18.17 = 1.09\ \text{m}

2. Scour depth and launching apron

Lacey's normal scour depth:

R=0.47(Qf)1/3=0.47(60001.76)1/3=7.07 mR = 0.47\left(\frac{Q}{f}\right)^{1/3} = 0.47\left(\frac{6000}{1.76}\right)^{1/3} = 7.07\ \text{m}

Maximum scour below HFL: 2R2R at the upstream nose, 1.5R1.5R at the shank (straight portion). The apron must launch to the slope 2H:1V2H:1V, so its horizontal width is 1.5D′1.5D' and, when launched, it covers a slope length 5 D′\sqrt5\,D' with thickness 1.5t1.5t.

PortionScour factorScour depth below HFLDepth below bed D′D'Apron length 1.5D′1.5D'
Shank (straight)1.5R10.61 m6.61 m9.92 m

Thickness: pitching t=1.09t = 1.09 m, so the launched apron thickness is 1.5t=1.5×1.09=1.641.5t = 1.5\times1.09 = 1.64 m. Equating volumes per metre, the thickness as laid over 1.5D′1.5D' width is T=1.5t×5D′1.5D′=5 t=2.44T = \dfrac{1.5t\times\sqrt5 D'}{1.5D'} = \sqrt5\,t = 2.44 m (about 2.25t2.25t).

Answer (straight portion): length of launching apron =1.5D′=9.92=1.5D' = 9.92 m (horizontal), thickness =1.5t=1.64=1.5t = 1.64 m when launched (about 2.44 m as laid).

✓ Answer checked by Claude Opus 5.5 (high effort)

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