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Design discharge 2030, Surkhet village

Short answer

Design population 2019 after 15 years at 2%. Net demand 137501 l/d; adding 15% losses gives 158126 l/d = 158.13 m3/d = 1.83 l/s. Design discharge: max day 2.75 l/s, peak hour 5.49 l/s.

Calculate the design discharge for design year 2030 for a village in Surkhet District. The data collected in survey year 2015 is as below:

Survey year population = 1500; Population growth rate = 2.0% per year; Number of buffalos = 345; Number of cows = 450; Number of goats = 800; Number of chickens = 2000; Number of boarder students = 64; Number of day scholar students = 450; Number of offices = 3.

Survey year 2015, design year 2030, so n=15n = 15 years.

Design population

P2030=1500×(1.02)15=2,019P_{2030} = 1500\times(1.02)^{15} = 2{,}019

Water demand

Design values assumed (Nepal rural water supply practice): domestic 45 lpcd (public taps); day scholar 5 l/d; boarder 45 l/d; office staff 45 l/d with 10 staff per office; big animal (cow, buffalo) 45 l/d; small animal (goat, pig) 5 l/d; poultry 0.2 l/d; health post 1000 l/d; tea shop 500 l/d; losses and wastage 15% of net demand; maximum day factor 1.5 and peak hour factor 3.

DemandQuantityRateDemand (l/day)
Domestic (45 lpcd)2,01945 l/c/d90,846
Boarders6445 l/c/d2,880
Day scholars4505 l/c/d2,250
Buffaloes + cows79545 l/d35,775
Goats8005 l/d4,000
Chickens2,0000.2 l/d400
Offices (10 staff each)3045 l/staff1,350
Net demand137,501

Losses and wastage =15%= 15\% of net demand =20,625= 20{,}625 l/day

Qavg=137,501+20,625=158,126 l/day=158.13 m3/day=1.83 l/sQ_{avg} = 137{,}501 + 20{,}625 = 158{,}126\ \text{l/day} = 158.13\ \mathrm{m^3/day} = 1.83\ \text{l/s}

Design discharge

  • Maximum day demand =1.5×1.83=2.75= 1.5\times1.83 = 2.75 l/s (source, intake and transmission main).
  • Peak hour demand =3×1.83=5.49= 3\times1.83 = 5.49 l/s (distribution).

Answer: Design discharge (maximum day) = 2.75 l/s; average demand = 1.83 l/s (158.1 m3^3/day); peak hour = 5.49 l/s.

✓ Answer checked by Claude Opus 5.5 (high effort)

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