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Isochronous generator transient response

Short answer

An isochronous generator uses an integral governor (zero droop) to maintain constant frequency. Following a step load increase, speed drops, integral action increases prime mover power, and speed exactly recovers with zero steady-state frequency error.

What do you mean by Isochronous generator? Describe its transient response for a step increase in load.

An isochronous generator is a generating unit whose governor is isochronous (integral type, zero droop). It keeps the speed and frequency exactly at the set value for any load within its rating. It is used for a single unit supplying an isolated load, or for one unit that controls frequency in a small system.

Governor law: ΔY(s)=−Ks ΔΩ(s)\Delta Y(s) = -\dfrac{K}{s}\,\Delta\Omega(s), so the gate keeps moving as long as there is any speed error.

Transient response to a step increase in load

 power
 P0+dPL     .________________ Pe
            |      __.-- Pm -> Pe
            |   _.'
 P0   ______|__/  (Pm)
          t = 0
 speed
 w0   ______.            .---- w0 (restored)
             \         .'
              '.____.-'
          t = 0                 time
  1. At t=0t = 0 the electrical output PeP_e jumps by ΔPL\Delta P_L; PmP_m is unchanged, so the rotor decelerates and speed falls (slope −ΔPL/2H-\Delta P_L/2H).
  2. The integral governor opens the gate; PmP_m rises (a hydro turbine first dips a little).
  3. When Pm>PeP_m > P_e the rotor speeds up again. Because the integrator acts until the error is zero, the speed returns exactly to ω0\omega_0.
  4. Final state: Δω=0\Delta\omega = 0 and ΔPm=ΔPe=ΔPL\Delta P_m = \Delta P_e = \Delta P_L. Frequency error is zero, unlike a droop governor which leaves Δωss=−ΔPL/(D+1/R)\Delta\omega_{ss} = -\Delta P_L/(D + 1/R).

✓ Answer checked by Claude Opus 5.5 (high effort)

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