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Short column 300x500, 2000 kN, M30

Short answer

Column is short. Provide 16-20 mm longitudinal bars (Asc 5027 mm2, 3.35%) and 8 mm ties at 300 mm c/c; biaxial interaction check is safe for M30 concrete and Fe500 steel.

Determine the longitudinal and transverse reinforcements in a short rectangular column subjected to a factored axial load of 2000 kN and factored moment MuxM_{ux} about major axis of 190 kN-m and MuyM_{uy} about minor axis of 95 kN-m. The size of the column is 300 mm x 500 mm and the unsupported length of 3 m. Adopt M30 concrete and Fe 500 grade steel.

Data and assumptions

  • Column 300 mm (width bb) × 500 mm (depth DD); Pu=2000P_u = 2000 kN; fck=30f_{ck} = 30 MPa, fy=500f_y = 500 MPa. Clear cover 40 mm (IS 456 cl. 26.4.2.1), 8 mm ties.
  • Moments: about major axis (x-x) MuxM_{ux} = 190 kN·m; about minor axis (y-y) MuyM_{uy} = 95 kN·m.
  • Sizes are given as b×Db \times D with D≥bD \ge b; moments MuxM_{ux} act about the major axis (depth DD) and MuyM_{uy} about the minor axis (depth bb).

Slenderness

Axislel_e (mm)Dimension (mm)le/l_e/dimType
x-x (about major)30005006.00short
y-y (about minor)300030010.00short

Both ratios are below 12, so the column is short; no additional moment is required.

Minimum eccentricity (cl. 25.4)

emin=max⁡(L500+D30, 20)e_{min} = \max\left(\frac{L}{500} + \frac{D}{30},\ 20\right)
  • About x-x: ex=3000/500+500/30=22.7e_x = 3000/500 + 500/30 = 22.7 mm (min. 20 mm); adopt 22.7 mm; Mux,min=Pue=45.3M_{ux,min} = P_u e = 45.3 kN·m
  • About y-y: ey=3000/500+300/30=16.0e_y = 3000/500 + 300/30 = 16.0 mm (min. 20 mm); adopt 20.0 mm; Muy,min=40.0M_{uy,min} = 40.0 kN·m

Design moments

  • Design moments: Mux=190.0M_{ux} = 190.0 kN·m, Muy=95.0M_{uy} = 95.0 kN·m (not less than the minimum-eccentricity values).

Longitudinal reinforcement

PufckbD=200000030×300×500=0.444\dfrac{P_u}{f_{ck} b D} = \dfrac{2000000}{30 \times 300 \times 500} = 0.444 Bars are chosen so that pp lies between 0.8% (minimum) and 4% (practical maximum; IS 456 cl. 26.5.3.1 allows 6%). The uniaxial capacities Mux1M_{ux1}, Muy1M_{uy1} at PuP_u are read from the SP-16 interaction charts for rectangular sections; here they are computed by strain compatibility with the IS 456 stress block and the design stress-strain curve of steel (same basis as the charts), with effective cover d′=40+8+ϕ/2d' = 40 + 8 + \phi/2.

Trialpp (%)d′/Dd'/DMux1M_{ux1}Muy1M_{uy1}Pu/PuzP_u/P_{uz}αn\alpha_n(Mux/Mux1)αn+(Muy/Muy1)αn(M_{ux}/M_{ux1})^{\alpha_n}+(M_{uy}/M_{uy1})^{\alpha_n}
14-20 φ2.930.116258.7138.30.5531.591.163 ✗
10-25 φ3.270.121282.5151.30.5261.541.029 ✗
16-20 φ3.350.116299.9148.70.5211.530.999 ✓

Check

Puz=0.45fckAc+0.75fyAsc=0.45×30×144973+0.75×500×5027=3842P_{uz} = 0.45 f_{ck} A_c + 0.75 f_y A_{sc} = 0.45 \times 30 \times 144973 + 0.75 \times 500 \times 5027 = 3842 kN PuPuz=20003842=0.521\dfrac{P_u}{P_{uz}} = \dfrac{2000}{3842} = 0.521, so αn=1.53\alpha_n = 1.53 (IS 456 cl. 39.6; linear between 1.0 at 0.2 and 2.0 at 0.8).

(MuxMux1)αn+(MuyMuy1)αn=(190.0299.9)1.53+(95.0148.7)1.53=0.999≤1.0\left(\frac{M_{ux}}{M_{ux1}}\right)^{\alpha_n} + \left(\frac{M_{uy}}{M_{uy1}}\right)^{\alpha_n} = \left(\frac{190.0}{299.9}\right)^{1.53} + \left(\frac{95.0}{148.7}\right)^{1.53} = 0.999 \le 1.0

The interaction condition is satisfied; the section is safe.

Provide 16-20 mm bars (Asc=5027A_{sc} = 5027 mm², p=3.35%p = 3.35\%), within 0.8% to 4%.

Lateral ties

  • Diameter ≥max⁡(ϕmax/4, 6)=max⁡(20/4,6)=6\ge \max(\phi_{max}/4,\ 6) = \max(20/4, 6) = 6 mm → provide 8 mm.
  • Pitch ≤min⁡\le \min(least lateral dimension, 16ϕmin16\phi_{min}, 300 mm) =min⁡(300,320,300)=300= \min(300, 320, 300) = 300 mm → provide 8 mm ties @ 300 mm c/c.

Detailing

CROSS-SECTION 300 x 500
    +-------------------------+
    |    o   o   o   o   o    |
    |                         |
    |                         |
    |    o               o    |
    |                         |
    |    o               o    |
    |                         |
    |    o               o    |
    |                         |
    |                         |
    |    o   o   o   o   o    |
    +-------------------------+
   o = 20 mm bars, ties 8 mm @ 300 c/c

Answer: 300 × 500 mm column with 16-20 mm longitudinal bars (p=3.35%p = 3.35\%) and 8 mm ties @ 300 mm c/c.

✓ Answer checked by Claude Opus 5.5 (high effort)

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