- 2068 Bhadra (old course) · 20 marks
Bending moment ratio, 132 kV vs 220 kV towers
Short answer
With DEER conductor, 300 m span, and appropriate tower geometries, base bending moment is 44,903 kg·m for 132 kV and 53,833 kg·m for 220 kV. The ratio (132/220 kV) is 0.834.
Compute the ratio of bending moment acting on transmission tower of a 132 kV and 220 kV single circuit transmission lines of span 300 m with DEER conductor. Use data from Appendix and assume any suitable data if necessary. [The appendix is not reproduced with this paper.]
The bending moment at the tower base is the sum of each transverse load times its height. Both lines use the same conductor and span, so they have the same sag and the same wind load per wire. The ratio therefore comes from the tower geometry: ground clearance, conductor spacing and earth wire height, all of which grow with voltage.
Data and assumptions
| Item | Value |
|---|---|
| DEER (ACSR 30/7/4.27 mm) | d = 29.89 mm, A = 529.8 mm², w = 1.9714 kg/m, UTS = 179 kN = 18,253 kg |
| E, α (30/7 ACSR) | kg/cm², /°C |
| Toughest condition | 0°C, wind 100 kg/m², no ice, |
| Easiest condition | 60°C, no wind |
| Earth wire | 7/3.66 mm GS wire, d = 10.98 mm, one per tower |
| Air clearance | 6.5 inch per 10 kV (phase rms of max voltage) + 8 inch |
| Insulator string | 254 × 146 mm discs (9 for 132 kV, 14 for 220 kV) + 0.3 m hardware |
| String swing | 45°; tower width at cross arm 1.5 m |
| Ground clearance | ft |
| Towers | Suspension (straight-line); wind span = 300 m |
| Conductors | Three levels, one conductor per level |
Step 1 – maximum sag (same for both lines)
Solving gives kg. Then
Step 2 – clearances and tower geometry
| Quantity | Formula | 132 kV | 220 kV |
|---|---|---|---|
| Max phase voltage | 83.72 kV | 141.45 kV | |
| Air clearance a | in | 1.585 m | 2.539 m |
| String length l | 1.614 m | 2.344 m | |
| Vertical spacing Y | 3.199 m | 4.883 m | |
| Cross arm X | 2.727 m | 4.196 m | |
| Earth wire height above top conductor | 6.022 m | 8.567 m | |
| Ground clearance | ft | 20 ft = 6.096 m | 22.67 ft = 6.909 m |
Conductor heights at the tower:
| Height | 132 kV (m) | 220 kV (m) |
|---|---|---|
| 10.666 | 11.479 | |
| 13.865 | 16.361 | |
| 17.064 | 21.244 | |
| 23.086 | 29.810 |
Step 3 – transverse loads (wind span 300 m)
Step 4 – bending moment at the base
Step 5 – ratio
220 kV 132 kV
E 29.8 m E 23.1 m
| |
--* 21.2 m --* 17.1 m
*-- 16.4 m *-- 13.9 m
--* 11.5 m --* 10.7 m
===== ground ===== ground
Answer: the bending moment is about 44.9 t·m for the 132 kV tower and 53.8 t·m for the 220 kV tower, a ratio of M(132) : M(220) ≈ 0.83 : 1. The loads per wire are the same, so the 220 kV tower carries about 20% more moment only because it is taller, through larger clearances and spacing.
✓ Answer checked by Claude Opus 5.5 (high effort)
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