Skip to main content

TTL voltage profile and noise margin; Gray code

Short answer

TTL voltage profile: VOH(min)=2.4V, VOL(max)=0.4V; VIH(min)=2.0V, VIL(max)=0.8V; noise margins NMH=NML=0.4V. Gray code is a unit-distance code where successive numbers differ in only one bit, avoiding false intermediate codes; used in shaft encoders and K-maps.

Draw the general input output voltage profile for TTL gates and also mention the noise margin. What do you mean by Gray code?

Input–output voltage profile of TTL

The profile shows the voltage ranges for logic 0 and 1 at the output of a driving gate and at the input of a receiving gate (VCC=5V_{CC} = 5 V):

  Output (driving)       Input (receiving)
 5.0 +--------+         5.0 +--------+
     | HIGH   |             | HIGH   |
 2.4 +--------+ VOH(min) 2.0 +--------+ VIH(min)
     |invalid |  NM_H=0.4   | indet. |
 0.4 +--------+ VOL(max) 0.8 +--------+ VIL(max)
     | LOW    |  NM_L=0.4   | LOW    |
 0.0 +--------+         0.0 +--------+
ParameterValue
VOH(min)V_{OH(min)}2.4 V
VOL(max)V_{OL(max)}0.4 V
VIH(min)V_{IH(min)}2.0 V
VIL(max)V_{IL(max)}0.8 V

Inputs between 0.8 V and 2.0 V are not allowed (indeterminate).

Noise margin

Noise margin is the largest noise voltage that can be added to a valid output without the next input reading a wrong level:

NMH=VOH(min)−VIH(min)=2.4−2.0=0.4 VNML=VIL(max)−VOL(max)=0.8−0.4=0.4 V\begin{aligned} NM_H &= V_{OH(min)} - V_{IH(min)} = 2.4 - 2.0 = 0.4\ \text{V} \\ NM_L &= V_{IL(max)} - V_{OL(max)} = 0.8 - 0.4 = 0.4\ \text{V} \end{aligned}

So standard TTL has a noise margin of 0.4 V in both states.

Gray code

Gray code is an unweighted, unit-distance (reflected binary) code: successive numbers differ in only one bit. This avoids false intermediate codes when several bits change together, so it is used in shaft encoders, K-map ordering and error reduction. Binary to Gray: Gn=BnG_{n} = B_{n} (MSB), Gi=Bi+1⊕BiG_i = B_{i+1} \oplus B_i.

DecimalBinaryGray
0000000
1001001
2010011
3011010
4100110
5101111
6110101
7111100

✓ Answer checked by Claude Opus 5.5 (high effort)

All Digital Logic chapter 10 questions →