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Chapter 6 · 4 hours

River Training Works

IOE past exam questions

Past questions and answers

33 questions set from this chapter, 7 of them more than once; 8 are most repeated (set, or a close variant set, in 3 or more exams). Most repeated first.

  • Most repeated · 6 of 34 exams
  • Asked 6 times
  • 2073 Magh · 8 marks
  • 2079 Jestha · 4 marks
  • 2080 Chaitra · 6 marks
  • 2073 Bhadra · 2×4 marks
  • 2063 Baisakh (old course) · 8 marks
  • 2078 Poush · 3 marks

What is river training works? Explain with sketches the different methods (types) of river training works normally adopted in Nepalese rivers (Terai region).

Answer

River training works are structures built on or along a river to guide and confine the flow, control its erosion and deposition, and keep it in a stable course so that bridges, headworks, towns and farmland are protected. Rivers of the Nepal Terai (Koshi, Narayani, Bagmati, Karnali) are steep, braided and carry heavy bed load from the Churia hills, so they need training works.

Objectives

  • Prevent floods and spilling over the banks.
  • Protect banks from erosion and the river from shifting its course (flanking a bridge or barrage).
  • Give a steady, axial approach flow to a structure.
  • Control silt entry and maintain a navigable or regular channel.

Methods normally adopted in the Terai

1. Guide bunds (guide banks) are embankments built on both sides of the river upstream (and a short length downstream) of a bridge or barrage, to guide flow centrally through the opening.

 flow --->      ____ guide bund (curved head)
 ______________/    \______
                   waterway W      = bridge/barrage
 ______________    ______/
               \____/

2. Spurs (groynes) project from the bank into the river to push the current away from the bank, create slack water and cause silt to settle between them. They protect concave banks.

  bank ======+==+==+==+====
             |  |  |  |      spurs (L)
             v  v  v  v      current deflected away

3. Marginal (flood) embankments are earth levees along the river, set back from the bank, which confine the flood within the river corridor.

4. Bank protection (revetment / pitching) covers the bank with stone pitching, concrete blocks or gabion mattresses over a filter, with a launching apron at the toe.

5. Cut-offs are artificial channels across the neck of a meander that straighten the river and lower flood levels.

6. Check dams / bed sills and gabion crate walls control bed degradation in steep tributaries.

7. Bio-engineering (vegetative spurs, bamboo piles, planting of grass and trees) is used as a cheap supplement along banks.

8. Pitched islands and training walls are used where the river must be held in one channel.

Selection depends on river slope, bed material, flood discharge and cost; in practice a combination (embankment, spurs and gabion revetment) is used.

  • Most repeated · 4 of 34 exams
  • Asked 4 times
  • 2065 Kartik (old course) · 4 marks
  • 2072 Asoj · 3 marks
  • 2074 Bhadra · 3 marks
  • 2065 Shrawan (old course) · 3 marks

Explain with sketches how spurs assist in river control work, their functions, types and layout to train the river in a bend.

Answer

A spur (groyne) is an embankment-type structure built out from the bank into the river, at an angle to the flow, to protect the bank and train the river in a bend.

How spurs assist river control

  • The current is turned away from the concave (eroding) bank toward the centre of the river.
  • Behind the spur, velocity is low and silt settles, building a new bank (land reclamation).
  • The river is narrowed to a desired width and the thalweg is held in the channel centre.

Functions

  1. Protect the bank from erosion and prevent flanking of embankments.
  2. Contract the river and improve the navigable or approach channel.
  3. Induce silting (sedimenting) and create a new bank line.
  4. Guide the river toward the entrance of a structure.

Types

TypeInclination to flowEffect
Repelling (inclined upstream, 100 to 120° with bank)Points upstreamStrongly repels current; sets up deep scour at head
Attracting (inclined downstream, 60 to 70°)Points downstreamAttracts flow; low scour; less protective
Deflecting/neutral (perpendicular, 90°)Right angleModerate effect; most common
T-head / hockey-headT-shaped headReduces scour at head; wider protection
Permeable (piles, wire crates)Slows flowSilting
Impermeable (earth, stone, gabion)Blocks flowDeflection

Layout in a bend

 convex bank (silting)
        .  .  .
 -----------------------------
    flow ->     (centre line)
 -----------------------------
 | | | | |   concave bank: spurs at spacing S
 v v v v v   spur length L, pointing slightly upstream
  • Spurs are placed on the concave bank, starting upstream of the eroding reach and ending where the bank is stable.
  • Spacing is about 2 to 2.5 times the spur length (S≈2S \approx 2 to 2.5L2.5L) on a concave bank, more on straight reaches.
  • Length is limited to about 20 % of the river width so the channel is not choked.
  • Heads are well protected with stone pitching and a launching apron; the root is anchored into the bank.
  • Most repeated · 4 of 34 exams
  • Asked 4 times
  • 2070 Chaitra (old course) · 4 marks
  • 2065 Shrawan (old course) · 3 marks
  • 2063 Asoj (old course) · 4 marks
  • 2062 Baisakh (old course) · 4 marks

Explain the different (structural) methods of flood control measures.

Answer

Flood control aims to reduce the damage from floods by storing, diverting, confining or reducing flood flow. The structural methods are as follows.

1. Storage reservoirs

A dam stores flood water and releases it gradually, cutting the peak flow downstream. It is the most effective method but costly. Used on the Koshi, Karnali and Sapta Gandaki river systems of Nepal in the planning stage.

2. Detention basins and retarding basins

Low-lying areas or small ponds hold flood water temporarily.

3. Embankments (levees or dykes)

Earth banks built along the river confine the flood and prevent spilling. The flood level rises inside the embankments, so they must be raised periodically and have free-board.

   ____ levee               levee ____
  /    \_______ river _______/    \
 /  flood plain protected          \

4. Channel improvement

Straightening, widening, deepening, desilting or removal of obstacles raise the carrying capacity and lower flood levels.

5. Cut-offs

A shortcut across a meander neck steepens the slope and lowers flood levels upstream.

6. Diversion and flood-ways

Excess flood is diverted to a side channel, lake or another basin through a spillway or gated weir.

7. Bank protection and river training

Spurs, revetments and guide bunds protect banks and hold the river in its course.

8. Watershed management

Afforestation, check dams and terracing in the catchment cut run-off and sediment.

9. Flood proofing and warning

Raised platforms, flood warning systems and zoning of the flood plain reduce damage to people and property (non-structural, but used with the above).

  • Most repeated · 3 of 34 exams
  • Asked 3 times
  • 2070 Chaitra (old course) · 4 marks
  • 2064 Kartik (old course) · 4 marks
  • 2076 Bhadra · 4 marks

Explain different stages of rivers (and their characteristics along the flow path, including the meandering process).

Answer

A river changes character along its course from the hills to the sea. Three stages are recognised.

Stages of a river

StageLocationSlopeCharacteristics
Mountain (youth)Upper reach, in the hillsVery steepNarrow V-valley, high velocity, boulders and gravel, strong erosion, rapids and waterfalls; bed degrades
Valley or foot-hill (mature)Piedmont zone (Churia and Bhabar)ModerateGravel and sand bed, braided channels, aggrading bed, wide shifting channel, heavy bed load
Plain or delta (old)Terai plain and deltaFlatFine silt, low velocity, meanders, flood plain, branching distributaries in the delta; deposition dominates

In the Terai, rivers leaving the Churia hills spill into the plain where slope falls suddenly, so their load is dropped and they braid and shift.

Meandering process

A meander is a bend that develops in an alluvial channel in a flat reach. It forms by this sequence:

  1. Small irregularities cause the flow to attack one bank, creating a bend.
  2. In the bend, a transverse (helical) flow develops. The surface water moves toward the outer (concave) bank and bottom water toward the inner (convex) bank.
  3. The outer bank erodes and the inner bank gets silt deposits, so the bend grows in amplitude.
  4. The meander migrates downstream. Pools form on the outer side and riffles (shoals) in the crossings.
  5. Eventually the neck narrows; in flood the river cuts across it (natural cut-off), leaving an oxbow lake.
      outer bank erodes
   ______      ______
  /      \____/      \___   -->
         inner bank deposits

Meandering is controlled by guide bunds, spurs and bank protection on the concave side.

  • Most repeated · 3 of 34 exams
  • Asked 3 times
  • 2075 Bhadra · 8 marks
  • 2075 Baisakh · 8 marks
  • 2064 Jestha (old course) · 8 marks

Neatly sketch a guide bund and design the following components of a guide bund for a river discharge of 4000 m³/s, flood height 5.0 m and silt factor 1.1: (i) length of guide bund (ii) thickness of pitching (iii) width of launching apron (iv) depth of launching apron.

Answer

Data and design basis

  • Silt factor given: f=1.10f = 1.10
  • Flood depth: h=5.00h = 5.00 m
  • Design discharge for scour/apron: Q=4000Q = 4000 m³/s

1. Waterway and length of guide bund

Lacey's regime waterway: W=4.75Q=4.754000=300.42W = 4.75\sqrt{Q} = 4.75\sqrt{4000} = 300.42 m. Adopt W≈300W \approx 300 m. Length of guide bund (Garg): upstream shank =1.0=1.0 to 1.5 W1.5\,W, downstream tail =0.2=0.2 to 0.5 W0.5\,W. Adopt

Lus=1.25W=1.25×300=375 mLds=0.25W=75 m\begin{aligned} L_{us} &= 1.25W = 1.25\times 300 = 375\ \text{m} \\ L_{ds} &= 0.25W = 75\ \text{m} \end{aligned}

Curved heads: upstream radius Ru≈0.5W=150R_u \approx 0.5W = 150 m with sweep 120∘120^\circ to 145∘145^\circ (adopt 120∘120^\circ); downstream radius Rd≈0.25W=75R_d \approx 0.25W = 75 m with sweep about 45∘45^\circ. Arc length of upstream head =Ruθ=150×2.094=314= R_u\theta = 150\times 2.094 = 314 m, so total length on the upstream side ≈689\approx 689 m.

2. Thickness of stone pitching

t=0.06 Q1/3=0.06×40001/3=0.06×15.87=0.95 mt = 0.06\,Q^{1/3} = 0.06\times 4000^{1/3} = 0.06\times 15.87 = 0.95\ \text{m}

Adopt t≈1.0t \approx 1.0 m (pitching on the river side slope 2:1, over a 0.15 to 0.3 m graded filter).

3. Scour depth and launching apron

Lacey's normal scour depth:

R=0.47(Qf)1/3=0.47(40001.10)1/3=7.23 mR = 0.47\left(\frac{Q}{f}\right)^{1/3} = 0.47\left(\frac{4000}{1.10}\right)^{1/3} = 7.23\ \text{m}

Maximum scour below HFL: 2R2R at the upstream nose, 1.5R1.5R at the shank (straight portion). The apron must launch to the slope 2H:1V2H:1V, so its horizontal width is 1.5D′1.5D' and, when launched, it covers a slope length 5 D′\sqrt5\,D' with thickness 1.5t1.5t.

PortionScour factorScour depth below HFLDepth below bed D′D'Apron length 1.5D′1.5D'
Nose (u/s curved head)2.0R14.45 m9.45 m14.18 m
Shank (straight)1.5R10.84 m5.84 m8.76 m

Thickness: pitching t=0.95t = 0.95 m, so the launched apron thickness is 1.5t=1.5×0.95=1.431.5t = 1.5\times0.95 = 1.43 m. Equating volumes per metre, the thickness as laid over 1.5D′1.5D' width is T=1.5t×5D′1.5D′=5 t=2.13T = \dfrac{1.5t\times\sqrt5 D'}{1.5D'} = \sqrt5\,t = 2.13 m (about 2.25t2.25t).

Summary

ItemValue
Lacey waterway WW300.42 m (adopt 300 m)
Length of guide bund (u/s)375 m; d/s tail 75 m
Pitching thickness tt0.95 m
Apron at shank: width 1.5D′1.5D' / thickness8.76 m / 1.43 m launched (2.13 m laid)
Apron at nose: width / thickness14.18 m / 1.43 m launched (2.13 m laid)

Sketches

Plan of guide bunds:

 U/S                                          D/S
                       bridge / weir axis
   Shank (straight)                |
 ________________________________  |  ___
/  1.0-1.5 W upstream            \ | /   \  tail
\________________________________/=|=\___/  0.25 W
 curved head                       |
 R, sweep 120 deg    <-- waterway W -->
 ________________________________  |  ___
/                                \ | /   \
\________________________________/=|=\___/

Section at the shank (straight portion):

           top width 6 m
         ___________  <- HFL + 1.5 m
        /           \
 HFL ---/-------------\---  2:1 slopes
       / pitching t    \
 bed__/__ filter ______ \___
      \_ launching apron _/ (launches at 2:1)
  • Most repeated · 3 of 34 exams
  • 2064 Kartik (old course) · 8 marks

Determine the length and thickness of launching apron for the straight portion of a guide bund in a river: Design flood = 5000 m³/s; av. dia. of bed material = 1 mm; HFL = 225.00 m; River bed level = 222.00 m.

