- 2072 Chaitra · 8 marks
180° three-phase inverter and fundamental phase voltage
Short answer
In 180° conduction, each switch conducts for half a cycle, producing a six-step phase voltage with levels ±Vdc/3 and ±2Vdc/3. The fundamental component per phase is obtained by Fourier analysis: peak value = 2Vdc/π, rms = √2 Vdc/π.
Explain the operation of a three phase inverter for 180 degree conduction with neat circuit diagram and waveforms. How the fundamental component of output (per phase) voltage can be calculated?
In 180° conduction each switch of the six-switch bridge conducts for half a cycle, three switches are ON at a time (one per leg), and firing is in the order S1 to S6 at 60° intervals. With a star resistive load this gives a six-step phase voltage.
Circuit
+-----+--------+--------+
| | | |
| S1 D1 S3 D3 S5 D5
Vdc | | |
| +--a +--b +--c
| | | |
| S4 D4 S6 D6 S2 D2
| | | |
+-----+--------+--------+
a, b, c -> star load (R per phase)
Operation
| Mode | ON switches | ||||
|---|---|---|---|---|---|
| 1 | 0–60° | S5, S6, S1 | |||
| 2 | 60–120° | S6, S1, S2 | |||
| 3 | 120–180° | S1, S2, S3 | |||
| 4 | 180–240° | S2, S3, S4 | |||
| 5 | 240–300° | S3, S4, S5 | |||
| 6 | 300–360° | S4, S5, S6 |
In mode 1, a and c are on the positive bus and b on the negative bus: total resistance , so and . Other modes follow similarly.
van 2V/3 ___
V/3 __| |__
0 ----------+----------- wt
-V/3 |__ __
-2V/3 |___|
vab V _______
0 |___ ___
-V |_____|
0 60 120 180 240 300 360
Line voltage : for 0–120°, 0 for 120–180°, for 180–300°, 0 for 300–360°.
Fundamental component of phase voltage
Method 1 — Fourier analysis of the six-step wave (odd, half-wave symmetric):
Method 2 — from the line voltage: the 120° quasi-square has fundamental peak ; dividing by gives the same phase value.
Full series: (triplen harmonics absent). Total rms phase voltage . Example: V gives a fundamental of 381.97 V peak (270.09 V rms).
✓ Answer checked by Claude Opus 5.5 (high effort)
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