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Materials: 100 m² plaster 1:6, 100 m³ PCC 1:2:4

Short answer

For 100 m2 12 mm plaster (1:6), wet mortar 1.2 m3, dry 1.524 m3: cement 6.27 bags, sand 1.31 m3. For 100 m3 PCC (1:2:4), dry volume 154 m3: cement 633.6 bags, sand 44 m3, aggregate 88 m3.

Calculate the quantities of material required for following works. i) 100 m² cement sand plaster 12 mm thick in (1:6) ii) 100 m³ P.C.C. (1:2:4).

Assumptions: dry volume 1.27 × wet for mortar and 1.54 × wet for concrete; 1 m³ cement = 28.8 bags; no wastage.

(i) 100 m² of 12 mm plaster (1:6)

  • Wet mortar =100.0×0.0120=1.2000= 100.0 \times 0.0120 = 1.2000 m³; dry volume =1.27×1.2000=1.5240= 1.27 \times 1.2000 = 1.5240 m³
  • Cement =1/7×1.5240=0.2177= 1/7 \times 1.5240 = 0.2177 m³ =6.27= 6.27 bags
  • Sand =6/7×1.5240=1.3063= 6/7 \times 1.5240 = 1.3063 m³

(ii) 100 m³ of PCC (1:2:4)

  • Wet volume =100.000= 100.000 m³; dry volume =1.54×100.000=154.000= 1.54 \times 100.000 = 154.000 m³ (sum of ratio =7= 7)
  • Cement =1/7×154.000=22.000= 1/7 \times 154.000 = 22.000 m³ =22.000×28.8=633.6= 22.000 \times 28.8 = 633.6 bags (50 kg)
  • Sand =2/7×154.000=44.000= 2/7 \times 154.000 = 44.000 m³
  • Coarse aggregate =4/7×154.000=88.000= 4/7 \times 154.000 = 88.000 m³

Answer: (i) cement 6.3 bags, sand 1.31 m³. (ii) cement 633.6 bags, sand 44.00 m³, aggregate 88.00 m³.

✓ Answer checked by Claude Opus 5.5 (high effort)

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