Similar questions: Launching apron, 8000 m3/s, HFL 128.5 m (2062 Kartik (old course)) · Launching apron, 7000 m3/s, HFL 114 m (2063 Baisakh (old course))

Answer

Data and design basis

  • Silt factor (Lacey): f=1.76dmm=1.761.0=1.76f = 1.76\sqrt{d_{mm}} = 1.76\sqrt{1.0} = 1.76
  • Flood depth above bed: h=225.0−222.0=3.00h = 225.0 - 222.0 = 3.00 m
  • Design discharge for scour/apron: Q=5000Q = 5000 m³/s

1. Scour depth and launching apron

Lacey's normal scour depth:

R=0.47(Qf)1/3=0.47(50001.76)1/3=6.66 mR = 0.47\left(\frac{Q}{f}\right)^{1/3} = 0.47\left(\frac{5000}{1.76}\right)^{1/3} = 6.66\ \text{m}

Maximum scour below HFL: 2R2R at the upstream nose, 1.5R1.5R at the shank (straight portion). The apron must launch to the slope 2H:1V2H:1V, so its horizontal width is 1.5D′1.5D' and, when launched, it covers a slope length 5 D′\sqrt5\,D' with thickness 1.5t1.5t.

PortionScour factorScour depth below HFLDepth below bed D′D'Apron length 1.5D′1.5D'
Shank (straight)1.5R9.98 m6.98 m10.48 m

Thickness: pitching t=1.03t = 1.03 m, so the launched apron thickness is 1.5t=1.5×1.03=1.541.5t = 1.5\times1.03 = 1.54 m. Equating volumes per metre, the thickness as laid over 1.5D′1.5D' width is T=1.5t×5D′1.5D′=5 t=2.29T = \dfrac{1.5t\times\sqrt5 D'}{1.5D'} = \sqrt5\,t = 2.29 m (about 2.25t2.25t).

Answer (straight portion): length of launching apron =1.5D′=10.48=1.5D' = 10.48 m, thickness =1.5t=1.54=1.5t = 1.54 m launched (about 2.29 m as laid).

  • Most repeated · 3 of 34 exams
  • 2063 Baisakh (old course) · 8 marks

Design the length and thickness of launching apron for the straight portion of a guide bund in a river: Design flood = 7000 m³/s; Average diameter of river bed material = 1 mm; River bed level = 111.00; HFL = 114.00. Provide a neat sketch of designed apron.

Similar questions: Launching apron, 8000 m3/s, HFL 128.5 m (2062 Kartik (old course)) · Launching apron, 5000 m3/s, HFL 225 m (2064 Kartik (old course))

Answer

Data and design basis

  • Silt factor (Lacey): f=1.76dmm=1.761.0=1.76f = 1.76\sqrt{d_{mm}} = 1.76\sqrt{1.0} = 1.76
  • Flood depth above bed: h=114.0−111.0=3.00h = 114.0 - 111.0 = 3.00 m
  • Design discharge for scour/apron: Q=7000Q = 7000 m³/s

1. Scour depth and launching apron

Lacey's normal scour depth:

R=0.47(Qf)1/3=0.47(70001.76)1/3=7.45 mR = 0.47\left(\frac{Q}{f}\right)^{1/3} = 0.47\left(\frac{7000}{1.76}\right)^{1/3} = 7.45\ \text{m}

Maximum scour below HFL: 2R2R at the upstream nose, 1.5R1.5R at the shank (straight portion). The apron must launch to the slope 2H:1V2H:1V, so its horizontal width is 1.5D′1.5D' and, when launched, it covers a slope length 5 D′\sqrt5\,D' with thickness 1.5t1.5t.

PortionScour factorScour depth below HFLDepth below bed D′D'Apron length 1.5D′1.5D'
Shank (straight)1.5R11.17 m8.17 m12.25 m

Thickness: pitching t=1.15t = 1.15 m, so the launched apron thickness is 1.5t=1.5×1.15=1.721.5t = 1.5\times1.15 = 1.72 m. Equating volumes per metre, the thickness as laid over 1.5D′1.5D' width is T=1.5t×5D′1.5D′=5 t=2.57T = \dfrac{1.5t\times\sqrt5 D'}{1.5D'} = \sqrt5\,t = 2.57 m (about 2.25t2.25t).

Answer (straight portion): length of launching apron =1.5D′=12.25=1.5D' = 12.25 m, thickness =1.5t=1.72=1.5t = 1.72 m launched (about 2.57 m as laid).

        pitching
   ____/\__ 
  /\ apron laid: width 1.5D', T = 2.24 t
 bed ___________ river bed
   after launching: 2:1 slope, 1.5 t thick
  • Most repeated · 3 of 34 exams
  • 2062 Kartik (old course) · 8 marks

Determine the length and thickness of launching apron for the straight portion of a guide bund in a river. Design flood = 8,000 m³/s; average diameter of river bed material = 1 mm; river bed level = 125.00; highest flood level = 128.50.

Similar questions: Launching apron, 7000 m3/s, HFL 114 m (2063 Baisakh (old course)) · Launching apron, 5000 m3/s, HFL 225 m (2064 Kartik (old course))

Answer

Data and design basis

  • Silt factor (Lacey): f=1.76dmm=1.761.0=1.76f = 1.76\sqrt{d_{mm}} = 1.76\sqrt{1.0} = 1.76
  • Flood depth above bed: h=128.5−125.0=3.50h = 128.5 - 125.0 = 3.50 m
  • Design discharge for scour/apron: Q=8000Q = 8000 m³/s

1. Scour depth and launching apron

Lacey's normal scour depth:

R=0.47(Qf)1/3=0.47(80001.76)1/3=7.79 mR = 0.47\left(\frac{Q}{f}\right)^{1/3} = 0.47\left(\frac{8000}{1.76}\right)^{1/3} = 7.79\ \text{m}

Maximum scour below HFL: 2R2R at the upstream nose, 1.5R1.5R at the shank (straight portion). The apron must launch to the slope 2H:1V2H:1V, so its horizontal width is 1.5D′1.5D' and, when launched, it covers a slope length 5 D′\sqrt5\,D' with thickness 1.5t1.5t.

PortionScour factorScour depth below HFLDepth below bed D′D'Apron length 1.5D′1.5D'
Shank (straight)1.5R11.68 m8.18 m12.27 m

Thickness: pitching t=1.20t = 1.20 m, so the launched apron thickness is 1.5t=1.5×1.20=1.801.5t = 1.5\times1.20 = 1.80 m. Equating volumes per metre, the thickness as laid over 1.5D′1.5D' width is T=1.5t×5D′1.5D′=5 t=2.68T = \dfrac{1.5t\times\sqrt5 D'}{1.5D'} = \sqrt5\,t = 2.68 m (about 2.25t2.25t).

Answer (straight portion): length of launching apron =1.5D′=12.27=1.5D' = 12.27 m, thickness =1.5t=1.80=1.5t = 1.80 m launched (about 2.68 m as laid).

  • Asked 2 times
  • 2065 Kartik (old course) · 2+8 marks
  • 2063 Asoj (old course) · 8 marks

What are the purposes of guide bunds? Explain with plan and sectional views at critical locations design of components of guide bunds (design criteria).

Answer

A guide bund is a pair of embankments, built along both banks upstream (and a short length downstream) of a bridge or barrage, which guide the river through the opening without allowing it to outflank the structure.

Purposes

  1. Confine and guide the river axially through the waterway.
  2. Prevent the river from attacking the approach embankments and abutments (flanking).
  3. Prevent the formation of eddies and cross-currents near the structure.
  4. Keep the scour holes and deposits away from the structure.
  5. Maintain a smooth, symmetrical entry of flow, so the afflux is minimum.

Design criteria (Lacey and Garg)

Plan

  • Waterway W=4.75QW = 4.75\sqrt{Q}.
  • Length of upstream shank: 1.01.0 to 1.5 W1.5\,W; downstream tail: 0.20.2 to 0.5 W0.5\,W.
  • Upstream curved head: radius about 0.5W0.5W and sweep 120∘120^\circ to 145∘145^\circ; downstream curved head: smaller radius, sweep about 45∘45^\circ.
 U/S                                 D/S
   ___________________________  |  ____
  /  shank 1.0-1.5 W           \ | /    \ tail
  \____________________________/=|=\____/ 0.2-0.5 W
  curved head                     axis
        <------ waterway W ------>

Cross-section at the shank

  • Top width 6 m (3 to 6 m) and top level == HFL ++ 1.5 m free-board.
  • Side slopes 2:1 on the river side (pitched) and 2:1 on the country side.
  • Pitching thickness t=0.06 Q1/3t = 0.06\,Q^{1/3} on a filter 0.15 to 0.30 m thick.

Launching apron

  • Scour depth R=0.47(Q/f)1/3R = 0.47(Q/f)^{1/3}; maximum scour below HFL is 2R2R at the nose and 1.5R1.5R at the shank.
  • Depth of apron below bed D′=D' = (scour below HFL) −- (flood depth).
  • Width =1.5D′= 1.5D' and thickness =1.5t= 1.5t when launched on a 2:1 slope (laid thickness about 2.25t2.25t).
 Section at shank                 Section at nose
      ____6 m___                      ___6 m___
     /          \ HFL+1.5            /         \
 HFL/____________\                 HFL/___________\
   / pitching t   \                  /             \
 _/_______apron____\_             _/____apron 2R_____\_

At the nose the scour is deeper (2R), so the pitching continues around the head and the apron is wider and thicker; sections are flatter (3:1) at the head.

  • Asked 2 times
  • 2079 Jestha · 5 marks
  • 2076 Baisakh · 8 marks

Write down the design steps of the guide bund (guide bank) with a suitable sketch / example.

Answer

The design of a guide bund (guide bank) follows Lacey's regime theory and Garg's recommendations. The steps are listed first and then worked for an example.

Design steps

  1. Find the design discharge QQ, HFL, bed level, bed material size dd.
  2. Silt factor f=1.76dmmf = 1.76\sqrt{d_{mm}}.
  3. Waterway W=4.75QW = 4.75\sqrt{Q}.
  4. Length: upstream shank =1.0= 1.0 to 1.5W1.5W, downstream =0.2= 0.2 to 0.5W0.5W.
  5. Curved heads: radius and sweep angle.
  6. Top level == HFL +1.5+ 1.5 m (free-board); top width 6 m; side slopes 2:1.
  7. Pitching thickness t=0.06 Q1/3t = 0.06\,Q^{1/3}.
  8. Scour depth R=0.47(Q/f)1/3R = 0.47(Q/f)^{1/3}; maximum scour 2R2R (nose), 1.5R1.5R (shank) below HFL.
  9. Apron: D′=D' = scour −- flood depth; width 1.5D′1.5D'; thickness 1.5t1.5t (launched).
  10. Draw plan and sections.

Example

Q=5000Q = 5000 m³/s, bed material d=1d = 1 mm, HFL =100.0= 100.0 m, bed =96.0= 96.0 m.

1. Waterway and length of guide bund

Lacey's regime waterway: W=4.75Q=4.755000=335.88W = 4.75\sqrt{Q} = 4.75\sqrt{5000} = 335.88 m. Adopt W≈336W \approx 336 m. Length of guide bund (Garg): upstream shank =1.0=1.0 to 1.5 W1.5\,W, downstream tail =0.2=0.2 to 0.5 W0.5\,W. Adopt

Lus=1.25W=1.25×336=420 mLds=0.25W=84 m\begin{aligned} L_{us} &= 1.25W = 1.25\times 336 = 420\ \text{m} \\ L_{ds} &= 0.25W = 84\ \text{m} \end{aligned}

Curved heads: upstream radius Ru≈0.5W=168R_u \approx 0.5W = 168 m with sweep 120∘120^\circ to 145∘145^\circ (adopt 120∘120^\circ); downstream radius Rd≈0.25W=84R_d \approx 0.25W = 84 m with sweep about 45∘45^\circ. Arc length of upstream head =Ruθ=168×2.094=352= R_u\theta = 168\times 2.094 = 352 m, so total length on the upstream side ≈772\approx 772 m.

2. Thickness of stone pitching

t=0.06 Q1/3=0.06×50001/3=0.06×17.10=1.03 mt = 0.06\,Q^{1/3} = 0.06\times 5000^{1/3} = 0.06\times 17.10 = 1.03\ \text{m}

Adopt t≈1.1t \approx 1.1 m (pitching on the river side slope 2:1, over a 0.15 to 0.3 m graded filter).

