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Column 350x350, 1440 kN, ductile detailing

Short answer

The 350x350 mm section is inadequate; enlarge to 450x450 mm. Provide 12-25 mm bars (Asc=5890 mm2, p=2.91%), 8 mm ties at 220 mm c/c outside the confining zone, with special confining reinforcement as per IS 13920.

Determine the longitudinal and transverse reinforcement of RC column subjected to a factored axial load of 1440 kN and factored moment MuxM_{ux} about major axis of 195 kNm and MuyM_{uy} about minor axis 180 kNm. The size of column is 350 mm x 350 mm and unsupported length of 3.60 m. Adopt M20 concrete and Fe500 grade (TMT) steel. Also do the ductile detailing of transversal reinforcement.

Check of the given section 350 × 350 mm

Even with the largest practical steel (for example 14-25 mm bars, p=5.6%p = 5.6\%), the interaction ratio is 1.77 > 1 for Pu=1440P_u = 1440 kN with the given moments. The given section is therefore too small, and the column must be enlarged.

Data and assumptions

  • The section given in the question (350 × 350 mm) is checked first and found inadequate (see above), so a revised section 450 × 450 mm is designed.
  • Column 450 mm (width bb) × 450 mm (depth DD); Pu=1440P_u = 1440 kN; fck=20f_{ck} = 20 MPa, fy=500f_y = 500 MPa. Clear cover 40 mm (IS 456 cl. 26.4.2.1), 8 mm ties.
  • Moments: about major axis (x-x) MuxM_{ux} = 195 kN·m; about minor axis (y-y) MuyM_{uy} = 180 kN·m.
  • Effective length is taken equal to the unsupported length, 3.6 m.

Slenderness

Axislel_e (mm)Dimension (mm)le/l_e/dimType
x-x (about major)36004508.00short
y-y (about minor)36004508.00short
Both ratios are below 12, so the column is short; no additional moment is required.

Minimum eccentricity (cl. 25.4)

emin=max⁡(L500+D30, 20)e_{min} = \max\left(\frac{L}{500} + \frac{D}{30},\ 20\right)
  • About x-x: ex=3600/500+450/30=22.2e_x = 3600/500 + 450/30 = 22.2 mm (min. 20 mm); adopt 22.2 mm; Mux,min=Pue=32.0M_{ux,min} = P_u e = 32.0 kN·m
  • About y-y: ey=3600/500+450/30=22.2e_y = 3600/500 + 450/30 = 22.2 mm (min. 20 mm); adopt 22.2 mm; Muy,min=32.0M_{uy,min} = 32.0 kN·m

Design moments

  • Design moments: Mux=195.0M_{ux} = 195.0 kN·m, Muy=180.0M_{uy} = 180.0 kN·m (not less than the minimum-eccentricity values).

Longitudinal reinforcement

PufckbD=144000020×450×450=0.356\dfrac{P_u}{f_{ck} b D} = \dfrac{1440000}{20 \times 450 \times 450} = 0.356 Bars are chosen so that pp lies between 0.8% (minimum) and 4% (practical maximum; IS 456 cl. 26.5.3.1 allows 6%). The uniaxial capacities Mux1M_{ux1}, Muy1M_{uy1} at PuP_u are read from the SP-16 interaction charts for rectangular sections; here they are computed by strain compatibility with the IS 456 stress block and the design stress-strain curve of steel (same basis as the charts), with effective cover d′=40+8+ϕ/2d' = 40 + 8 + \phi/2.

Trialpp (%)d′/Dd'/DMux1M_{ux1}Muy1M_{uy1}Pu/PuzP_u/P_{uz}αn\alpha_n(Mux/Mux1)αn+(Muy/Muy1)αn(M_{ux}/M_{ux1})^{\alpha_n}+(M_{uy}/M_{uy1})^{\alpha_n}
10-25 φ2.420.134271.5304.00.3981.331.142 ✗
16-20 φ2.480.129292.7292.70.3931.321.110 ✗
12-25 φ2.910.134330.6330.60.3621.270.974 ✓

Check

Puz=0.45fckAc+0.75fyAsc=0.45×20×196610+0.75×500×5890=3978P_{uz} = 0.45 f_{ck} A_c + 0.75 f_y A_{sc} = 0.45 \times 20 \times 196610 + 0.75 \times 500 \times 5890 = 3978 kN PuPuz=14403978=0.362\dfrac{P_u}{P_{uz}} = \dfrac{1440}{3978} = 0.362, so αn=1.27\alpha_n = 1.27 (IS 456 cl. 39.6; linear between 1.0 at 0.2 and 2.0 at 0.8).

