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T/F: peak demand as sum of class peaks

Short answer

FALSE. Different classes peak at different times; the coincident peak is the sum of class peaks multiplied by their contribution factors (≤1), which is less than the arithmetic sum.

State whether the following statement is TRUE or FALSE. Justify your answer with a brief explanation: The peak demand of a load centre is the sum of the peak demand of different consumer classes.

FALSE.

The peak demand of a load centre is the coincident (simultaneous) maximum of the combined load, not the arithmetic sum of the class peaks.

Justification:

  • Different consumer classes reach their maximum demand at different hours. Domestic load peaks in the evening (lighting, cooking), commercial load around midday/afternoon, and offices, schools and institutions during working hours.
  • At the hour of the load centre peak, each class draws only a fraction of its own peak. This fraction is the contribution (responsibility) factor cic_i.
  • Therefore
PLC=∑ci Pclass,i≤∑Pclass,iP_{LC} = \sum c_i \, P_{class,i} \le \sum P_{class,i}

Example: domestic peak 20 kW (evening, c=1c = 1), commercial peak 6 kW (c=0.5c = 0.5 in the evening), institutional peak 4 kW (c=0.1c = 0.1):

PLC=20+3+0.4=23.4 kW, not 30 kWP_{LC} = 20 + 3 + 0.4 = 23.4 \text{ kW, not } 30 \text{ kW}

Adding the class peaks directly would oversize the distribution transformer and feeders, raising capital cost and no-load losses. The plain sum is correct only if all classes peak at the same time (all contribution factors equal to 1), which rarely happens.

✓ Answer checked by Claude Opus 5.5 (high effort)

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