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Guide bund design, 4000 m3/s, d 0.1 mm

Short answer

Lacey waterway W=300m. Upstream shank 375m, downstream tail 75m, curved head radius 150m (120°). Pitching thickness 1.0m. Normal scour R=9.07m. Apron at shank: length 12.91m, launched thickness 1.43m (laid 2.13m). At nose: length 19.71m, same thickness.

Following hydraulic data near a proposed bridge site are obtained. Maximum discharge = 4000 m³/s; Highest flood level = 205.0 m; River bed level = 200.00 m; Average diameter of river bed material = 0.1 mm. Design the following components of a guide bund and neatly sketch it. (i) Length of guide bund (ii) Thickness of pitching of the slope (iii) Length of launching apron (iv) thickness of launching apron.

Data and design basis

  • Silt factor (Lacey): f=1.76dmm=1.760.1=0.557f = 1.76\sqrt{d_{mm}} = 1.76\sqrt{0.1} = 0.557
  • Flood depth above bed: h=205.0−200.0=5.00h = 205.0 - 200.0 = 5.00 m
  • Design discharge for scour/apron: Q=4000Q = 4000 m³/s

1. Waterway and length of guide bund

Lacey's regime waterway: W=4.75Q=4.754000=300.42W = 4.75\sqrt{Q} = 4.75\sqrt{4000} = 300.42 m. Adopt W≈300W \approx 300 m. Length of guide bund (Garg): upstream shank =1.0=1.0 to 1.5 W1.5\,W, downstream tail =0.2=0.2 to 0.5 W0.5\,W. Adopt

Lus=1.25W=1.25×300=375 mLds=0.25W=75 m\begin{aligned} L_{us} &= 1.25W = 1.25\times 300 = 375\ \text{m} \\ L_{ds} &= 0.25W = 75\ \text{m} \end{aligned}

Curved heads: upstream radius Ru≈0.5W=150R_u \approx 0.5W = 150 m with sweep 120∘120^\circ to 145∘145^\circ (adopt 120∘120^\circ); downstream radius Rd≈0.25W=75R_d \approx 0.25W = 75 m with sweep about 45∘45^\circ. Arc length of upstream head =Ruθ=150×2.094=314= R_u\theta = 150\times 2.094 = 314 m, so total length on the upstream side ≈689\approx 689 m.

2. Thickness of stone pitching

t=0.06 Q1/3=0.06×40001/3=0.06×15.87=0.95 mt = 0.06\,Q^{1/3} = 0.06\times 4000^{1/3} = 0.06\times 15.87 = 0.95\ \text{m}

Adopt t≈1.0t \approx 1.0 m (pitching on the river side slope 2:1, over a 0.15 to 0.3 m graded filter).

3. Scour depth and launching apron

Lacey's normal scour depth:

R=0.47(Qf)1/3=0.47(40000.557)1/3=9.07 mR = 0.47\left(\frac{Q}{f}\right)^{1/3} = 0.47\left(\frac{4000}{0.557}\right)^{1/3} = 9.07\ \text{m}

Maximum scour below HFL: 2R2R at the upstream nose, 1.5R1.5R at the shank (straight portion). The apron must launch to the slope 2H:1V2H:1V, so its horizontal width is 1.5D′1.5D' and, when launched, it covers a slope length 5 D′\sqrt5\,D' with thickness 1.5t1.5t.

PortionScour factorScour depth below HFLDepth below bed D′D'Apron length 1.5D′1.5D'
Nose (u/s curved head)2.0R18.14 m13.14 m19.71 m
Shank (straight)1.5R13.61 m8.61 m12.91 m

Thickness: pitching t=0.95t = 0.95 m, so the launched apron thickness is 1.5t=1.5×0.95=1.431.5t = 1.5\times0.95 = 1.43 m. Equating volumes per metre, the thickness as laid over 1.5D′1.5D' width is T=1.5t×5D′1.5D′=5 t=2.13T = \dfrac{1.5t\times\sqrt5 D'}{1.5D'} = \sqrt5\,t = 2.13 m (about 2.25t2.25t).

Summary

ItemValue
Lacey waterway WW300.42 m (adopt 300 m)
Length of guide bund (u/s)375 m; d/s tail 75 m
Pitching thickness tt0.95 m
Apron at shank: width 1.5D′1.5D' / thickness12.91 m / 1.43 m launched (2.13 m laid)
Apron at nose: width / thickness19.71 m / 1.43 m launched (2.13 m laid)

Sketches

Plan of guide bunds:

 U/S                                          D/S
                       bridge / weir axis
   Shank (straight)                |
 ________________________________  |  ___
/  1.0-1.5 W upstream            \ | /   \  tail
\________________________________/=|=\___/  0.25 W
 curved head                       |
 R, sweep 120 deg    <-- waterway W -->
 ________________________________  |  ___
/                                \ | /   \
\________________________________/=|=\___/

Section at the shank (straight portion):

           top width 6 m
         ___________  <- HFL + 1.5 m
        /           \
 HFL ---/-------------\---  2:1 slopes
       / pitching t    \
 bed__/__ filter ______ \___
      \_ launching apron _/ (launches at 2:1)

✓ Answer checked by Claude Opus 5.5 (high effort)

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