3. Scour depth and launching apron

Lacey's normal scour depth:

R=0.47(Qf)1/3=0.47(50001.76)1/3=6.66 mR = 0.47\left(\frac{Q}{f}\right)^{1/3} = 0.47\left(\frac{5000}{1.76}\right)^{1/3} = 6.66\ \text{m}

Maximum scour below HFL: 2R2R at the upstream nose, 1.5R1.5R at the shank (straight portion). The apron must launch to the slope 2H:1V2H:1V, so its horizontal width is 1.5D′1.5D' and, when launched, it covers a slope length 5 D′\sqrt5\,D' with thickness 1.5t1.5t.

PortionScour factorScour depth below HFLDepth below bed D′D'Apron length 1.5D′1.5D'
Nose (u/s curved head)2.0R13.31 m9.31 m13.97 m
Shank (straight)1.5R9.98 m5.98 m8.98 m

Thickness: pitching t=1.03t = 1.03 m, so the launched apron thickness is 1.5t=1.5×1.03=1.541.5t = 1.5\times1.03 = 1.54 m. Equating volumes per metre, the thickness as laid over 1.5D′1.5D' width is T=1.5t×5D′1.5D′=5 t=2.29T = \dfrac{1.5t\times\sqrt5 D'}{1.5D'} = \sqrt5\,t = 2.29 m (about 2.25t2.25t).

Result: W≈336W \approx 336 m, length of upstream bund =420= 420 m, t=1.03t = 1.03 m, shank apron width =8.98= 8.98 m and nose apron width =13.97= 13.97 m, launched thickness =1.54= 1.54 m.

 Plan:  ________ shank ________   bridge
       (  curved head           |=|
        \____________________   |=|
 Section: top 6 m, HFL+1.5, slope 2:1, pitching t, apron
  • 2072 Asoj · 5 marks

Design the length, radius of curved head, length and thickness of launching apron of a guide bund to train a river with the following data. Design Flood Discharge: 4500 cumecs; Bed Level of river: 150.00 m; HFL: 154.00 m; Av. dia. of river bed material: 0.1 mm.

Similar questions: Gabion guide bund and apron, 3000 m3/s (2071 Magh)

Answer

Data and design basis

  • Silt factor (Lacey): f=1.76dmm=1.760.1=0.56f = 1.76\sqrt{d_{mm}} = 1.76\sqrt{0.1} = 0.56
  • Flood depth above bed: h=154−150=4.00h = 154 - 150 = 4.00 m
  • Design discharge for scour/apron: Q=4500Q = 4500 m³/s

1. Waterway and length of guide bund

Lacey's regime waterway: W=4.75Q=4.754500=318.64W = 4.75\sqrt{Q} = 4.75\sqrt{4500} = 318.64 m. Adopt W≈319W \approx 319 m. Length of guide bund (Garg): upstream shank =1.0=1.0 to 1.5 W1.5\,W, downstream tail =0.2=0.2 to 0.5 W0.5\,W. Adopt

Lus=1.25W=1.25×319=399 mLds=0.25W=80 m\begin{aligned} L_{us} &= 1.25W = 1.25\times 319 = 399\ \text{m} \\ L_{ds} &= 0.25W = 80\ \text{m} \end{aligned}

Curved heads: upstream radius Ru≈0.5W=160R_u \approx 0.5W = 160 m with sweep 120∘120^\circ to 145∘145^\circ (adopt 120∘120^\circ); downstream radius Rd≈0.25W=80R_d \approx 0.25W = 80 m with sweep about 45∘45^\circ. Arc length of upstream head =Ruθ=160×2.094=334= R_u\theta = 160\times 2.094 = 334 m, so total length on the upstream side ≈733\approx 733 m.

2. Thickness of stone pitching

t=0.06 Q1/3=0.06×45001/3=0.06×16.51=0.99 mt = 0.06\,Q^{1/3} = 0.06\times 4500^{1/3} = 0.06\times 16.51 = 0.99\ \text{m}

Adopt t≈1.0t \approx 1.0 m (pitching on the river side slope 2:1, over a 0.15 to 0.3 m graded filter).

3. Scour depth and launching apron

Lacey's normal scour depth:

R=0.47(Qf)1/3=0.47(45000.56)1/3=9.43 mR = 0.47\left(\frac{Q}{f}\right)^{1/3} = 0.47\left(\frac{4500}{0.56}\right)^{1/3} = 9.43\ \text{m}

Maximum scour below HFL: 2R2R at the upstream nose, 1.5R1.5R at the shank (straight portion). The apron must launch to the slope 2H:1V2H:1V, so its horizontal width is 1.5D′1.5D' and, when launched, it covers a slope length 5 D′\sqrt5\,D' with thickness 1.5t1.5t.

PortionScour factorScour depth below HFLDepth below bed D′D'Apron length 1.5D′1.5D'
Nose (u/s curved head)2.0R18.87 m14.87 m22.30 m
Shank (straight)1.5R14.15 m10.15 m15.22 m

Thickness: pitching t=0.99t = 0.99 m, so the launched apron thickness is 1.5t=1.5×0.99=1.491.5t = 1.5\times0.99 = 1.49 m. Equating volumes per metre, the thickness as laid over 1.5D′1.5D' width is T=1.5t×5D′1.5D′=5 t=2.21T = \dfrac{1.5t\times\sqrt5 D'}{1.5D'} = \sqrt5\,t = 2.21 m (about 2.25t2.25t).

Summary

ItemValue
Lacey waterway WW318.64 m (adopt 319 m)
Length of guide bund (u/s)399 m; d/s tail 80 m
Pitching thickness tt0.99 m
Apron at shank: width 1.5D′1.5D' / thickness15.22 m / 1.49 m launched (2.21 m laid)
Apron at nose: width / thickness22.30 m / 1.49 m launched (2.21 m laid)
  • 2071 Magh · 8 marks

Design the length, radius of curved head, length and thickness of gabion slope pitching and gabion launching apron of a guide bund to train a river with the following data. Design Flood Discharge: 3000 cumecs; River Bed Level: 240.0 m; HFL: 245.0 m; Average dia. of river bed material: 0.1 mm.

Similar questions: Guide bund: length, curved head, apron; 4500 m3/s (2072 Asoj)

Answer

Data and design basis

  • Silt factor (Lacey): f=1.76dmm=1.760.1=0.56f = 1.76\sqrt{d_{mm}} = 1.76\sqrt{0.1} = 0.56
  • Flood depth above bed: h=245−240=5.00h = 245 - 240 = 5.00 m
  • Design discharge for scour/apron: Q=3000Q = 3000 m³/s

1. Waterway and length of guide bund

Lacey's regime waterway: W=4.75Q=4.753000=260.17W = 4.75\sqrt{Q} = 4.75\sqrt{3000} = 260.17 m. Adopt W≈260W \approx 260 m. Length of guide bund (Garg): upstream shank =1.0=1.0 to 1.5 W1.5\,W, downstream tail =0.2=0.2 to 0.5 W0.5\,W. Adopt

Lus=1.25W=1.25×260=325 mLds=0.25W=65 m\begin{aligned} L_{us} &= 1.25W = 1.25\times 260 = 325\ \text{m} \\ L_{ds} &= 0.25W = 65\ \text{m} \end{aligned}

Curved heads: upstream radius Ru≈0.5W=130R_u \approx 0.5W = 130 m with sweep 120∘120^\circ to 145∘145^\circ (adopt 120∘120^\circ); downstream radius Rd≈0.25W=65R_d \approx 0.25W = 65 m with sweep about 45∘45^\circ. Arc length of upstream head =Ruθ=130×2.094=272= R_u\theta = 130\times 2.094 = 272 m, so total length on the upstream side ≈597\approx 597 m.

2. Thickness of stone pitching

t=0.06 Q1/3=0.06×30001/3=0.87 mt = 0.06\,Q^{1/3} = 0.06\times 3000^{1/3} = 0.87\ \text{m}

Gabion slope protection: use gabion boxes (1.0 m thick) in one layer, so adopt tg=1.0t_g = 1.0 m (next standard size above 0.87 m) over a 0.15 m gravel filter.

3. Scour depth and launching apron

Lacey's normal scour depth:

R=0.47(Qf)1/3=0.47(30000.56)1/3=8.24 mR = 0.47\left(\frac{Q}{f}\right)^{1/3} = 0.47\left(\frac{3000}{0.56}\right)^{1/3} = 8.24\ \text{m}

Maximum scour below HFL: 2R2R at the upstream nose, 1.5R1.5R at the shank (straight portion). The apron must launch to the slope 2H:1V2H:1V, so its horizontal width is 1.5D′1.5D' and, when launched, it covers a slope length 5 D′\sqrt5\,D' with thickness 1.5t1.5t.

PortionScour factorScour depth below HFLDepth below bed D′D'Apron length 1.5D′1.5D'
Nose (u/s curved head)2.0R16.48 m11.48 m17.22 m
Shank (straight)1.5R12.36 m7.36 m11.04 m

Thickness: pitching t=0.87t = 0.87 m, so the launched apron thickness is 1.5t=1.5×0.87=1.301.5t = 1.5\times0.87 = 1.30 m. Equating volumes per metre, the thickness as laid over 1.5D′1.5D' width is T=1.5t×5D′1.5D′=5 t=1.93T = \dfrac{1.5t\times\sqrt5 D'}{1.5D'} = \sqrt5\,t = 1.93 m (about 2.25t2.25t).

Summary

ItemValue
Lacey waterway WW260.17 m (adopt 260 m)
Length of guide bund (u/s)325 m; d/s tail 65 m
Pitching thickness tt0.87 m
Apron at shank: width 1.5D′1.5D' / thickness11.04 m / 1.30 m launched (1.93 m laid)
Apron at nose: width / thickness17.22 m / 1.30 m launched (1.93 m laid)

Gabion details

  • Slope pitching: gabion boxes 2×1×12\times1\times1 m laid in one layer (1.0 m thick) on a 0.15 m geotextile or gravel filter, wire mesh 8x10 cm, galvanised and PVC coated.
  • Launching apron: launched thickness 1.5t=1.301.5t = 1.30 m; laid thickness 5 t=1.93\sqrt5\,t = 1.93 m, so adopt 2.0 m (two layers of 1 m gabion boxes or four layers of 0.5 m mattress) over a width 1.5D′1.5D' = 11.04 m (shank) and 17.22 m (nose).
  • Gabion boxes are flexible, so they follow the scour hole and launch without breaking.
  • 2072 Magh · 3+5 marks

Write various methods of river training. Discuss with necessary sketch the types of spurs used for river training works.

Answer

Methods of river training (3 marks)

River training works guide a river and protect its banks. The main methods are:

  1. Guide bunds for the approach to a bridge or barrage.
  2. Spurs (groynes) projecting from the bank.
  3. Marginal (flood) embankments along the banks.
  4. Revetment (bank pitching) with stone, concrete or gabion and a launching apron.
  5. Cut-offs across meander necks.
  6. Bed sills / check dams to arrest bed degradation in steep reaches.
  7. Bio-engineering and pitched islands.

Types of spurs used (5 marks)

Spurs are classified by orientation, material and shape.

By orientation to the flow

 Repelling (up)    Deflecting (90)    Attracting (down)
  \  /              |   |               /   /
   \/ <-flow        |   |              /   /
 -----------       -----------        -----------
  bank              bank                bank
  • Repelling spur points upstream (angle 100 to 120° to the bank). It pushes the current strongly away from the bank; the scour at its nose is large. Used on concave bank bends.
  • Deflecting (neutral) spur at right angles. It gives moderate effect and is the most common type.
  • Attracting spur points downstream (60 to 70°). It draws the current toward the bank and has less scour, but protects less.

By material and permeability

  • Impermeable (earth core with stone pitching, stone, gabion): deflect flow completely.
  • Permeable (pile and brushwood, wire-crate or bamboo): reduce velocity and induce silting.

By shape

  • Straight spur with a round or tapered head.
  • T-head spur and hockey (curved) spur: the head protects against scour and gives better protection downstream.

By height

  • Submerged spurs (overtopped at high flood) and non-submerged spurs (above HFL).

Spurs are laid in a series with spacing of about 2 to 2.5 times the spur length on a concave bank.

  • 2071 Bhadra · 1+2+3+2 marks

What is meant by river training works and what are the different objectives served by it. What are the underlying principles behind the determination of spur spacing. Draw L and X-section of a typical spur.

Answer

River training works (1 mark)

River training works are structures built on or along a river to guide the flow, control the river course, and protect banks and structures from erosion and floods.

Objectives (2 marks)

  1. Prevent the river from outflanking a bridge, barrage or town, and hold it in a stable course.
  2. Protect banks from erosion and the land from flooding.
  3. Provide an axial, uniform approach flow to structures, and control silt entry.
  4. Maintain a good channel for navigation or water supply.

