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Conductor selection, 100 MW 70 km 132 kV

Short answer

The line requires a minimum 486 A thermal rating, ≥94% efficiency, and ≤12% regulation. ACSR Goat meets thermal limit but fails regulation; Sheep and Bison are marginal. ACSR Deer (30/4.27+7/4.27 mm) satisfies all criteria with 643 A rating, 96.08% efficiency, and 11.65% regulation.

For 3 phase 50 Hz transmission line to deliver 100 MW of power over 70 km, 132 kV single circuit line has been decided to design. Suggest the suitable conductor which meets following technical criterion. (i) Satisfy the thermal limit. (ii) Efficiency of line not to be less than 94% (iii) Voltage regulation of line not to be greater than 12%. Use conductor table attached. Assume the ambient temperature and maximum allowable temperature same as mentioned in conductor table.

[Given ACSR conductor table:]

Code nameAluminium No./mmSteel No./mmApprox. overall diameter (mm)Aluminium area (mm²)Steel area (mm²)Total area (mm²)Approx. weight (kg/km)Nominal breaking load (kN)Nominal DC resistance at 20°C (Ω/km)Current rating (A)
Mole6/1.501/1.504.5010.61.7712.442.84.142.702766
Squirrel6/2.111/2.116.3321.03.5024.584.77.871.3659101
Fox6/2.791/2.798.3736.76.1142.8148.113.210.7812142
Mink6/3.661/3.6610.9863.110.5073.6254.921.870.4540199
Skunk12/2.597/2.5912.9563.236.90100.1463.052.790.4568206
Beaver6/3.991/3.9911.9775.012.5087.5302.925.760.3820221
Racoon6/4.091/4.0912.2778.813.1091.9318.327.060.3635228
Otter6/4.221/4.2212.6683.914.0097.9338.828.810.3415237
Cat6/4.501/4.5013.5095.415.90111.3385.332.760.3003256
Hare6/4.721/4.7214.16105.017.50122.5423.836.040.2730271
Coyote26/2.547/1.9115.89131.720.10151.8520.745.880.2192311
Cougar18/3.051/3.0515.25131.57.31138.8418.829.740.2188308
Tiger30/2.367/2.3616.52131.230.60161.8602.257.870.2202313
Lion30/3.187/3.1822.26238.355.60293.91093.4100.470.1213450
Bear30/3.357/3.3523.45264.461.70326.11213.4111.500.1093480
Goat30/3.717/3.7125.97324.375.70400.01488.2135.130.0891543
Sheep30/3.997/3.9927.93375.187.50462.61721.3156.300.0771592
Antelope54/2.977/2.9726.73374.148.50422.61413.8118.880.0773586
Bison54/3.007/3.0027.00381.749.50431.21442.5121.300.0758593
Deer30/4.277/4.2729.89429.6100.20529.81971.4179.000.0673643
Elk30/4.507/4.5031.50477.1111.30588.42189.5198.800.0606684
Camel54/3.357/3.3530.15476.061.70537.71798.8146.400.0608677
Moose54/3.537/3.5331.77528.569.50597.01997.3159.920.0547720

Note: current ratings are based on wind velocity of 0.6 m/s, solar heat radiation of 1200 W/m², ambient temperature of 50°C and conductor temperature of 80°C.

The conductor must pass three checks: the thermal limit, efficiency ≥ 94% and regulation ≤ 12%. The smallest standard ACSR that passes all three is chosen.

Assumptions (not given in the question):

  • Power factor 0.9 lagging.
  • Equivalent spacing Deq=5.0D_{eq} = 5.0 m, typical for a 132 kV single-circuit tower.
  • Resistance at 80 °C: R80=R20[1+0.004(80−20)]=1.24R20R_{80} = R_{20}[1 + 0.004(80 - 20)] = 1.24R_{20}.
  • GMR =0.7788r= 0.7788r.
  • 70 km is treated as a medium line using the nominal-π model.
  • Ambient 50 °C and conductor 80 °C, as in the table, so the tabulated current rating is used directly.

(i) Thermal limit

I=P3Vcos⁡ϕ=100×1063×132×103×0.9=486.0 AI = \frac{P}{\sqrt{3}V\cos\phi} = \frac{100\times10^6}{\sqrt{3}\times132\times10^3\times0.9} = 486.0\ \text{A}

The rating must be at least 486 A. Bear (480 A) and smaller conductors are rejected. Goat (543 A) is the smallest conductor that passes.

Line constants (per km)

X=2πf(2×10−7ln⁡D0.7788r)×1000 Ω/kmB=2πf 2πε0ln⁡(D/r)×1000 S/km\begin{aligned} X &= 2\pi f\left(2\times10^{-7}\ln\frac{D}{0.7788r}\right)\times1000\ \Omega/\text{km} \\ B &= 2\pi f\,\frac{2\pi\varepsilon_0}{\ln(D/r)}\times1000\ \text{S/km} \end{aligned}

For Deer (d=29.89d = 29.89 mm, r=1.4945r = 1.4945 cm):

  • R80=0.0673×1.24=0.0835 ΩR_{80} = 0.0673 \times 1.24 = 0.0835\ \Omega/km
  • X=0.3809 ΩX = 0.3809\ \Omega/km
  • B=3.007 μB = 3.007\ \muS/km

(ii) and (iii) Efficiency and regulation

For each conductor:

  • Z=(R+jX)×70Z = (R + jX)\times70, Y=jB×70Y = jB\times70, A=1+ZY/2A = 1 + ZY/2
  • VS=AVR+ZIRV_S = AV_R + ZI_R, IS=CVR+AIRI_S = CV_R + AI_R, with VR=132/3V_R = 132/\sqrt{3} kV
  • η=PR/PS\eta = P_R/P_S and VR=(VS/∣A∣−VR)/VRVR = (V_S/|A| - V_R)/V_R
ConductorIratedI_{rated} (A)Thermal OK?R80R_{80} (Ω/km)XX (Ω/km)η (%)VR (%)
Bear480No0.13550.396293.7813.98
Goat543Yes0.11050.389894.8712.88
Sheep592Yes0.09560.385295.5312.21
Bison593Yes0.09400.387395.6012.20
Deer643Yes0.08350.380996.0811.65

For Deer: VS=146.96V_S = 146.96 kV (line), loss = 4.081 MW, so η=100/(100+4.081)=96.08%\eta = 100/(100 + 4.081) = 96.08\% and VR=11.65%VR = 11.65\%.

Selection

  • Goat passes the thermal and efficiency checks but fails regulation (12.88% > 12%).
  • Sheep and Bison are marginal, at about 12.2%.
  • Deer passes all three: rating 643 A > 486 A, η = 96.08% > 94%, VR = 11.65% < 12%.

Answer: ACSR Deer (30/4.27 + 7/4.27 mm) is the suitable conductor.

If a smaller spacing (about 4 m) is used, Sheep and Bison would just meet the 12% limit (VR about 11.9%), and they could be compared with Deer on cost.

✓ Answer checked by Claude Opus 5.5 (high effort)

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