Why is no lane distribution factor (0.5) applied to the 5.11 x 10^4 ESAL per year?

Because it is a single-lane road, so all traffic uses the design lane

Because the traffic is already in the design lane

Because ESAL is already halved for single lanes

Because the construction period is one year

Which calculation gives the design ESAL of 0.914 x 10^6?

54166 x [(1.06)^12 - 1]/0.06 with 54166 = 51100 x 1.06

SN_base/a1 = 0.79/0.397 gives 51 mm. What does the answer provide and why?

55 mm, as the thickness must be at least the computed and at least 50 mm minimum, rounded to practical size

50 mm exactly, as the minimum governs

2070 Chaitra (old course) · 8 marks

Asphalt Institute design: 5.11×10⁴ ESAL/year, 12 years

Short answer

Subgrade Mr = 10×CBR = 40 MPa. Design ESAL = 51100×1.06×[(1.06^12-1)/0.06] = 0.914×10^6. Asphalt concrete 55 mm, emulsified stabilised base 120 mm, granular sub-base 250 mm (total 425 mm).

An existing single lane road has to be upgraded by bituminous pavement for a certain length by the following considerations: i) Base traffic of 80 kN equivalent single axle load (ESAL) = 5.11×10⁴ ESAL per year ii) Design period = 12 years iii) Construction period = 1 year iv) Traffic growth rate = 6% v) 87.5th percentile CBR value of sub-grade soil from 7 sample locations = 4% vi) Elastic modulus of asphalt concrete for surface course, Eac = 2900 MPa vii) Elastic modulus of emulsified stabilized base, Eb = 1600 MPa viii) Elastic modulus of granular sub-base, Esb = 125 MPa You are required to design the pavement from Asphalt Institute Method. Draw the cross section of final pavement layers considering the thickness of asphalt concrete on surface course is not less than 50 mm. (Full depth AC curve attached herewith)

Given data and assumptions

Single-lane road; base traffic 5.11 x 10^4 (51 100) ESAL (80 kN) per year, design period 12 years, construction period 1 year, growth 6 %.
87.5th percentile subgrade CBR = 4 %; moduli: asphalt concrete 2900 MPa, emulsified stabilised base 1600 MPa, granular sub-base 125 MPa.
Single lane: all traffic is in the design lane (factor 1.0). Minimum asphalt concrete 50 mm.
Method: Asphalt Institute (AI) thickness design as taught for IOE (and used in the Nepal DoR Pavement Design Guidelines); design reliability 90 percent, terminal serviceability 2.5.

Step 1 - Subgrade strength

The design (87.5th percentile) CBR of the subgrade is given as 4 %.

Resilient modulus of subgrade: $M_R = 10\times CBR = 10\times 4.0 = 40$ MPa.

Step 2 - Design traffic (ESAL)

ESAL at opening $=51\,100\times(1.06)^1=54166$ per year.

ESAL=54166\times\frac{(1.06)^{12}-1}{0.06}=54166\times16.870=0.914\times10^6

Design ESAL = 0.914 $\times 10^6$

Step 3 - Thickness required over each layer

The AI charts give the thickness of asphalt concrete (full depth) needed to protect a layer of a given modulus for the design ESAL. The same requirement is expressed here as a structural number $SN$ (AASHTO-93 relation with R = 90 percent, $S_0$ = 0.45, $\Delta PSI$ = 1.7), which closely approximates the AI chart readings (if the chart is supplied in the exam, read the thickness from it and use the same layer-coefficient steps below).

Protected layer	Modulus (MPa)	Required SN	Full-depth AC equivalent at $a_1=0.44$ (mm)
emulsified stabilised base	1600	0.79	46
granular sub-base	125	2.44	141
Subgrade	40	3.77	218

Step 4 - Layer coefficients

Using $a_1=0.323\log_{10}E-1.42$ , $a_2=0.249\log_{10}E-0.977$ , $a_3=0.227\log_{10}E-0.839$ with $E$ in psi:

Asphalt concrete (2900 MPa): $a_1 = 0.397$
emulsified stabilised base (1600 MPa): $a_2 = 0.359$
granular sub-base (125 MPa): $a_3 = 0.128$

Step 5 - Layer thicknesses

Asphalt concrete: $D_1 \ge SN_{base}/a_1 = 0.79/0.397=51$ mm, so provide 55 mm (minimum 50 mm). $SN_1 = 0.86$ .
Emulsified stabilised base: $D_2 \ge (SN_{sub}-SN_1)/a_2 = (2.44-0.86)/0.359 = 112$ mm, so provide 120 mm. $SN_2 = 1.70$ .
Granular sub-base: $D_3 \ge (SN_{sg}-SN_1-SN_2)/a_3 = (3.77-0.86-1.70)/0.128 = 242$ mm, so provide 250 mm. $SN_3 = 1.26$ .

Check: provided $SN = 0.86+1.70+1.26 = 3.81 \ge 3.77$ (required) - safe.

Answer: asphalt concrete 55 mm, emulsified stabilised base 120 mm, granular sub-base 250 mm; total pavement thickness = 425 mm.

   +-------------------------------------+
   | Asphalt concrete              55 mm |
   +-------------------------------------+
   | Emulsified stabilised base   120 mm |
   +-------------------------------------+
   | Granular sub-base            250 mm |
   +-------------------------------------+
   | Subgrade, CBR 4.0 %                 |
   +-------------------------------------+

✓ Answer checked by Claude Opus 5.5 (high effort)

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