- 2072 Asoj · 4 marks
Substation capacity and diversity factor from load pattern
Short answer
Combined loads per 4-hour interval: max total = 73 kVA (second 12-16 interval). Substation capacity = 73 kVA (practically 100 kVA standard). Individual max demands: A=22, B=34, C=40 kVA; sum=96 kVA. Diversity factor = 96/73 = 1.315. Substation sized for simultaneous peak, not sum of individual peaks.
The load pattern of ABC complex is:
| Time | (0:00-4:00) | (4:00-8:00) | (8:00-12:00) | (12:00-16:00) | (12:00-16:00) | (16:00-20:00) | (20:00-24:00) |
|---|---|---|---|---|---|---|---|
| Load of Block-A in KVA | 5 | 13 | 18 | 9 | 16 | 22 | 8 |
| Load of Block-B in KVA | 7 | 19 | 22 | 34 | 17 | 14 | 6 |
| Load of Block-C in KVA | 3 | 12 | 16 | 24 | 40 | 35 | 4 |
Calculate: i) Capacity of substation required. ii) Diversity factor. (The fifth column is printed as (12:00-16:00) a second time in the paper.)
The fifth column repeats "(12:00–16:00)"; it is taken as a separate 4-hour interval as printed, giving 7 intervals of data.
Step 1: Combined load in each interval
| Interval | A | B | C | Total (kVA) |
|---|---|---|---|---|
| 0–4 | 5 | 7 | 3 | 15 |
| 4–8 | 13 | 19 | 12 | 44 |
| 8–12 | 18 | 22 | 16 | 56 |
| 12–16 | 9 | 34 | 24 | 67 |
| 12–16 (2nd) | 16 | 17 | 40 | 73 |
| 16–20 | 22 | 14 | 35 | 71 |
| 20–24 | 8 | 6 | 4 | 18 |
Step 2: Capacity of substation
The substation must supply the highest combined (simultaneous) load:
Max demand of complex = 73 kVA
Answer (i): Required substation capacity = 73 kVA (in practice the next standard transformer, 100 kVA, would be installed).
Step 3: Diversity factor
Individual maximum demands:
Block A max = 22 kVA
Block B max = 34 kVA
Block C max = 40 kVA
Sum = 96 kVA
Diversity factor
= Σ individual MDs / Max demand of system
= 96 / 73
= 1.315
Answer (ii): Diversity factor = 1.32.
Because the blocks reach their peaks at different times, the substation needs only 73 kVA instead of 96 kVA.
✓ Answer checked by Claude Opus 5.5 (high effort)
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