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Guide bank design, 4000 m3/s, d 0.40 mm

Short answer

Lacey waterway 300 m; upstream guide bund 375 m, downstream tail 75 m. Pitching thickness 0.95 m. Normal scour depth R=7.20 m. Nose apron width 17.10 m, shank apron 11.70 m; launched thickness 1.43 m, laid thickness 2.13 m.

Design a guide bank required for a bridge on a river having following particulars: maximum flood discharge = 4000 m³/s, HFL = 205 m, river bed level = 202 m, average diameter of river bed material = 0.40 mm.

Data and design basis

  • Silt factor (Lacey): f=1.76dmm=1.760.4=1.11f = 1.76\sqrt{d_{mm}} = 1.76\sqrt{0.4} = 1.11
  • Flood depth above bed: h=205−202=3.00h = 205 - 202 = 3.00 m
  • Design discharge for scour/apron: Q=4000Q = 4000 m³/s

1. Waterway and length of guide bund

Lacey's regime waterway: W=4.75Q=4.754000=300.42W = 4.75\sqrt{Q} = 4.75\sqrt{4000} = 300.42 m. Adopt W≈300W \approx 300 m. Length of guide bund (Garg): upstream shank =1.0=1.0 to 1.5 W1.5\,W, downstream tail =0.2=0.2 to 0.5 W0.5\,W. Adopt

Lus=1.25W=1.25×300=375 mLds=0.25W=75 m\begin{aligned} L_{us} &= 1.25W = 1.25\times 300 = 375\ \text{m} \\ L_{ds} &= 0.25W = 75\ \text{m} \end{aligned}

Curved heads: upstream radius Ru≈0.5W=150R_u \approx 0.5W = 150 m with sweep 120∘120^\circ to 145∘145^\circ (adopt 120∘120^\circ); downstream radius Rd≈0.25W=75R_d \approx 0.25W = 75 m with sweep about 45∘45^\circ. Arc length of upstream head =Ruθ=150×2.094=314= R_u\theta = 150\times 2.094 = 314 m, so total length on the upstream side ≈689\approx 689 m.

2. Thickness of stone pitching

t=0.06 Q1/3=0.06×40001/3=0.06×15.87=0.95 mt = 0.06\,Q^{1/3} = 0.06\times 4000^{1/3} = 0.06\times 15.87 = 0.95\ \text{m}

Adopt t≈1.0t \approx 1.0 m (pitching on the river side slope 2:1, over a 0.15 to 0.3 m graded filter).

3. Scour depth and launching apron

Lacey's normal scour depth:

R=0.47(Qf)1/3=0.47(40001.11)1/3=7.20 mR = 0.47\left(\frac{Q}{f}\right)^{1/3} = 0.47\left(\frac{4000}{1.11}\right)^{1/3} = 7.20\ \text{m}

Maximum scour below HFL: 2R2R at the upstream nose, 1.5R1.5R at the shank (straight portion). The apron must launch to the slope 2H:1V2H:1V, so its horizontal width is 1.5D′1.5D' and, when launched, it covers a slope length 5 D′\sqrt5\,D' with thickness 1.5t1.5t.

PortionScour factorScour depth below HFLDepth below bed D′D'Apron length 1.5D′1.5D'
Nose (u/s curved head)2.0R14.40 m11.40 m17.10 m
Shank (straight)1.5R10.80 m7.80 m11.70 m

Thickness: pitching t=0.95t = 0.95 m, so the launched apron thickness is 1.5t=1.5×0.95=1.431.5t = 1.5\times0.95 = 1.43 m. Equating volumes per metre, the thickness as laid over 1.5D′1.5D' width is T=1.5t×5D′1.5D′=5 t=2.13T = \dfrac{1.5t\times\sqrt5 D'}{1.5D'} = \sqrt5\,t = 2.13 m (about 2.25t2.25t).

Summary

ItemValue
Lacey waterway WW300.42 m (adopt 300 m)
Length of guide bund (u/s)375 m; d/s tail 75 m
Pitching thickness tt0.95 m
Apron at shank: width 1.5D′1.5D' / thickness11.70 m / 1.43 m launched (2.13 m laid)
Apron at nose: width / thickness17.10 m / 1.43 m launched (2.13 m laid)

Sketches

Plan of guide bunds:

 U/S                                          D/S
                       bridge / weir axis
   Shank (straight)                |
 ________________________________  |  ___
/  1.0-1.5 W upstream            \ | /   \  tail
\________________________________/=|=\___/  0.25 W
 curved head                       |
 R, sweep 120 deg    <-- waterway W -->
 ________________________________  |  ___
/                                \ | /   \
\________________________________/=|=\___/

Section at the shank (straight portion):

           top width 6 m
         ___________  <- HFL + 1.5 m
        /           \
 HFL ---/-------------\---  2:1 slopes
       / pitching t    \
 bed__/__ filter ______ \___
      \_ launching apron _/ (launches at 2:1)

✓ Answer checked by Claude Opus 5.5 (high effort)

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