Principles behind spur spacing (3 marks)

The spacing must be such that the eroding current cannot reach the bank between two spurs.

  1. The flow leaving the head of a spur spreads out at a small angle (about 10° to 15° with the spur line). The next spur must lie inside the protected zone, so spacing is limited by this expansion angle.
  2. Spacing is related to spur length LL: about 22 to 2.5L2.5L on a concave bank, 33 to 4L4L on a straight reach and larger on a convex bank.
  3. Spacing becomes smaller for: sharper curvature, higher velocity, weaker bank soil, and greater deflection.
  4. The area between spurs should silt up quickly. A very large spacing leaves the bank unprotected; a very small one wastes money.
  5. The river width and spur length should not choke the channel: L≤0.2WriverL \le 0.2W_{river}.

Longitudinal and cross-section of a spur (2 marks)

 Longitudinal section (along spur axis)
  top level HFL+1 m ________ nose
  bank  ---------/        \
      root       slope 1:1 ... 3:1 at nose
  bed ---------------------------- launching apron

 Cross-section
        3-6 m
      _________
     /         \  side slopes 2:1 (3:1 at head)
 ---/ pitching   \---
 bed__ filter ____ apron

Top width is 3 to 6 m, top level HFL ++ 1 m (sloping down toward the head), and the head is pitched with stone and an apron.

  • 2068 Baisakh (old course) · 2+3+2 marks

Define river training works. Enumerate three major objectives of river training works. Write down two basic purposes of spur installation.

Answer

Definition (2 marks)

River training works are structures constructed on, along or across a river so as to guide the flow, control the river's behaviour and protect the banks and the structures from erosion, floods and shifting.

Three major objectives (3 marks)

  1. To prevent flooding and spilling over the banks by confining the river within a defined course.
  2. To protect banks and structures (bridges, barrages, embankments, towns, farmland) from erosion, scour and outflanking.
  3. To ensure axial flow to a structure and control silt, so that a stable and uniform channel is maintained for headworks, navigation or water supply.

Two basic purposes of spurs (2 marks)

  1. Training the river: to deflect the current away from an eroding bank and hold it near the centre of the channel.
  2. Creating slack water for silting: to reduce velocity near the bank and promote deposition between the spurs, forming a new, stable bank (land reclamation).
  • 2066 Bhadra (old course) · 4 marks

Write down the five objectives of river training works.

Answer

River training works serve five main objectives.

  1. Flood protection: confine the river within a fixed channel and prevent it from spilling over the banks and flooding adjacent land and settlements.
  2. Bank protection and prevention of avulsion: stop erosion of the banks and prevent the river from shifting its course or outflanking bridges, barrages, towns and roads.
  3. Axial approach to structures: guide the flow centrally and smoothly to the opening of a bridge, barrage or headwork, avoiding eddies and cross-currents.
  4. Control of silt and sediment: induce silting where land is to be reclaimed and prevent deposits or scour holes at critical locations (such as in front of a canal head regulator).
  5. Maintenance of a stable channel for use: keep a definite, stable channel and depth for navigation, water supply or irrigation intake and protect the river against excessive meandering.

Common works used are guide bunds, spurs, marginal embankments, revetments and cut-offs, chosen to suit the river and its objectives.

  • 2070 Chaitra (old course) · 8 marks

Define groynes and explain different types of groynes.

Answer

A groyne (or spur) is a structure built out from the river bank, roughly at right angles or inclined to the current, to deflect the flow away from the bank, reduce velocity near the bank and induce silting. The root is anchored in the bank and the head projects into the stream.

Types of groynes

1. According to the effect on the current (inclination)

  • Repelling groyne: inclined upstream (100 to 120° with the bank). It pushes the current toward the middle, but the scour at the head is heavy.
  • Attracting groyne: inclined downstream (60 to 70°). It attracts the current, and has little scour.
  • Deflecting or neutral groyne: at right angles to the bank. The commonest type.
 Repelling         Deflecting        Attracting
  \                 |                  /
   \ flow->          |                 /
 ---------        ---------        ---------

2. According to permeability

  • Impermeable groynes are of earth, stone, concrete or gabion. They block the flow.
  • Permeable groynes are of piles, bamboo or brushwood, or wire crates with stone. They let a slow flow pass, causing silt deposits, and have little scour; they suit sandy, low-velocity rivers.

3. According to shape of the head

  • Straight groyne, T-head groyne and hockey (curved) head groyne. A T-head gives better protection and reduces scour at the nose.

4. According to the height

  • Submerged groynes are overtopped in floods.
  • Non-submerged groynes stand above HFL.

5. According to the material

  • Earth with stone pitching, boulder or stone masonry, concrete block, gabion and bio-engineering types.

Design features

  • Length limited to about 20 % of river width; spacing about 2 to 2.5 times the length on concave banks.
  • Top width 3 to 6 m and top level at HFL plus a margin.
  • Heads protected with pitching and a launching apron.
  • 2062 Baisakh (old course) · 1+2+5 marks

Define river training works. Enumerate different methods of river training works. Explain the design of different components of a guide bank.

Answer

Definition (1 mark)

River training works are structures built on or along a river to guide the flow, stabilise its course, protect its banks and safeguard structures like bridges and barrages from floods and erosion.

Methods (2 marks)

  1. Guide bunds (guide banks).
  2. Spurs (groynes).
  3. Marginal embankments (levees).
  4. Bank pitching (revetment) with a launching apron.
  5. Cut-offs.
  6. Bed sills, check dams and bio-engineering.

Design of the components of a guide bank (5 marks)

Waterway: Lacey's regime width W=4.75QW = 4.75\sqrt{Q} (Q in m³/s). Silt factor f=1.76dmmf = 1.76\sqrt{d_{mm}}.

ComponentDesign
Length of guide bankUpstream shank 1.01.0 to 1.5W1.5W; downstream tail 0.20.2 to 0.5W0.5W
Curved headRadius about 0.5W0.5W (upstream), sweep 120120 to 145∘145^\circ; downstream sweep about 45∘45^\circ
Top level and widthHFL +1.5+ 1.5 m free-board; width 6 m (3 to 6 m)
Side slopes2:1 river side (3:1 around the head); 2:1 country side
PitchingThickness t=0.06Q1/3t = 0.06Q^{1/3} on 0.15 to 0.3 m graded filter
Scour depthR=0.47(Q/f)1/3R = 0.47(Q/f)^{1/3}; 2R2R below HFL at nose, 1.5R1.5R at shank
Launching apronDepth below bed D′=D' = scour depth −- flood depth; width 1.5D′1.5D'; launched thickness 1.5t1.5t (laid about 2.25t2.25t)
 Section at shank
      _6 m_
     /     \  HFL+1.5 m
 HFL/_______\ 2:1
   / pitching \
 _/___filter___\_ apron (width 1.5D', launches at 2:1)

The apron is laid at the toe of the pitching and, as the river scours the bed, the stones slide down the 2:1 slope and protect the bund against undermining.

  • 2079 Asoj · 3+5 marks

Draw a neat plan and sections of a Bell's Bund and give salient steps of its design procedure.

Answer

A Bell's bund is a guide bund (guide bank) on the pattern recommended by Bell, in which a pair of embankments with curved heads on the upstream and a short tail on the downstream, are laid symmetrically about the axis of a bridge or barrage so that the river approaches the waterway axially. The waterway is based on Lacey's regime width.

Plan and sections (3 marks)

 U/S                                       D/S
   ______________________________   |   ____
  /   upstream shank 1.0-1.5 W   \  |  /    \ tail
 (  curved head, R = 0.5W,        )=|=(      ) 0.25 W
  \ sweep 120 deg                 /  |  \____/
   \_____________________________/   |
         waterway W (Lacey)        axis of bridge
 Section at shank              Section at nose
     __6 m__                      __6 m__
    /       \  HFL+1.5           /        \
 HFL/_________\ 2:1          HFL/__________\ 3:1
  / pitching t \                / pitching t \
 /___ apron ____\ (1.5R)    /____ apron (2R) ___\

Design steps (5 marks)

  1. Design discharge QQ, HFL, bed level and median grain size dd.
  2. Silt factor f=1.76dmmf = 1.76\sqrt{d_{mm}}, and waterway W=4.75QW = 4.75\sqrt{Q}.
  3. Length of upstream shank 1.01.0 to 1.5W1.5W, downstream tail 0.20.2 to 0.5W0.5W.
  4. Radius of upstream curved head about 0.5W0.5W with sweep 120120 to 145∘145^\circ; tail with a smaller radius, sweep about 45∘45^\circ.
  5. Top level == HFL +1.5+ 1.5 m, top width 6 m, side slopes 2:1.
  6. Pitching thickness t=0.06Q1/3t = 0.06Q^{1/3}.
  7. Scour depth R=0.47(Q/f)1/3R = 0.47(Q/f)^{1/3}; max scour below HFL: 2R2R at nose, 1.5R1.5R at shank.
  8. Launching apron: depth below bed D′=D' = scour depth −- flood depth, width 1.5D′1.5D', launched thickness 1.5t1.5t.
  9. Draw plan and sections.
  • 2068 Chaitra (old course) · 4+4 marks

With neat sketch (plan and section), show the river training works for a bridge. What is a launching apron? How is it designed?

Answer

River training works for a bridge (4 marks)

At a bridge on an alluvial river, the river is contracted to the bridge waterway, so training works are provided to guide the flow axially and prevent flanking: guide bunds on both sides upstream, approach embankments, pitching of slopes and the river banks, launching aprons and sometimes spurs upstream.

 Plan
 U/S                                     D/S
  ____________________      |       ____
 /   guide bund        \ approach |=| /    \
(   curved head         )========|=|=(     )
 \____________________/ embankment|=| \____/
 flow --->  waterway W between abutments
 Section through guide bund
      __6 m__    HFL+1.5
     /       \
 HFL/_________\ 2:1
   / pitching   \
 _/__ filter ____\_ launching apron

Launching apron (2 marks)

A launching apron is a layer of loose stone (or concrete blocks or gabion) laid on the bed at the toe of the pitching. When scour develops at the toe, the stones slide into the scour hole and form a protective layer on the slope, preventing undermining of the bund.

Design of launching apron (2 marks)

  1. Scour depth R=0.47(Q/f)1/3R = 0.47(Q/f)^{1/3} with f=1.76dmmf = 1.76\sqrt{d_{mm}}.
  2. Maximum scour below HFL: 2R2R (nose) or 1.5R1.5R (shank). Depth below bed D′=D' = scour −- flood depth.
  3. Launching slope 2H:1V, so the stone volume must cover a slope length 5D′=2.236D′\sqrt5 D' = 2.236D'.
  4. Thickness of launched apron =1.5t= 1.5t where t=0.06Q1/3t = 0.06Q^{1/3} is pitching thickness.
  5. Width laid =1.5D′= 1.5D' and thickness laid =1.5t×2.236D′1.5D′=2.24t= \dfrac{1.5t\times 2.236D'}{1.5D'} = 2.24t (about 2.25t2.25t).
  • 2078 Chaitra · 8 marks

A barrage is to be constructed across a river, having 100 year flood discharge of 7500 m³/s and high flood level is 238.00 m. River bed level is 232.00 m and average diameter of bed material is 5.07 mm. Find out the desired waterway for the barrage. Design Bell's guide bunds including launching apron.

Answer

Desired waterway of the barrage

Lacey's regime waterway (wetted perimeter) is

W=4.75Q=4.757500=411.4 mW = 4.75\sqrt{Q} = 4.75\sqrt{7500} = 411.4\ \text{m}

For a barrage the waterway is generally kept equal to this regime width (1.0 to 1.2 times); adopt W=411W = 411 m between abutments. Flood depth h=238.0−232.0=6.0h = 238.0 - 232.0 = 6.0 m.

Data and design basis (Bell's guide bund)

  • Bell's guide bund is designed on Lacey's regime width; bed material is gravel (5.07 mm).
  • Silt factor (Lacey): f=1.76dmm=1.765.07=3.96f = 1.76\sqrt{d_{mm}} = 1.76\sqrt{5.07} = 3.96
  • Flood depth above bed: h=238.0−232.0=6.00h = 238.0 - 232.0 = 6.00 m
  • Design discharge for scour/apron: Q=7500Q = 7500 m³/s

1. Waterway and length of guide bund

Lacey's regime waterway: W=4.75Q=4.757500=411.36W = 4.75\sqrt{Q} = 4.75\sqrt{7500} = 411.36 m. Adopt W≈411W \approx 411 m. Length of guide bund (Garg): upstream shank =1.0=1.0 to 1.5 W1.5\,W, downstream tail =0.2=0.2 to 0.5 W0.5\,W. Adopt

Lus=1.25W=1.25×411=514 mLds=0.25W=103 m\begin{aligned} L_{us} &= 1.25W = 1.25\times 411 = 514\ \text{m} \\ L_{ds} &= 0.25W = 103\ \text{m} \end{aligned}

Curved heads: upstream radius Ru≈0.5W=206R_u \approx 0.5W = 206 m with sweep 120∘120^\circ to 145∘145^\circ (adopt 120∘120^\circ); downstream radius Rd≈0.25W=103R_d \approx 0.25W = 103 m with sweep about 45∘45^\circ. Arc length of upstream head =Ruθ=206×2.094=430= R_u\theta = 206\times 2.094 = 430 m, so total length on the upstream side ≈944\approx 944 m.

