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Short column 300x400, 1400 kN

Short answer

The 300x400 section is inadequate; revise to 400x500. Use 14-20 mm bars (p=2.20%) and 8 mm ties @200 mm c/c outside the confining zone; provide special confining hoops @75 mm c/c over 500 mm at each end.

Determine the longitudinal and transverse reinforcements in a short RC column subjected to factored axial load of 1400 kN and factored moment MuxM_{ux} of 200 kN-m and MuyM_{uy} of 110 kNm. The size of the column is 300 mm x 400 mm and unsupported length of 3 m. Adopt M20 concrete and Fe500 grade (TMT) bars. Also, do the ductile detailing of transverse reinforcements.

Check of the given section 300 × 400 mm

Even with the largest practical steel (for example 14-25 mm bars, p=5.7%p = 5.7\%), the interaction ratio is 1.34 > 1 for Pu=1400P_u = 1400 kN with the given moments. The given section is therefore too small, and the column must be enlarged.

Data and assumptions

  • The section given in the question (300 × 400 mm) is checked first and found inadequate (see above), so a revised section 400 × 500 mm is designed.
  • Column 400 mm (width bb) × 500 mm (depth DD); Pu=1400P_u = 1400 kN; fck=20f_{ck} = 20 MPa, fy=500f_y = 500 MPa. Clear cover 40 mm (IS 456 cl. 26.4.2.1), 8 mm ties.
  • Moments: about major axis (x-x) MuxM_{ux} = 200 kN·m; about minor axis (y-y) MuyM_{uy} = 110 kN·m.
  • Effective length is taken equal to the unsupported length, 3 m.

Slenderness

Axislel_e (mm)Dimension (mm)le/l_e/dimType
x-x (about major)30005006.00short
y-y (about minor)30004007.50short
Both ratios are below 12, so the column is short; no additional moment is required.

Minimum eccentricity (cl. 25.4)

emin=max⁡(L500+D30, 20)e_{min} = \max\left(\frac{L}{500} + \frac{D}{30},\ 20\right)
  • About x-x: ex=3000/500+500/30=22.7e_x = 3000/500 + 500/30 = 22.7 mm (min. 20 mm); adopt 22.7 mm; Mux,min=Pue=31.7M_{ux,min} = P_u e = 31.7 kN·m
  • About y-y: ey=3000/500+400/30=19.3e_y = 3000/500 + 400/30 = 19.3 mm (min. 20 mm); adopt 20.0 mm; Muy,min=28.0M_{uy,min} = 28.0 kN·m

Design moments

  • Design moments: Mux=200.0M_{ux} = 200.0 kN·m, Muy=110.0M_{uy} = 110.0 kN·m (not less than the minimum-eccentricity values).

Longitudinal reinforcement

PufckbD=140000020×400×500=0.350\dfrac{P_u}{f_{ck} b D} = \dfrac{1400000}{20 \times 400 \times 500} = 0.350 Bars are chosen so that pp lies between 0.8% (minimum) and 4% (practical maximum; IS 456 cl. 26.5.3.1 allows 6%). The uniaxial capacities Mux1M_{ux1}, Muy1M_{uy1} at PuP_u are read from the SP-16 interaction charts for rectangular sections; here they are computed by strain compatibility with the IS 456 stress block and the design stress-strain curve of steel (same basis as the charts), with effective cover d′=40+8+ϕ/2d' = 40 + 8 + \phi/2.

Trialpp (%)d′/Dd'/DMux1M_{ux1}Muy1M_{uy1}Pu/PuzP_u/P_{uz}αn\alpha_n(Mux/Mux1)αn+(Muy/Muy1)αn(M_{ux}/M_{ux1})^{\alpha_n}+(M_{uy}/M_{uy1})^{\alpha_n}
8-25 φ1.960.121283.1210.20.4321.391.025 ✗
20-16 φ2.010.112283.5212.00.4281.381.022 ✗
14-20 φ2.200.116292.9234.00.4111.350.958 ✓

Check

Puz=0.45fckAc+0.75fyAsc=0.45×20×195602+0.75×500×4398=3410P_{uz} = 0.45 f_{ck} A_c + 0.75 f_y A_{sc} = 0.45 \times 20 \times 195602 + 0.75 \times 500 \times 4398 = 3410 kN PuPuz=14003410=0.411\dfrac{P_u}{P_{uz}} = \dfrac{1400}{3410} = 0.411, so αn=1.35\alpha_n = 1.35 (IS 456 cl. 39.6; linear between 1.0 at 0.2 and 2.0 at 0.8).

