- 2068 Bhadra (old course) · 8 marks
Mid-line reactor for Vr = Vs at no load
Short answer
For a lossless line, the required reactor at midpoint is XL = (Zc/2) cot(βl/2). With Zc=316.23 Ω and βl=28.46°, XL = 623.5 Ω per phase (≈257 MVAr at 400 kV).
A 400 kV, 500 km, 50 Hz HV transmission line has r = 0.031 Ω/km, l = 1 mH/km and C = 10 nF/km. Calculate the value of XL of a reactor required at the middle of the line as shown in figure below so that the receiving end voltage at no load could be controlled as Vr = Vs. [Figure: line from Vs to Vr with a single shunt reactor jXL connected from the midpoint of the line to ground]
Treat the line as lossless for the reactor calculation (as usual; has a negligible effect, checked below). Split it into two equal halves, each with electrical length , with the reactor at the midpoint.
Line constants:
Without the reactor: pu.
Derivation
Second half (midpoint M to the open receiving end, ):
At M: the current leaving the first half feeds the reactor and the second half:
First half:
Condition
Check: ✓. Including /km, the same reactor gives , so neglecting is justified.
Reactor rating (3-phase, 400 kV): MVAr.
Vs o------ 250 km ------+------ 250 km ------o Vr
|
jXL = 623.5 ohm
|
------------------------+--------------------- gnd
Answer: 623.5 Ω per phase (about 257 MVAr) at the midpoint.
✓ Answer checked by Claude Opus 5.5 (high effort)
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