2. Thickness of stone pitching

t=0.06 Q1/3=0.06×75001/3=0.06×19.57=1.17 mt = 0.06\,Q^{1/3} = 0.06\times 7500^{1/3} = 0.06\times 19.57 = 1.17\ \text{m}

Adopt t≈1.2t \approx 1.2 m (pitching on the river side slope 2:1, over a 0.15 to 0.3 m graded filter).

3. Scour depth and launching apron

Lacey's normal scour depth:

R=0.47(Qf)1/3=0.47(75003.96)1/3=5.81 mR = 0.47\left(\frac{Q}{f}\right)^{1/3} = 0.47\left(\frac{7500}{3.96}\right)^{1/3} = 5.81\ \text{m}

Maximum scour below HFL: 2R2R at the upstream nose, 1.5R1.5R at the shank (straight portion). The apron must launch to the slope 2H:1V2H:1V, so its horizontal width is 1.5D′1.5D' and, when launched, it covers a slope length 5 D′\sqrt5\,D' with thickness 1.5t1.5t.

PortionScour factorScour depth below HFLDepth below bed D′D'Apron length 1.5D′1.5D'
Nose (u/s curved head)2.0R11.63 m5.63 m8.44 m
Shank (straight)1.5R8.72 m2.72 m4.08 m

Thickness: pitching t=1.17t = 1.17 m, so the launched apron thickness is 1.5t=1.5×1.17=1.761.5t = 1.5\times1.17 = 1.76 m. Equating volumes per metre, the thickness as laid over 1.5D′1.5D' width is T=1.5t×5D′1.5D′=5 t=2.63T = \dfrac{1.5t\times\sqrt5 D'}{1.5D'} = \sqrt5\,t = 2.63 m (about 2.25t2.25t).

Summary

ItemValue
Lacey waterway WW411.36 m (adopt 411 m)
Length of guide bund (u/s)514 m; d/s tail 103 m
Pitching thickness tt1.17 m
Apron at shank: width 1.5D′1.5D' / thickness4.08 m / 1.76 m launched (2.63 m laid)
Apron at nose: width / thickness8.44 m / 1.76 m launched (2.63 m laid)

Sketches

Plan of guide bunds:

 U/S                                          D/S
                       bridge / weir axis
   Shank (straight)                |
 ________________________________  |  ___
/  1.0-1.5 W upstream            \ | /   \  tail
\________________________________/=|=\___/  0.25 W
 curved head                       |
 R, sweep 120 deg    <-- waterway W -->
 ________________________________  |  ___
/                                \ | /   \
\________________________________/=|=\___/

Section at the shank (straight portion):

           top width 6 m
         ___________  <- HFL + 1.5 m
        /           \
 HFL ---/-------------\---  2:1 slopes
       / pitching t    \
 bed__/__ filter ______ \___
      \_ launching apron _/ (launches at 2:1)
  • 2078 Baisakh · 8 marks

Design guide bunds and launching apron required to be provided for a bridge across a river whose total waterway is 658.88 m. The design flood discharge is 13,100 m³/s which may be increased by 20% for the design of the launching apron. The mean size of the river bed material is 0.3 mm.

Answer

Data and design basis

  • Total waterway W=658.88W = 658.88 m (given). The flood depth is not given, so Lacey's regime depth for the intensity q=Q/W=13100/658.88=19.88q = Q/W = 13100/658.88 = 19.88 m²/s is used: RL=1.35(q2/f)1/3=10.03R_L = 1.35(q^2/f)^{1/3} = 10.03 m. f=1.760.3=0.964f = 1.76\sqrt{0.3} = 0.964.
  • Discharge is increased by 20 % for the apron design: Qa=1.2×13100=15720Q_a = 1.2\times13100 = 15720 m³/s.
  • Silt factor given: f=0.96f = 0.96
  • Flood depth: h=10.03h = 10.03 m
  • Design discharge for scour/apron: Q=15720Q = 15720 m³/s

1. Waterway and length of guide bund

Waterway between abutments W=658.88W = 658.88 m (given). Length of guide bund (Garg): upstream shank =1.0=1.0 to 1.5 W1.5\,W, downstream tail =0.2=0.2 to 0.5 W0.5\,W. Adopt

Lus=1.25W=1.25×659=824 mLds=0.25W=165 m\begin{aligned} L_{us} &= 1.25W = 1.25\times 659 = 824\ \text{m} \\ L_{ds} &= 0.25W = 165\ \text{m} \end{aligned}

Curved heads: upstream radius Ru≈0.5W=330R_u \approx 0.5W = 330 m with sweep 120∘120^\circ to 145∘145^\circ (adopt 120∘120^\circ); downstream radius Rd≈0.25W=165R_d \approx 0.25W = 165 m with sweep about 45∘45^\circ. Arc length of upstream head =Ruθ=330×2.094=690= R_u\theta = 330\times 2.094 = 690 m, so total length on the upstream side ≈1514\approx 1514 m.

2. Thickness of stone pitching

t=0.06 Q1/3=0.06×131001/3=0.06×23.57=1.41 mt = 0.06\,Q^{1/3} = 0.06\times 13100^{1/3} = 0.06\times 23.57 = 1.41\ \text{m}

Adopt t≈1.5t \approx 1.5 m (pitching on the river side slope 2:1, over a 0.15 to 0.3 m graded filter).

3. Scour depth and launching apron

Lacey's normal scour depth:

R=0.47(Qf)1/3=0.47(157200.96)1/3=11.92 mR = 0.47\left(\frac{Q}{f}\right)^{1/3} = 0.47\left(\frac{15720}{0.96}\right)^{1/3} = 11.92\ \text{m}

Maximum scour below HFL: 2R2R at the upstream nose, 1.5R1.5R at the shank (straight portion). The apron must launch to the slope 2H:1V2H:1V, so its horizontal width is 1.5D′1.5D' and, when launched, it covers a slope length 5 D′\sqrt5\,D' with thickness 1.5t1.5t.

PortionScour factorScour depth below HFLDepth below bed D′D'Apron length 1.5D′1.5D'
Nose (u/s curved head)2.0R23.84 m13.81 m20.71 m
Shank (straight)1.5R17.88 m7.85 m11.77 m

Thickness: pitching t=1.41t = 1.41 m, so the launched apron thickness is 1.5t=1.5×1.41=2.121.5t = 1.5\times1.41 = 2.12 m. Equating volumes per metre, the thickness as laid over 1.5D′1.5D' width is T=1.5t×5D′1.5D′=5 t=3.16T = \dfrac{1.5t\times\sqrt5 D'}{1.5D'} = \sqrt5\,t = 3.16 m (about 2.25t2.25t).

Summary

ItemValue
Lacey waterway WW658.88 m (adopt 659 m)
Length of guide bund (u/s)824 m; d/s tail 165 m
Pitching thickness tt1.41 m
Apron at shank: width 1.5D′1.5D' / thickness11.77 m / 2.12 m launched (3.16 m laid)
Apron at nose: width / thickness20.71 m / 2.12 m launched (3.16 m laid)

Sketches

Plan of guide bunds:

 U/S                                          D/S
                       bridge / weir axis
   Shank (straight)                |
 ________________________________  |  ___
/  1.0-1.5 W upstream            \ | /   \  tail
\________________________________/=|=\___/  0.25 W
 curved head                       |
 R, sweep 120 deg    <-- waterway W -->
 ________________________________  |  ___
/                                \ | /   \
\________________________________/=|=\___/

Section at the shank (straight portion):

           top width 6 m
         ___________  <- HFL + 1.5 m
        /           \
 HFL ---/-------------\---  2:1 slopes
       / pitching t    \
 bed__/__ filter ______ \___
      \_ launching apron _/ (launches at 2:1)
  • 2078 Poush · 5 marks

Design a guide bank required for a bridge on a river having following particulars: maximum flood discharge = 4000 m³/s, HFL = 205 m, river bed level = 202 m, average diameter of river bed material = 0.40 mm.

Answer

Data and design basis

  • Silt factor (Lacey): f=1.76dmm=1.760.4=1.11f = 1.76\sqrt{d_{mm}} = 1.76\sqrt{0.4} = 1.11
  • Flood depth above bed: h=205−202=3.00h = 205 - 202 = 3.00 m
  • Design discharge for scour/apron: Q=4000Q = 4000 m³/s

1. Waterway and length of guide bund

Lacey's regime waterway: W=4.75Q=4.754000=300.42W = 4.75\sqrt{Q} = 4.75\sqrt{4000} = 300.42 m. Adopt W≈300W \approx 300 m. Length of guide bund (Garg): upstream shank =1.0=1.0 to 1.5 W1.5\,W, downstream tail =0.2=0.2 to 0.5 W0.5\,W. Adopt

Lus=1.25W=1.25×300=375 mLds=0.25W=75 m\begin{aligned} L_{us} &= 1.25W = 1.25\times 300 = 375\ \text{m} \\ L_{ds} &= 0.25W = 75\ \text{m} \end{aligned}

Curved heads: upstream radius Ru≈0.5W=150R_u \approx 0.5W = 150 m with sweep 120∘120^\circ to 145∘145^\circ (adopt 120∘120^\circ); downstream radius Rd≈0.25W=75R_d \approx 0.25W = 75 m with sweep about 45∘45^\circ. Arc length of upstream head =Ruθ=150×2.094=314= R_u\theta = 150\times 2.094 = 314 m, so total length on the upstream side ≈689\approx 689 m.

2. Thickness of stone pitching

t=0.06 Q1/3=0.06×40001/3=0.06×15.87=0.95 mt = 0.06\,Q^{1/3} = 0.06\times 4000^{1/3} = 0.06\times 15.87 = 0.95\ \text{m}

Adopt t≈1.0t \approx 1.0 m (pitching on the river side slope 2:1, over a 0.15 to 0.3 m graded filter).

3. Scour depth and launching apron

Lacey's normal scour depth:

R=0.47(Qf)1/3=0.47(40001.11)1/3=7.20 mR = 0.47\left(\frac{Q}{f}\right)^{1/3} = 0.47\left(\frac{4000}{1.11}\right)^{1/3} = 7.20\ \text{m}

Maximum scour below HFL: 2R2R at the upstream nose, 1.5R1.5R at the shank (straight portion). The apron must launch to the slope 2H:1V2H:1V, so its horizontal width is 1.5D′1.5D' and, when launched, it covers a slope length 5 D′\sqrt5\,D' with thickness 1.5t1.5t.

PortionScour factorScour depth below HFLDepth below bed D′D'Apron length 1.5D′1.5D'
Nose (u/s curved head)2.0R14.40 m11.40 m17.10 m
Shank (straight)1.5R10.80 m7.80 m11.70 m

Thickness: pitching t=0.95t = 0.95 m, so the launched apron thickness is 1.5t=1.5×0.95=1.431.5t = 1.5\times0.95 = 1.43 m. Equating volumes per metre, the thickness as laid over 1.5D′1.5D' width is T=1.5t×5D′1.5D′=5 t=2.13T = \dfrac{1.5t\times\sqrt5 D'}{1.5D'} = \sqrt5\,t = 2.13 m (about 2.25t2.25t).

Summary

ItemValue
Lacey waterway WW300.42 m (adopt 300 m)
Length of guide bund (u/s)375 m; d/s tail 75 m
Pitching thickness tt0.95 m
Apron at shank: width 1.5D′1.5D' / thickness11.70 m / 1.43 m launched (2.13 m laid)
Apron at nose: width / thickness17.10 m / 1.43 m launched (2.13 m laid)

Sketches

Plan of guide bunds:

 U/S                                          D/S
                       bridge / weir axis
   Shank (straight)                |
 ________________________________  |  ___
/  1.0-1.5 W upstream            \ | /   \  tail
\________________________________/=|=\___/  0.25 W
 curved head                       |
 R, sweep 120 deg    <-- waterway W -->
 ________________________________  |  ___
/                                \ | /   \
\________________________________/=|=\___/

Section at the shank (straight portion):

           top width 6 m
         ___________  <- HFL + 1.5 m
        /           \
 HFL ---/-------------\---  2:1 slopes
       / pitching t    \
 bed__/__ filter ______ \___
      \_ launching apron _/ (launches at 2:1)
  • 2077 Chaitra · 8 marks

Design a guide bank for the weir site from the following data provided. Bed level of river = 105.00 m; Depth of water during high flood = 5 m; Discharge of river = 6500 m³/s. The value of Lacey's silt factor may be taken as 1.