(MuxMux1)αn+(MuyMuy1)αn=(200.0292.9)1.35+(110.0234.0)1.35=0.958≤1.0\left(\frac{M_{ux}}{M_{ux1}}\right)^{\alpha_n} + \left(\frac{M_{uy}}{M_{uy1}}\right)^{\alpha_n} = \left(\frac{200.0}{292.9}\right)^{1.35} + \left(\frac{110.0}{234.0}\right)^{1.35} = 0.958 \le 1.0

The interaction condition is satisfied; the section is safe.

Provide 14-20 mm bars (Asc=4398A_{sc} = 4398 mm², p=2.20%p = 2.20\%), within 0.8% to 4%.

Lateral ties

  • Diameter ≥max⁡(ϕmax/4, 6)=max⁡(20/4,6)=6\ge \max(\phi_{max}/4,\ 6) = \max(20/4, 6) = 6 mm → provide 8 mm.
  • Pitch by IS 456 ≤min⁡\le \min(least lateral dimension, 16ϕmin16\phi_{min}, 300 mm) =min⁡(400,320,300)=300= \min(400, 320, 300) = 300 mm. For ductile detailing, IS 13920 limits the spacing outside the confining zone to half the least lateral dimension = 200 mm → provide 8 mm ties @ 200 mm c/c outside lol_o.

Ductile detailing of transverse steel (IS 13920)

  • Special confining length at each end: lo≥max⁡(D, L/6, 450)=max⁡(500,500,450)=500l_o \ge \max(D,\ L/6,\ 450) = \max(500, 500, 450) = 500 mm → provide 500 mm from each joint face.
  • Spacing of hoops within lol_o: ≤min⁡(b/4, 6ϕL, 100)=min⁡(100,120,100)=100\le \min(b/4,\ 6\phi_L,\ 100) = \min(100, 120, 100) = 100 mm, and not less than 75 mm → 100 mm c/c.
  • The bars are about 95 mm apart (more than 75 mm), so the intermediate bars are held by cross-ties in addition to the rectangular hoop.
  • Area of one hoop leg: Ash≥0.18 s h fckfy(AgAk−1)A_{sh} \ge 0.18\, s\, h\, \dfrac{f_{ck}}{f_y}\left(\dfrac{A_g}{A_k} - 1\right), where hh is the longer c/c distance between adjacent hoop legs or cross-ties (not more than 300 mm), here h≈120h \approx 120 mm; Ak=320×420=134400A_k = 320 \times 420 = 134400 mm² (core measured to the outside of the hoop); Ag=200000A_g = 200000 mm². Ash=0.18×100×120×20500×(200000134400−1)=42.2A_{sh} = 0.18 \times 100 \times 120 \times \dfrac{20}{500} \times \left(\dfrac{200000}{134400} - 1\right) = 42.2 mm²
  • An 8 mm leg gives 50.3 mm² >> 42.2 mm², so 8 mm hoops and cross-ties @ 100 mm c/c are adequate. Hoops have 135° hooks with a 6φ (≥ 65 mm) extension.
  • Outside lol_o: 8 mm ties @ 200 mm c/c (≤b/2=200\le b/2 = 200 mm).

Detailing

CROSS-SECTION 400 x 500
    +-------------------------+
    |   o     o     o     o   |
    |                         |
    |                         |
    |   o                 o   |
    |                         |
    |   o                 o   |
    |                         |
    |   o                 o   |
    |                         |
    |                         |
    |   o     o     o     o   |
    +-------------------------+
   o = 20 mm bars; hoop + cross-ties
   8 mm @ 100 c/c over 500 mm at each end,
   8 mm @ 200 c/c in the middle region

Answer: 400 × 500 mm column with 14-20 mm longitudinal bars (p=2.20%p = 2.20\%); 8 mm hoops with cross-ties @ 100 mm c/c over 500 mm at each end, and 8 mm ties @ 200 mm c/c in the middle region.

✓ Answer checked by Claude Opus 5.5 (high effort)

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