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Effect of excitation on armature current and pf
Short answer
With constant load, varying DC excitation changes Eb. Under-excitation (Eb<V) yields lagging pf and high current; normal excitation (Eb≈V) gives unity pf and minimum current; over-excitation (Eb>V) yields leading pf and increased current. Armature current follows V-curves; pf follows inverted V-curves.
Explain the variation of armature current and power factor for different values of excitation current (normal excitation, under-excitation and over-excitation) in a synchronous motor with suitable figures and phasor diagrams.
In a synchronous motor with constant load (constant power ), varying the DC field current changes the back emf . Since and are fixed, stays constant, so the tip of the current phasor moves along a line perpendicular to , while also stays constant.
(a) Normal excitation
- Field current gives such that the current is in phase with : unity pf.
- Armature current is minimum for that load.
(b) Under-excitation
- is smaller; the resultant voltage swings so that the current lags .
- Armature current is larger than at normal excitation; the motor draws lagging reactive power (magnetising current) from the supply.
(c) Over-excitation
- is larger; the current leads .
- Armature current again increases; the motor supplies reactive power to the supply (synchronous condenser action).
Phasors at constant load (V reference, Rs = 0)
I3 (lead, over-excited)
\
\ I1 (upf, normal)
O----+------> V I tip moves on the
/ vertical line I cos(phi)
/ = constant
I2 (lag, under-excited)
V-curves and inverted V-curves
Ia pf
| \ / full load | _
| \ / | / \ (inverted V)
| \ \ / / | / \
| \_\_/_/ no load | / \
+------------> If +--------------> If
lag | upf | lead lag upf lead
- V-curves: vs at constant load, shaped like a "V". The minimum point of each curve is at unity pf. The left side (under-excited) is lagging, the right side (over-excited) is leading. Higher load gives a higher curve.
- Inverted V-curves: pf vs ; the peak is unity pf. The locus of minimum points (unity pf) shifts to the right as load increases, since more excitation is needed at higher load.
| Excitation | pf | Armature current |
|---|---|---|
| Under | Lagging | High |
| Normal | Unity | Minimum |
| Over | Leading | High |
This property lets an over-excited synchronous motor drive its load and also correct the plant power factor.
✓ Answer checked by Claude Sonnet 5.5
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