Answer

Data and design basis

  • Bed level 105.00 m, flood depth 5 m, so HFL =110.00=110.00 m; top level of bank =111.50=111.50 m.
  • Silt factor given: f=1.00f = 1.00
  • Flood depth: h=5.00h = 5.00 m
  • Design discharge for scour/apron: Q=6500Q = 6500 m³/s

1. Waterway and length of guide bund

Lacey's regime waterway: W=4.75Q=4.756500=382.96W = 4.75\sqrt{Q} = 4.75\sqrt{6500} = 382.96 m. Adopt W≈383W \approx 383 m. Length of guide bund (Garg): upstream shank =1.0=1.0 to 1.5 W1.5\,W, downstream tail =0.2=0.2 to 0.5 W0.5\,W. Adopt

Lus=1.25W=1.25×383=479 mLds=0.25W=96 m\begin{aligned} L_{us} &= 1.25W = 1.25\times 383 = 479\ \text{m} \\ L_{ds} &= 0.25W = 96\ \text{m} \end{aligned}

Curved heads: upstream radius Ru≈0.5W=192R_u \approx 0.5W = 192 m with sweep 120∘120^\circ to 145∘145^\circ (adopt 120∘120^\circ); downstream radius Rd≈0.25W=96R_d \approx 0.25W = 96 m with sweep about 45∘45^\circ. Arc length of upstream head =Ruθ=192×2.094=401= R_u\theta = 192\times 2.094 = 401 m, so total length on the upstream side ≈880\approx 880 m.

2. Thickness of stone pitching

t=0.06 Q1/3=0.06×65001/3=0.06×18.66=1.12 mt = 0.06\,Q^{1/3} = 0.06\times 6500^{1/3} = 0.06\times 18.66 = 1.12\ \text{m}

Adopt t≈1.2t \approx 1.2 m (pitching on the river side slope 2:1, over a 0.15 to 0.3 m graded filter).

3. Scour depth and launching apron

Lacey's normal scour depth:

R=0.47(Qf)1/3=0.47(65001.00)1/3=8.77 mR = 0.47\left(\frac{Q}{f}\right)^{1/3} = 0.47\left(\frac{6500}{1.00}\right)^{1/3} = 8.77\ \text{m}

Maximum scour below HFL: 2R2R at the upstream nose, 1.5R1.5R at the shank (straight portion). The apron must launch to the slope 2H:1V2H:1V, so its horizontal width is 1.5D′1.5D' and, when launched, it covers a slope length 5 D′\sqrt5\,D' with thickness 1.5t1.5t.

PortionScour factorScour depth below HFLDepth below bed D′D'Apron length 1.5D′1.5D'
Nose (u/s curved head)2.0R17.54 m12.54 m18.81 m
Shank (straight)1.5R13.16 m8.16 m12.24 m

Thickness: pitching t=1.12t = 1.12 m, so the launched apron thickness is 1.5t=1.5×1.12=1.681.5t = 1.5\times1.12 = 1.68 m. Equating volumes per metre, the thickness as laid over 1.5D′1.5D' width is T=1.5t×5D′1.5D′=5 t=2.50T = \dfrac{1.5t\times\sqrt5 D'}{1.5D'} = \sqrt5\,t = 2.50 m (about 2.25t2.25t).

Summary

ItemValue
Lacey waterway WW382.96 m (adopt 383 m)
Length of guide bund (u/s)479 m; d/s tail 96 m
Pitching thickness tt1.12 m
Apron at shank: width 1.5D′1.5D' / thickness12.24 m / 1.68 m launched (2.50 m laid)
Apron at nose: width / thickness18.81 m / 1.68 m launched (2.50 m laid)

Sketches

Plan of guide bunds:

 U/S                                          D/S
                       bridge / weir axis
   Shank (straight)                |
 ________________________________  |  ___
/  1.0-1.5 W upstream            \ | /   \  tail
\________________________________/=|=\___/  0.25 W
 curved head                       |
 R, sweep 120 deg    <-- waterway W -->
 ________________________________  |  ___
/                                \ | /   \
\________________________________/=|=\___/

Section at the shank (straight portion):

           top width 6 m
         ___________  <- HFL + 1.5 m
        /           \
 HFL ---/-------------\---  2:1 slopes
       / pitching t    \
 bed__/__ filter ______ \___
      \_ launching apron _/ (launches at 2:1)
  • 2081 Chaitra · 8 marks

Design and sketch (plan, section at straight portion, section at nose) guide bunds including launching apron, for a bridge site with following hydraulic data: Designed discharge = 2500 m³/s; H.F.L = 78.8 m; river bed level = 75.5 m; and D50 of bed material = 0.1 mm.

Answer

Data and design basis

  • Silt factor (Lacey): f=1.76dmm=1.760.1=0.56f = 1.76\sqrt{d_{mm}} = 1.76\sqrt{0.1} = 0.56
  • Flood depth above bed: h=78.8−75.5=3.30h = 78.8 - 75.5 = 3.30 m
  • Design discharge for scour/apron: Q=2500Q = 2500 m³/s

1. Waterway and length of guide bund

Lacey's regime waterway: W=4.75Q=4.752500=237.50W = 4.75\sqrt{Q} = 4.75\sqrt{2500} = 237.50 m. Adopt W≈238W \approx 238 m. Length of guide bund (Garg): upstream shank =1.0=1.0 to 1.5 W1.5\,W, downstream tail =0.2=0.2 to 0.5 W0.5\,W. Adopt

Lus=1.25W=1.25×238=298 mLds=0.25W=60 m\begin{aligned} L_{us} &= 1.25W = 1.25\times 238 = 298\ \text{m} \\ L_{ds} &= 0.25W = 60\ \text{m} \end{aligned}

Curved heads: upstream radius Ru≈0.5W=119R_u \approx 0.5W = 119 m with sweep 120∘120^\circ to 145∘145^\circ (adopt 120∘120^\circ); downstream radius Rd≈0.25W=60R_d \approx 0.25W = 60 m with sweep about 45∘45^\circ. Arc length of upstream head =Ruθ=119×2.094=249= R_u\theta = 119\times 2.094 = 249 m, so total length on the upstream side ≈547\approx 547 m.

2. Thickness of stone pitching

t=0.06 Q1/3=0.06×25001/3=0.06×13.57=0.81 mt = 0.06\,Q^{1/3} = 0.06\times 2500^{1/3} = 0.06\times 13.57 = 0.81\ \text{m}

Adopt t≈0.9t \approx 0.9 m (pitching on the river side slope 2:1, over a 0.15 to 0.3 m graded filter).

3. Scour depth and launching apron

Lacey's normal scour depth:

R=0.47(Qf)1/3=0.47(25000.56)1/3=7.75 mR = 0.47\left(\frac{Q}{f}\right)^{1/3} = 0.47\left(\frac{2500}{0.56}\right)^{1/3} = 7.75\ \text{m}

Maximum scour below HFL: 2R2R at the upstream nose, 1.5R1.5R at the shank (straight portion). The apron must launch to the slope 2H:1V2H:1V, so its horizontal width is 1.5D′1.5D' and, when launched, it covers a slope length 5 D′\sqrt5\,D' with thickness 1.5t1.5t.

PortionScour factorScour depth below HFLDepth below bed D′D'Apron length 1.5D′1.5D'
Nose (u/s curved head)2.0R15.51 m12.21 m18.31 m
Shank (straight)1.5R11.63 m8.33 m12.50 m

Thickness: pitching t=0.81t = 0.81 m, so the launched apron thickness is 1.5t=1.5×0.81=1.221.5t = 1.5\times0.81 = 1.22 m. Equating volumes per metre, the thickness as laid over 1.5D′1.5D' width is T=1.5t×5D′1.5D′=5 t=1.82T = \dfrac{1.5t\times\sqrt5 D'}{1.5D'} = \sqrt5\,t = 1.82 m (about 2.25t2.25t).

Summary

ItemValue
Lacey waterway WW237.50 m (adopt 238 m)
Length of guide bund (u/s)298 m; d/s tail 60 m
Pitching thickness tt0.81 m
Apron at shank: width 1.5D′1.5D' / thickness12.50 m / 1.22 m launched (1.82 m laid)
Apron at nose: width / thickness18.31 m / 1.22 m launched (1.82 m laid)

Sketches

Plan:

 U/S                                          D/S
                       bridge / weir axis
   Shank (straight)                |
 ________________________________  |  ___
/  1.0-1.5 W upstream            \ | /   \  tail
\________________________________/=|=\___/  0.25 W
 curved head                       |
 R, sweep 120 deg    <-- waterway W -->
 ________________________________  |  ___
/                                \ | /   \
\________________________________/=|=\___/

Section at the straight portion (shank):

           top width 6 m
         ___________  <- HFL + 1.5 m
        /           \
 HFL ---/-------------\---  2:1 slopes
       / pitching t    \
 bed__/__ filter ______ \___
      \_ launching apron _/ (launches at 2:1)

Section at the nose (upstream curved head):

 Section at u/s curved head (nose)
            ______  <- HFL + 1.5 m
           /      \   top 6 m, side 3:1 (flatter)
 HFL ----/---------\----
        / pitching t \
 bed ___/_____________\__
         \_ apron: 2.0R scour, 1.5D' wide _/
  • 2069 Bhadra · 8 marks

Following hydraulic data near a proposed bridge site are obtained. Maximum discharge = 4000 m³/s; Highest flood level = 205.0 m; River bed level = 200.00 m; Average diameter of river bed material = 0.1 mm. Design the following components of a guide bund and neatly sketch it. (i) Length of guide bund (ii) Thickness of pitching of the slope (iii) Length of launching apron (iv) thickness of launching apron.

Answer

Data and design basis

  • Silt factor (Lacey): f=1.76dmm=1.760.1=0.56f = 1.76\sqrt{d_{mm}} = 1.76\sqrt{0.1} = 0.56
  • Flood depth above bed: h=205.0−200.0=5.00h = 205.0 - 200.0 = 5.00 m
  • Design discharge for scour/apron: Q=4000Q = 4000 m³/s

1. Waterway and length of guide bund

Lacey's regime waterway: W=4.75Q=4.754000=300.42W = 4.75\sqrt{Q} = 4.75\sqrt{4000} = 300.42 m. Adopt W≈300W \approx 300 m. Length of guide bund (Garg): upstream shank =1.0=1.0 to 1.5 W1.5\,W, downstream tail =0.2=0.2 to 0.5 W0.5\,W. Adopt

Lus=1.25W=1.25×300=375 mLds=0.25W=75 m\begin{aligned} L_{us} &= 1.25W = 1.25\times 300 = 375\ \text{m} \\ L_{ds} &= 0.25W = 75\ \text{m} \end{aligned}

Curved heads: upstream radius Ru≈0.5W=150R_u \approx 0.5W = 150 m with sweep 120∘120^\circ to 145∘145^\circ (adopt 120∘120^\circ); downstream radius Rd≈0.25W=75R_d \approx 0.25W = 75 m with sweep about 45∘45^\circ. Arc length of upstream head =Ruθ=150×2.094=314= R_u\theta = 150\times 2.094 = 314 m, so total length on the upstream side ≈689\approx 689 m.

2. Thickness of stone pitching

t=0.06 Q1/3=0.06×40001/3=0.06×15.87=0.95 mt = 0.06\,Q^{1/3} = 0.06\times 4000^{1/3} = 0.06\times 15.87 = 0.95\ \text{m}

Adopt t≈1.0t \approx 1.0 m (pitching on the river side slope 2:1, over a 0.15 to 0.3 m graded filter).

3. Scour depth and launching apron

Lacey's normal scour depth:

R=0.47(Qf)1/3=0.47(40000.56)1/3=9.07 mR = 0.47\left(\frac{Q}{f}\right)^{1/3} = 0.47\left(\frac{4000}{0.56}\right)^{1/3} = 9.07\ \text{m}

Maximum scour below HFL: 2R2R at the upstream nose, 1.5R1.5R at the shank (straight portion). The apron must launch to the slope 2H:1V2H:1V, so its horizontal width is 1.5D′1.5D' and, when launched, it covers a slope length 5 D′\sqrt5\,D' with thickness 1.5t1.5t.