(MuxMux1)αn+(MuyMuy1)αn=(195.0330.6)1.27+(180.0330.6)1.27=0.974≤1.0\left(\frac{M_{ux}}{M_{ux1}}\right)^{\alpha_n} + \left(\frac{M_{uy}}{M_{uy1}}\right)^{\alpha_n} = \left(\frac{195.0}{330.6}\right)^{1.27} + \left(\frac{180.0}{330.6}\right)^{1.27} = 0.974 \le 1.0

The interaction condition is satisfied; the section is safe.

Provide 12-25 mm bars (Asc=5890A_{sc} = 5890 mm², p=2.91%p = 2.91\%), within 0.8% to 4%.

Lateral ties

  • Diameter ≥max⁡(ϕmax/4, 6)=max⁡(25/4,6)=6\ge \max(\phi_{max}/4,\ 6) = \max(25/4, 6) = 6 mm → provide 8 mm.
  • Pitch by IS 456 ≤min⁡\le \min(least lateral dimension, 16ϕmin16\phi_{min}, 300 mm) =min⁡(450,400,300)=300= \min(450, 400, 300) = 300 mm. For ductile detailing, IS 13920 limits the spacing outside the confining zone to half the least lateral dimension = 225 mm → provide 8 mm ties @ 220 mm c/c outside lol_o.

Ductile detailing of transverse steel (IS 13920)

  • Special confining length at each end: lo≥max⁡(D, L/6, 450)=max⁡(450,600,450)=600l_o \ge \max(D,\ L/6,\ 450) = \max(450, 600, 450) = 600 mm → provide 600 mm from each joint face.
  • Spacing of hoops within lol_o: ≤min⁡(b/4, 6ϕL, 100)=min⁡(112,150,100)=100\le \min(b/4,\ 6\phi_L,\ 100) = \min(112, 150, 100) = 100 mm, and not less than 75 mm → 100 mm c/c.
  • The bars are about 110 mm apart (more than 75 mm), so the two intermediate bars on each face are held by cross-ties: a rectangular hoop plus 2 cross-ties in each direction.
  • Area of one hoop leg: Ash≥0.18 s h fckfy(AgAk−1)A_{sh} \ge 0.18\, s\, h\, \dfrac{f_{ck}}{f_y}\left(\dfrac{A_g}{A_k} - 1\right), where hh is the longer c/c distance between adjacent hoop legs or cross-ties (not more than 300 mm), here h≈135h \approx 135 mm; Ak=370×370=136900A_k = 370 \times 370 = 136900 mm² (core measured to the outside of the hoop); Ag=202500A_g = 202500 mm². Ash=0.18×100×135×20500×(202500136900−1)=46.6A_{sh} = 0.18 \times 100 \times 135 \times \dfrac{20}{500} \times \left(\dfrac{202500}{136900} - 1\right) = 46.6 mm²
  • An 8 mm leg gives 50.3 mm² >> 46.6 mm², so 8 mm hoops and cross-ties @ 100 mm c/c are adequate. Hoops have 135° hooks with a 6φ (≥ 65 mm) extension.
  • Outside lol_o: 8 mm ties @ 220 mm c/c (≤b/2=225\le b/2 = 225 mm).

Detailing

CROSS-SECTION 450 x 450
    +-------------------------+
    |                         |
    |  o      o     o      o  |
    |                         |
    |                         |
    |  o                   o  |
    |                         |
    |  o                   o  |
    |                         |
    |                         |
    |  o      o     o      o  |
    |                         |
    +-------------------------+
   o = 25 mm bars; hoop + 2 cross-ties each way
   8 mm @ 100 c/c over 600 mm at each end,
   8 mm @ 220 c/c in the middle region

Answer: 450 × 450 mm column with 12-25 mm longitudinal bars (p=2.91%p = 2.91\%); 8 mm hoops with cross-ties @ 100 mm c/c over 600 mm at each end, and 8 mm ties @ 220 mm c/c in the middle region.

✓ Answer checked by Claude Opus 5.5 (high effort)

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