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Underground RCC tank: brickwork 1:4, M20 PCC, steel

Short answer

Brickwork in two steps by centre-line method:3.199 m³. M20 concrete for floor and lining wall totals1.446 m³. Steel at1% gives113.5 kg.

Drawing of an Underground RCC water tank is given below (Fig. 1). Prepare detailed estimate for the following items of works: i) Brickwork (1:4) ii) PCC for M20 RCC work iii) Steel reinforcement for M20 RCC work (assuming 1% steel) [Figure 1: plan 3000 mm × 2300 mm outside; brick wall 230 mm thick at top stepping to 380 mm at base with 150 mm offset; clear inside 1990 mm × 1290 mm; M20 RCC walls/floor 125 mm; 125 mm thick M25 RCC slab at top; section: 800 mm and 475 mm wall heights, overall 1450 mm, clear height 1150 mm; brickwork (1:4); PCC (1:3:6) base with flat brick soling. All dimensions in mm.]

Reading of Fig. 1

  • Outside size at base 3.00×2.303.00 \times 2.30 m; clear inside 1.99×1.291.99 \times 1.29 m. Wall at the base is 0.380.38 m of brick plus 0.1250.125 m of M20 RCC, so 1.99+2×(0.38+0.125)=3.001.99 + 2 \times (0.38 + 0.125) = 3.00 m and 1.29+2×0.505=2.301.29 + 2 \times 0.505 = 2.30 m (check).
  • Brick wall: 0.380.38 m thick for the lower 0.4750.475 m, stepping in by 0.150.15 m on the outer face to 0.230.23 m for the upper 0.800.80 m (total brick height 1.2751.275 m = clear height 1.151.15 m + floor 0.1250.125 m).
  • Inside the brick: 125 mm M20 RCC lining wall, 1.151.15 m high, and 125 mm M20 RCC floor. Top slab 125 mm M25 RCC (not part of the M20 quantity).

i) Brickwork (1:4), centre-line method

PartCentre-line length (m)Thickness (m)Height (m)Volume (m³)
Lower2 [(3.00−0.38)+(2.30−0.38)]=9.082\,[(3.00-0.38)+(2.30-0.38)] = 9.080.380.4751.639
Upper2 [(3.00−0.53)+(2.30−0.53)]=8.482\,[(3.00-0.53)+(2.30-0.53)] = 8.480.230.8001.560
Total3.199

The upper wall's outer face is set in by 0.150.15 m on each side, so its centre-line rectangle is (3.00−0.30−0.23)×(2.30−0.30−0.23)=2.47×1.77(3.00 - 0.30 - 0.23) \times (2.30 - 0.30 - 0.23) = 2.47 \times 1.77 m.

ii) Concrete for M20 RCC work

MemberWorkingVolume (m³)
Floor(1.99+0.25)(1.29+0.25)×0.125(1.99 + 0.25)(1.29 + 0.25) \times 0.1250.431
Lining wall2 [(1.99+0.125)+(1.29+0.125)]×0.125×1.15=7.06×0.125×1.152\,[(1.99+0.125)+(1.29+0.125)] \times 0.125 \times 1.15 = 7.06 \times 0.125 \times 1.151.015
Total M201.446

(For information, the M25 top slab is 2.70×2.00×0.125=0.6752.70 \times 2.00 \times 0.125 = 0.675 m³.)

iii) Steel in M20 RCC (1%)

W=0.01×1.446×7850=113.5W = 0.01 \times 1.446 \times 7850 = 113.5 kg

Answer: brickwork (1:4) = 3.199 m³; M20 concrete = 1.446 m³; steel = 113.5 kg.

✓ Answer checked by Claude Opus 5.5 (high effort)

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