PortionScour factorScour depth below HFLDepth below bed D′D'Apron length 1.5D′1.5D'
Nose (u/s curved head)2.0R18.14 m13.14 m19.71 m
Shank (straight)1.5R13.61 m8.61 m12.91 m

Thickness: pitching t=0.95t = 0.95 m, so the launched apron thickness is 1.5t=1.5×0.95=1.431.5t = 1.5\times0.95 = 1.43 m. Equating volumes per metre, the thickness as laid over 1.5D′1.5D' width is T=1.5t×5D′1.5D′=5 t=2.13T = \dfrac{1.5t\times\sqrt5 D'}{1.5D'} = \sqrt5\,t = 2.13 m (about 2.25t2.25t).

Summary

ItemValue
Lacey waterway WW300.42 m (adopt 300 m)
Length of guide bund (u/s)375 m; d/s tail 75 m
Pitching thickness tt0.95 m
Apron at shank: width 1.5D′1.5D' / thickness12.91 m / 1.43 m launched (2.13 m laid)
Apron at nose: width / thickness19.71 m / 1.43 m launched (2.13 m laid)

Sketches

Plan of guide bunds:

 U/S                                          D/S
                       bridge / weir axis
   Shank (straight)                |
 ________________________________  |  ___
/  1.0-1.5 W upstream            \ | /   \  tail
\________________________________/=|=\___/  0.25 W
 curved head                       |
 R, sweep 120 deg    <-- waterway W -->
 ________________________________  |  ___
/                                \ | /   \
\________________________________/=|=\___/

Section at the shank (straight portion):

           top width 6 m
         ___________  <- HFL + 1.5 m
        /           \
 HFL ---/-------------\---  2:1 slopes
       / pitching t    \
 bed__/__ filter ______ \___
      \_ launching apron _/ (launches at 2:1)
  • 2076 Bhadra · 6 marks

Determine the length and thickness of launching apron for the straight portion of a guide bund in a river for the following data given below. Max. discharge = 6000 m³/s, Average dia. of bed material = 1.0 mm, Highest flood level (HFL) = 330 m and River bed level = 326 m.

Answer

Data and design basis

  • Silt factor (Lacey): f=1.76dmm=1.761.0=1.76f = 1.76\sqrt{d_{mm}} = 1.76\sqrt{1.0} = 1.76
  • Flood depth above bed: h=330−326=4.00h = 330 - 326 = 4.00 m
  • Design discharge for scour/apron: Q=6000Q = 6000 m³/s

1. Scour depth and launching apron

Lacey's normal scour depth:

R=0.47(Qf)1/3=0.47(60001.76)1/3=7.07 mR = 0.47\left(\frac{Q}{f}\right)^{1/3} = 0.47\left(\frac{6000}{1.76}\right)^{1/3} = 7.07\ \text{m}

Maximum scour below HFL: 2R2R at the upstream nose, 1.5R1.5R at the shank (straight portion). The apron must launch to the slope 2H:1V2H:1V, so its horizontal width is 1.5D′1.5D' and, when launched, it covers a slope length 5 D′\sqrt5\,D' with thickness 1.5t1.5t.

PortionScour factorScour depth below HFLDepth below bed D′D'Apron length 1.5D′1.5D'
Shank (straight)1.5R10.61 m6.61 m9.92 m

Thickness: pitching t=1.09t = 1.09 m, so the launched apron thickness is 1.5t=1.5×1.09=1.641.5t = 1.5\times1.09 = 1.64 m. Equating volumes per metre, the thickness as laid over 1.5D′1.5D' width is T=1.5t×5D′1.5D′=5 t=2.44T = \dfrac{1.5t\times\sqrt5 D'}{1.5D'} = \sqrt5\,t = 2.44 m (about 2.25t2.25t).

Answer (straight portion): length of launching apron =1.5D′=9.92=1.5D' = 9.92 m (horizontal), thickness =1.5t=1.64=1.5t = 1.64 m when launched (about 2.44 m as laid).

  • 2074 Bhadra · 5 marks

A bridge is to be constructed across a river having the following hydraulic data: Maximum flood Discharge: 5000 m³/s; Highest flood level: 254.0 m; River bed level: 250 m; Average diameter of river sand: 0.25 m. Design and sketch a guide bank including launching apron to train the river.

Answer

Data and design basis

  • The average size of the river sand is taken as 0.25 mm (0.25 m would not be sand).
  • Silt factor (Lacey): f=1.76dmm=1.760.25=0.88f = 1.76\sqrt{d_{mm}} = 1.76\sqrt{0.25} = 0.88
  • Flood depth above bed: h=254−250=4.00h = 254 - 250 = 4.00 m
  • Design discharge for scour/apron: Q=5000Q = 5000 m³/s

1. Waterway and length of guide bund

Lacey's regime waterway: W=4.75Q=4.755000=335.88W = 4.75\sqrt{Q} = 4.75\sqrt{5000} = 335.88 m. Adopt W≈336W \approx 336 m. Length of guide bund (Garg): upstream shank =1.0=1.0 to 1.5 W1.5\,W, downstream tail =0.2=0.2 to 0.5 W0.5\,W. Adopt

Lus=1.25W=1.25×336=420 mLds=0.25W=84 m\begin{aligned} L_{us} &= 1.25W = 1.25\times 336 = 420\ \text{m} \\ L_{ds} &= 0.25W = 84\ \text{m} \end{aligned}

Curved heads: upstream radius Ru≈0.5W=168R_u \approx 0.5W = 168 m with sweep 120∘120^\circ to 145∘145^\circ (adopt 120∘120^\circ); downstream radius Rd≈0.25W=84R_d \approx 0.25W = 84 m with sweep about 45∘45^\circ. Arc length of upstream head =Ruθ=168×2.094=352= R_u\theta = 168\times 2.094 = 352 m, so total length on the upstream side ≈772\approx 772 m.

2. Thickness of stone pitching

t=0.06 Q1/3=0.06×50001/3=0.06×17.10=1.03 mt = 0.06\,Q^{1/3} = 0.06\times 5000^{1/3} = 0.06\times 17.10 = 1.03\ \text{m}

Adopt t≈1.1t \approx 1.1 m (pitching on the river side slope 2:1, over a 0.15 to 0.3 m graded filter).

3. Scour depth and launching apron

Lacey's normal scour depth:

R=0.47(Qf)1/3=0.47(50000.88)1/3=8.39 mR = 0.47\left(\frac{Q}{f}\right)^{1/3} = 0.47\left(\frac{5000}{0.88}\right)^{1/3} = 8.39\ \text{m}

Maximum scour below HFL: 2R2R at the upstream nose, 1.5R1.5R at the shank (straight portion). The apron must launch to the slope 2H:1V2H:1V, so its horizontal width is 1.5D′1.5D' and, when launched, it covers a slope length 5 D′\sqrt5\,D' with thickness 1.5t1.5t.

PortionScour factorScour depth below HFLDepth below bed D′D'Apron length 1.5D′1.5D'
Nose (u/s curved head)2.0R16.77 m12.77 m19.16 m
Shank (straight)1.5R12.58 m8.58 m12.87 m

Thickness: pitching t=1.03t = 1.03 m, so the launched apron thickness is 1.5t=1.5×1.03=1.541.5t = 1.5\times1.03 = 1.54 m. Equating volumes per metre, the thickness as laid over 1.5D′1.5D' width is T=1.5t×5D′1.5D′=5 t=2.29T = \dfrac{1.5t\times\sqrt5 D'}{1.5D'} = \sqrt5\,t = 2.29 m (about 2.25t2.25t).

Summary

ItemValue
Lacey waterway WW335.88 m (adopt 336 m)
Length of guide bund (u/s)420 m; d/s tail 84 m
Pitching thickness tt1.03 m
Apron at shank: width 1.5D′1.5D' / thickness12.87 m / 1.54 m launched (2.29 m laid)
Apron at nose: width / thickness19.16 m / 1.54 m launched (2.29 m laid)

Sketches

Plan of guide bunds:

 U/S                                          D/S
                       bridge / weir axis
   Shank (straight)                |
 ________________________________  |  ___
/  1.0-1.5 W upstream            \ | /   \  tail
\________________________________/=|=\___/  0.25 W
 curved head                       |
 R, sweep 120 deg    <-- waterway W -->
 ________________________________  |  ___
/                                \ | /   \
\________________________________/=|=\___/

Section at the shank (straight portion):

           top width 6 m
         ___________  <- HFL + 1.5 m
        /           \
 HFL ---/-------------\---  2:1 slopes
       / pitching t    \
 bed__/__ filter ______ \___
      \_ launching apron _/ (launches at 2:1)
  • 2070 Bhadra · 8 marks

The launching apron of a guide bank is laid in a width equal to 1.8 times the depth of scour below original bed. If a scour slope of 3:1 is to be maintained with thickness 1.5 t, find the thickness of apron before it gets launched. Draw neat sketch of designed structure.

Answer

A launching apron is laid flat at the toe of the pitching. When the bed scours, the stones slide down the scour slope and cover it. The thickness before launching follows from equality of the stone volume per metre run before and after launching.

Data

  • Scour depth below original bed =D= D (unknown, cancels out).
  • Laid width of apron =1.8D= 1.8D; scour slope 3H:1V3H:1V; launched thickness =1.5t= 1.5t (tt = thickness of pitching).

Calculation

Length of the scour slope: D2+(3D)2=10 D=3.162D\sqrt{D^2 + (3D)^2} = \sqrt{10}\,D = 3.162D.

Volume per metre after launching: V=1.5t×3.162D=4.743 tDV = 1.5t\times3.162D = 4.743\,tD.

Volume per metre before launching: V=T×1.8DV = T\times1.8D, where TT is the thickness as laid.

T×1.8D=1.5t×10 DT=1.5101.8 t=2.635 t\begin{aligned} T\times1.8D &= 1.5t\times\sqrt{10}\,D \\ T &= \frac{1.5\sqrt{10}}{1.8}\,t = 2.635\,t \end{aligned}

Answer: thickness of apron before launching T≈2.64 tT \approx 2.64\,t (that is, about 2.6 times the pitching thickness).

Sketch

 Before launching            After launching (3H:1V)
  pitching                     pitching
 ___\____ T                   ___\
      |<--1.8D-->|                 \  1.5t thick
 bed ____apron___| river bed        \ scour slope
                                     \__ depth D

For example, if t=1.0t = 1.0 m the laid thickness is 2.64 m.

  • 2066 Bhadra (old course) · 5+3 marks

Design the following components of a guide bund for a river discharge of 6000 m³/s and silt factor as 1.1. Take HFL = 150 m, Bed level = 145 m. (i) Length of guide bund (ii) Thickness of pitching (iii) Width of launching apron (iv) Depth of launching apron. Using the design data, draw the following: A) Plan of guide bank B) Section at shank and C) Section at u/s curved head.

Answer

Data and design basis

  • Silt factor given: f=1.10f = 1.10
  • Flood depth above bed: h=150−145=5.00h = 150 - 145 = 5.00 m
  • Design discharge for scour/apron: Q=6000Q = 6000 m³/s

1. Waterway and length of guide bund

Lacey's regime waterway: W=4.75Q=4.756000=367.93W = 4.75\sqrt{Q} = 4.75\sqrt{6000} = 367.93 m. Adopt W≈368W \approx 368 m. Length of guide bund (Garg): upstream shank =1.0=1.0 to 1.5 W1.5\,W, downstream tail =0.2=0.2 to 0.5 W0.5\,W. Adopt

Lus=1.25W=1.25×368=460 mLds=0.25W=92 m\begin{aligned} L_{us} &= 1.25W = 1.25\times 368 = 460\ \text{m} \\ L_{ds} &= 0.25W = 92\ \text{m} \end{aligned}

Curved heads: upstream radius Ru≈0.5W=184R_u \approx 0.5W = 184 m with sweep 120∘120^\circ to 145∘145^\circ (adopt 120∘120^\circ); downstream radius Rd≈0.25W=92R_d \approx 0.25W = 92 m with sweep about 45∘45^\circ. Arc length of upstream head =Ruθ=184×2.094=385= R_u\theta = 184\times 2.094 = 385 m, so total length on the upstream side ≈845\approx 845 m.

2. Thickness of stone pitching

t=0.06 Q1/3=0.06×60001/3=0.06×18.17=1.09 mt = 0.06\,Q^{1/3} = 0.06\times 6000^{1/3} = 0.06\times 18.17 = 1.09\ \text{m}

Adopt t≈1.1t \approx 1.1 m (pitching on the river side slope 2:1, over a 0.15 to 0.3 m graded filter).

3. Scour depth and launching apron

Lacey's normal scour depth:

R=0.47(Qf)1/3=0.47(60001.10)1/3=8.27 mR = 0.47\left(\frac{Q}{f}\right)^{1/3} = 0.47\left(\frac{6000}{1.10}\right)^{1/3} = 8.27\ \text{m}

Maximum scour below HFL: 2R2R at the upstream nose, 1.5R1.5R at the shank (straight portion). The apron must launch to the slope 2H:1V2H:1V, so its horizontal width is 1.5D′1.5D' and, when launched, it covers a slope length 5 D′\sqrt5\,D' with thickness 1.5t1.5t.

