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Guide bank design, 6500 m3/s

Short answer

Waterway 383 m; upstream guide bund 479 m, downstream tail 96 m. Pitching thickness 1.12 m. Scour depth R=8.77 m. Nose apron width 18.81 m, shank apron 12.24 m; launched thickness 1.68 m, laid thickness 2.50 m.

Design a guide bank for the weir site from the following data provided. Bed level of river = 105.00 m; Depth of water during high flood = 5 m; Discharge of river = 6500 m³/s. The value of Lacey's silt factor may be taken as 1.

Data and design basis

  • Bed level 105.00 m, flood depth 5 m, so HFL =110.00=110.00 m; top level of bank =111.50=111.50 m.
  • Silt factor given: f=1.00f = 1.00
  • Flood depth: h=5.00h = 5.00 m
  • Design discharge for scour/apron: Q=6500Q = 6500 m³/s

1. Waterway and length of guide bund

Lacey's regime waterway: W=4.75Q=4.756500=382.96W = 4.75\sqrt{Q} = 4.75\sqrt{6500} = 382.96 m. Adopt W≈383W \approx 383 m. Length of guide bund (Garg): upstream shank =1.0=1.0 to 1.5 W1.5\,W, downstream tail =0.2=0.2 to 0.5 W0.5\,W. Adopt

Lus=1.25W=1.25×383=479 mLds=0.25W=96 m\begin{aligned} L_{us} &= 1.25W = 1.25\times 383 = 479\ \text{m} \\ L_{ds} &= 0.25W = 96\ \text{m} \end{aligned}

Curved heads: upstream radius Ru≈0.5W=192R_u \approx 0.5W = 192 m with sweep 120∘120^\circ to 145∘145^\circ (adopt 120∘120^\circ); downstream radius Rd≈0.25W=96R_d \approx 0.25W = 96 m with sweep about 45∘45^\circ. Arc length of upstream head =Ruθ=192×2.094=401= R_u\theta = 192\times 2.094 = 401 m, so total length on the upstream side ≈880\approx 880 m.

2. Thickness of stone pitching

t=0.06 Q1/3=0.06×65001/3=0.06×18.66=1.12 mt = 0.06\,Q^{1/3} = 0.06\times 6500^{1/3} = 0.06\times 18.66 = 1.12\ \text{m}

Adopt t≈1.2t \approx 1.2 m (pitching on the river side slope 2:1, over a 0.15 to 0.3 m graded filter).

3. Scour depth and launching apron

Lacey's normal scour depth:

R=0.47(Qf)1/3=0.47(65001.00)1/3=8.77 mR = 0.47\left(\frac{Q}{f}\right)^{1/3} = 0.47\left(\frac{6500}{1.00}\right)^{1/3} = 8.77\ \text{m}

Maximum scour below HFL: 2R2R at the upstream nose, 1.5R1.5R at the shank (straight portion). The apron must launch to the slope 2H:1V2H:1V, so its horizontal width is 1.5D′1.5D' and, when launched, it covers a slope length 5 D′\sqrt5\,D' with thickness 1.5t1.5t.

PortionScour factorScour depth below HFLDepth below bed D′D'Apron length 1.5D′1.5D'
Nose (u/s curved head)2.0R17.54 m12.54 m18.81 m
Shank (straight)1.5R13.16 m8.16 m12.24 m

Thickness: pitching t=1.12t = 1.12 m, so the launched apron thickness is 1.5t=1.5×1.12=1.681.5t = 1.5\times1.12 = 1.68 m. Equating volumes per metre, the thickness as laid over 1.5D′1.5D' width is T=1.5t×5D′1.5D′=5 t=2.50T = \dfrac{1.5t\times\sqrt5 D'}{1.5D'} = \sqrt5\,t = 2.50 m (about 2.25t2.25t).

Summary

ItemValue
Lacey waterway WW382.96 m (adopt 383 m)
Length of guide bund (u/s)479 m; d/s tail 96 m
Pitching thickness tt1.12 m
Apron at shank: width 1.5D′1.5D' / thickness12.24 m / 1.68 m launched (2.50 m laid)
Apron at nose: width / thickness18.81 m / 1.68 m launched (2.50 m laid)

Sketches

Plan of guide bunds:

 U/S                                          D/S
                       bridge / weir axis
   Shank (straight)                |
 ________________________________  |  ___
/  1.0-1.5 W upstream            \ | /   \  tail
\________________________________/=|=\___/  0.25 W
 curved head                       |
 R, sweep 120 deg    <-- waterway W -->
 ________________________________  |  ___
/                                \ | /   \
\________________________________/=|=\___/

Section at the shank (straight portion):

           top width 6 m
         ___________  <- HFL + 1.5 m
        /           \
 HFL ---/-------------\---  2:1 slopes
       / pitching t    \
 bed__/__ filter ______ \___
      \_ launching apron _/ (launches at 2:1)

✓ Answer checked by Claude Opus 5.5 (high effort)

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