PortionScour factorScour depth below HFLDepth below bed D′D'Apron length 1.5D′1.5D'
Nose (u/s curved head)2.0R16.55 m11.55 m17.32 m
Shank (straight)1.5R12.41 m7.41 m11.12 m

Thickness: pitching t=1.09t = 1.09 m, so the launched apron thickness is 1.5t=1.5×1.09=1.641.5t = 1.5\times1.09 = 1.64 m. Equating volumes per metre, the thickness as laid over 1.5D′1.5D' width is T=1.5t×5D′1.5D′=5 t=2.44T = \dfrac{1.5t\times\sqrt5 D'}{1.5D'} = \sqrt5\,t = 2.44 m (about 2.25t2.25t).

Summary

ItemValue
Lacey waterway WW367.93 m (adopt 368 m)
Length of guide bund (u/s)460 m; d/s tail 92 m
Pitching thickness tt1.09 m
Apron at shank: width 1.5D′1.5D' / thickness11.12 m / 1.64 m launched (2.44 m laid)
Apron at nose: width / thickness17.32 m / 1.64 m launched (2.44 m laid)

Sketches

A) Plan of guide bank:

 U/S                                          D/S
                       bridge / weir axis
   Shank (straight)                |
 ________________________________  |  ___
/  1.0-1.5 W upstream            \ | /   \  tail
\________________________________/=|=\___/  0.25 W
 curved head                       |
 R, sweep 120 deg    <-- waterway W -->
 ________________________________  |  ___
/                                \ | /   \
\________________________________/=|=\___/

B) Section at the shank:

           top width 6 m
         ___________  <- HFL + 1.5 m
        /           \
 HFL ---/-------------\---  2:1 slopes
       / pitching t    \
 bed__/__ filter ______ \___
      \_ launching apron _/ (launches at 2:1)

C) Section at the u/s curved head:

 Section at u/s curved head (nose)
            ______  <- HFL + 1.5 m
           /      \   top 6 m, side 3:1 (flatter)
 HFL ----/---------\----
        / pitching t \
 bed ___/_____________\__
         \_ apron: 2.0R scour, 1.5D' wide _/
  • 2065 Shrawan (old course) · 6 marks

Design a guide bund for a flood discharge of 7000 cumecs, the high flood depth is 5 m and the silt factor is 1.1.

Answer

Data and design basis

  • Silt factor given: f=1.10f = 1.10
  • Flood depth: h=5.00h = 5.00 m
  • Design discharge for scour/apron: Q=7000Q = 7000 m³/s

1. Waterway and length of guide bund

Lacey's regime waterway: W=4.75Q=4.757000=397.41W = 4.75\sqrt{Q} = 4.75\sqrt{7000} = 397.41 m. Adopt W≈397W \approx 397 m. Length of guide bund (Garg): upstream shank =1.0=1.0 to 1.5 W1.5\,W, downstream tail =0.2=0.2 to 0.5 W0.5\,W. Adopt

Lus=1.25W=1.25×397=496 mLds=0.25W=99 m\begin{aligned} L_{us} &= 1.25W = 1.25\times 397 = 496\ \text{m} \\ L_{ds} &= 0.25W = 99\ \text{m} \end{aligned}

Curved heads: upstream radius Ru≈0.5W=198R_u \approx 0.5W = 198 m with sweep 120∘120^\circ to 145∘145^\circ (adopt 120∘120^\circ); downstream radius Rd≈0.25W=99R_d \approx 0.25W = 99 m with sweep about 45∘45^\circ. Arc length of upstream head =Ruθ=198×2.094=416= R_u\theta = 198\times 2.094 = 416 m, so total length on the upstream side ≈912\approx 912 m.

2. Thickness of stone pitching

t=0.06 Q1/3=0.06×70001/3=0.06×19.13=1.15 mt = 0.06\,Q^{1/3} = 0.06\times 7000^{1/3} = 0.06\times 19.13 = 1.15\ \text{m}

Adopt t≈1.2t \approx 1.2 m (pitching on the river side slope 2:1, over a 0.15 to 0.3 m graded filter).

3. Scour depth and launching apron

Lacey's normal scour depth:

R=0.47(Qf)1/3=0.47(70001.10)1/3=8.71 mR = 0.47\left(\frac{Q}{f}\right)^{1/3} = 0.47\left(\frac{7000}{1.10}\right)^{1/3} = 8.71\ \text{m}

Maximum scour below HFL: 2R2R at the upstream nose, 1.5R1.5R at the shank (straight portion). The apron must launch to the slope 2H:1V2H:1V, so its horizontal width is 1.5D′1.5D' and, when launched, it covers a slope length 5 D′\sqrt5\,D' with thickness 1.5t1.5t.

PortionScour factorScour depth below HFLDepth below bed D′D'Apron length 1.5D′1.5D'
Nose (u/s curved head)2.0R17.42 m12.42 m18.63 m
Shank (straight)1.5R13.06 m8.06 m12.10 m

Thickness: pitching t=1.15t = 1.15 m, so the launched apron thickness is 1.5t=1.5×1.15=1.721.5t = 1.5\times1.15 = 1.72 m. Equating volumes per metre, the thickness as laid over 1.5D′1.5D' width is T=1.5t×5D′1.5D′=5 t=2.57T = \dfrac{1.5t\times\sqrt5 D'}{1.5D'} = \sqrt5\,t = 2.57 m (about 2.25t2.25t).

Summary

ItemValue
Lacey waterway WW397.41 m (adopt 397 m)
Length of guide bund (u/s)496 m; d/s tail 99 m
Pitching thickness tt1.15 m
Apron at shank: width 1.5D′1.5D' / thickness12.10 m / 1.72 m launched (2.57 m laid)
Apron at nose: width / thickness18.63 m / 1.72 m launched (2.57 m laid)

Sketches

Plan of guide bunds:

 U/S                                          D/S
                       bridge / weir axis
   Shank (straight)                |
 ________________________________  |  ___
/  1.0-1.5 W upstream            \ | /   \  tail
\________________________________/=|=\___/  0.25 W
 curved head                       |
 R, sweep 120 deg    <-- waterway W -->
 ________________________________  |  ___
/                                \ | /   \
\________________________________/=|=\___/

Section at the shank (straight portion):

           top width 6 m
         ___________  <- HFL + 1.5 m
        /           \
 HFL ---/-------------\---  2:1 slopes
       / pitching t    \
 bed__/__ filter ______ \___
      \_ launching apron _/ (launches at 2:1)
  • 2068 Baisakh (old course) · 9 marks

Calculate the thickness of a 7 m long launching apron of loosed stones for a shank portion of guide bund at a bridge site of a river having design flood of 8000 m³/s and flood depth of 5 m. Assume that average diameter of river bed material at flood time is 0.3 mm.

Answer

A launching apron of loose stone is laid at the toe of the guide bund. When scour occurs it launches down a 2H:1V slope. The laid thickness is found by equating the stone volume before and after launching.

Data

Q=8000Q = 8000 m³/s, flood depth h=5h = 5 m, d=0.3d = 0.3 mm, laid width of apron =7= 7 m (shank portion).

Step 1. Silt factor and scour depth

f=1.76dmm=1.760.3=0.964R=0.47(Qf)1/3=0.47(80000.964)1/3=9.52 m\begin{aligned} f &= 1.76\sqrt{d_{mm}} = 1.76\sqrt{0.3} = 0.964 \\ R &= 0.47\left(\frac{Q}{f}\right)^{1/3} = 0.47\left(\frac{8000}{0.964}\right)^{1/3} = 9.52\ \text{m} \end{aligned}

Maximum scour at the shank: 1.5R=14.271.5R = 14.27 m below HFL. Scour below the bed: D′=1.5R−h=14.27−5=9.27D' = 1.5R - h = 14.27 - 5 = 9.27 m.

Step 2. Pitching and launched thickness

t=0.06 Q1/3=0.06×20.00=1.20 m,1.5t=1.80 mt = 0.06\,Q^{1/3} = 0.06\times20.00 = 1.20\ \text{m}, \qquad 1.5t = 1.80\ \text{m}

Step 3. Thickness of the 7 m apron before launching

Slope length of launched apron =5 D′=2.236×9.27=20.74= \sqrt5\,D' = 2.236\times9.27 = 20.74 m.

T×7=1.5t×5D′=1.80×20.74T=5.33 m\begin{aligned} T\times7 &= 1.5t\times\sqrt5 D' = 1.80\times20.74 \\ T &= 5.33\ \text{m} \end{aligned}

Answer: thickness of the 7 m wide apron as laid T=5.33T = 5.33 m (it launches to 1.80 m thick on the 2:1 slope). A 7 m apron is short against a required width of 1.5D′=13.911.5D' = 13.91 m, so a thick apron is needed; it may be better to widen it to 13.913.9 m, when T=2.68T = 2.68 m.

  pitching
  ___\__ T = 5.33 m
 bed __|<-- 7 m -->|___ river bed
   after launch: 2H:1V, 1.80 m thick, D' = 9.27 m
  • 2079 Chaitra · 10 marks

Design a spur for concave bank of the river if maximum flood discharge is 5,000 m³/sec, river bed level = 1000.00 masl, high flood level = 1010.00 masl, and Lacey's silt factor = 1.0. Design length spacing, total height and side slope of spur and launching apron for Bank, middle part and nose.

Answer

A spur on the concave bank deflects the current away from the eroding bank. It is designed from the regime width, the scour depth and the severity of the bend. The design uses Lacey and standard spur practice (Garg).

Data

Q=5000Q = 5000 m³/s, bed level 1000.00 m, HFL 1010.00 m (flood depth h=10h = 10 m), f=1.0f = 1.0.

Step 1. Regime width and scour depth

W=4.75Q=4.755000=335.9 mR=0.47(Qf)1/3=0.47×17.10=8.04 mt=0.06 Q1/3=1.03 m\begin{aligned} W &= 4.75\sqrt{Q} = 4.75\sqrt{5000} = 335.9\ \text{m} \\ R &= 0.47\left(\frac{Q}{f}\right)^{1/3} = 0.47\times17.10 = 8.04\ \text{m} \\ t &= 0.06\,Q^{1/3} = 1.03\ \text{m} \end{aligned}

Step 2. Length and spacing

  • Length of spur is limited to about 20 % of the regime width: Ls=0.2×336≈65L_s = 0.2\times336 \approx 65 m (measured from the bank line at HFL).
  • Spacing on a concave bank S=2S = 2 to 2.5 Ls2.5\,L_s; adopt S=2Ls=130S = 2L_s = 130 m.
  • Spurs are set pointing slightly upstream (about 100∘100^\circ to 110∘110^\circ with the bank), with a T-head or round head at the nose.

Step 3. Height and side slopes

  • Top level == HFL +1.0+ 1.0 m =1011.0= 1011.0 m (bank end); nose end is kept about 0.5 to 1.0 m lower, but not below HFL.
  • Total height at the root above bed =1011.0−1000.0=11.0= 1011.0 - 1000.0 = 11.0 m.
  • Top width 4 m (3 to 6 m).
  • Side slopes: 2:1 on the shank (middle) and bank part, 3:1 at the nose; stone pitching thickness t=1.03t = 1.03 m (adopt 1.1 m) on a 0.3 m filter.

Step 4. Launching apron at bank, middle and nose

Scour below HFL is taken as 1.5R at the bank (root), 1.75R in the middle and 2.25R at the nose. The apron slope is 2:1 and its width is 1.5D′1.5D'.

PartScour factorScour below HFL (m)D′D' below bed (m)Apron width 1.5D′1.5D' (m)Launched thickness 1.5t1.5t (m)
Bank (root)1.5R12.062.063.081.54
Middle1.75R14.064.066.101.54
Nose (head)2.25R18.088.0812.121.54

Thickness of apron laid ≈5 t=2.29\approx \sqrt5\,t = 2.29 m (launched thickness 1.5t=1.541.5t = 1.54 m).

Answer: Ls≈65L_s \approx 65 m, spacing ≈130\approx 130 m, total height 11 m, side slopes 2:1 (3:1 at the nose), apron widths 3.1 m (bank), 6.1 m (middle) and 12.1 m (nose).

 bank ====root====|========== shank ===========\ nose
 HFL+1 --------------------------------------    \
 HFL ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
 bed ____apron 3.1m___apron 6.1m_______apron 12.1m__

Questions from Old Question Collection (CE 654) (IOE exam papers from 2062 to 2079 (CE 654 and older Irrigation Engineering)) and Old Question Collection (CE 654) (IOE exam papers from 2071 to 2081). Answers are written for this site; check them against your class notes.

Chapter titles and hours from the IOE syllabus ↗